Question Number 113154 by I want to learn more last updated on 11/Sep/20 $$\mathrm{If}\:\:\:\:\:\:\lfloor\mathrm{x}\:\:+\:\:\sqrt{\mathrm{5}}\rfloor\:\:\:=\:\:\:\lfloor\mathrm{x}\rfloor\:\:+\:\:\lfloor\mathrm{5}\rfloor \\ $$$$\mathrm{then}\:\:\:\:\:\lfloor\mathrm{x}\rfloor\:\:−\:\:\mathrm{x}\:\:\:\:\mathrm{would}\:\mathrm{be}\:\mathrm{greater}\:\mathrm{than} \\ $$$$\left(\mathrm{a}\right)\:\:\:\:\sqrt{\mathrm{5}}\:\:−\:\:\mathrm{2}\:\:\:\:\:\:\:\left(\mathrm{b}\right)\:\:\:\:\sqrt{\mathrm{5}}\:\:−\:\:\mathrm{3}\:\:\:\:\:\:\left(\mathrm{c}\right)\:\:\:\:\sqrt{\mathrm{5}}\:\:\:\:\:\:\:\:\left(\mathrm{d}\right)\:\:\:\:\sqrt{\mathrm{5}}\:\:+\:\:\mathrm{1}\:\:\:\:\:\:\:\left(\mathrm{e}\right)\:\:\:\sqrt{\mathrm{5}}\:\:−\:\:\mathrm{1} \\ $$ Answered by 1549442205PVT last updated…
Question Number 178686 by greougoury555 last updated on 20/Oct/22 $$\:{Given}\:\mathrm{2}{x}^{\mathrm{2}} {y}^{\mathrm{2}} +\mathrm{12}{y}^{\mathrm{2}} =\mathrm{7}{x}^{\mathrm{2}} +\mathrm{647}\: \\ $$$$\:{for}\:{x},{y}\:\varepsilon\:\mathbb{Z}\:. \\ $$$$\:{Find}\:{the}\:{remaider}\:{if}\:\mathrm{3}{x}^{\mathrm{2}} {y}^{\mathrm{4}} \:{divide}\:{by} \\ $$$$\:\:\mathrm{11}\:. \\ $$ Answered…
Question Number 113114 by bemath last updated on 11/Sep/20 Commented by bemath last updated on 11/Sep/20 $$\mathrm{find}\:\mathrm{AD} \\ $$ Answered by mr W last updated…
Question Number 178640 by CrispyXYZ last updated on 19/Oct/22 $$\forall−\mathrm{1}\leqslant{a}\leqslant\mathrm{1},\:\exists\mathrm{0}\leqslant{b}\leqslant\mathrm{2},\:{x}^{\mathrm{2}} −\mathrm{2}{ax}+{a}\geqslant\mid{b}−\mathrm{1}\mid+\mid{b}−\mathrm{2}\mid \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{x}.\:\left({x}\in\mathbb{R}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 113109 by bemath last updated on 11/Sep/20 Commented by bemath last updated on 11/Sep/20 $$\mathrm{any}\:\mathrm{one}\:\mathrm{help}\:\mathrm{this}\:\mathrm{question}? \\ $$ Commented by bemath last updated on…
Question Number 178612 by Acem last updated on 19/Oct/22 $${Be}\:{calm}\:{then}\:{solve}\:\mid\frac{{x}^{\mathrm{2}} +\mathrm{7}{x}−\mathrm{8}}{{x}+\mathrm{3}}\mid\geqslant\:\mathrm{2} \\ $$ Answered by cortano1 last updated on 19/Oct/22 $$\:\mathrm{x}\neq−\mathrm{3} \\ $$$$\:\mid\mathrm{x}^{\mathrm{2}} +\mathrm{7x}−\mathrm{8}\mid\geqslant\mid\mathrm{2x}+\mathrm{6}\mid \\…
Question Number 47543 by maxmathsup by imad last updated on 11/Nov/18 $${solve}\:\left(\mathrm{1}+{ix}\right)^{{n}} ={n}\:\:\:{with}\:{x}\:{unknown}\:{real}\:{and}\:{n}\:{integr}\:{natural}\:. \\ $$ Answered by arcana last updated on 11/Nov/18 $${ln}\left({e}^{\left(\mathrm{1}+{ix}\right){n}} \right)={n}\:{ln}\left({e}\:{e}^{{ix}} \right)={n}…
Question Number 178600 by Acem last updated on 18/Oct/22 $${Solve}\:\mathrm{1}{st}:\:\mid{x}−\mathrm{9}\mid\leqslant\:−\mathrm{1}\:,\:\mathrm{2}{nd}:\:\mid\mathrm{10}{x}+\mathrm{1}\mid>\:−\mathrm{4} \\ $$ Answered by Acem last updated on 19/Oct/22 $$ \\ $$$$\mathrm{1}{st}:\:{Impossible} \\ $$$$ \\…
Question Number 178596 by Acem last updated on 18/Oct/22 $${Let}\:\sqrt{{a}}+\:\sqrt{{b}}=\:\sqrt{\mathrm{2023}}\:\:\:,\:{Find}\:{values}\:{of}\:{a},\:{b}\:\in\:\mathbb{N} \\ $$ Commented by mr W last updated on 18/Oct/22 $${a}=\mathrm{7}\left(\mathrm{17}−{n}\right)^{\mathrm{2}} \\ $$$${b}=\mathrm{7}{n}^{\mathrm{2}} \\ $$$${with}\:{n}=\mathrm{1},\mathrm{2},…,\mathrm{16}…
Question Number 178595 by Acem last updated on 18/Oct/22 $${Solve}\:\frac{\mathrm{2}{x}}{{x}+\mathrm{1}}\geqslant\:\mathrm{3} \\ $$ Answered by Acem last updated on 19/Oct/22 $${The}\:{safest}\:{and}\:{surest}\:{way}\:{to}\:{avoid}\:{making} \\ $$$$\:{mental}\:{mistakes}: \\ $$$$ \\…