Question Number 178586 by infinityaction last updated on 18/Oct/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 178576 by Spillover last updated on 18/Oct/22 $$\mathrm{If}\:\mathrm{a}>\mathrm{b}>\mathrm{0}\:\:\:\mathrm{prove}\:\mathrm{that} \\ $$$$\mathrm{b}<\frac{\mathrm{ae}^{\mathrm{x}} +\mathrm{be}^{−\mathrm{x}} }{\mathrm{e}^{\mathrm{x}} +\mathrm{e}^{−\mathrm{x}} }<\mathrm{a} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 178577 by Spillover last updated on 18/Oct/22 $$\mathrm{prove}\:\mathrm{that} \\ $$$$\left(\mathrm{a}\right)\mathrm{cosh}\:^{−\mathrm{1}} \mathrm{x}=\pm\mathrm{ln}\:\left(\mathrm{x}+\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\right) \\ $$$$\left(\mathrm{b}\right)\mathrm{tanh}\:^{−\mathrm{1}} \mathrm{x}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\left(\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}−\mathrm{1}}\right),\mid\mathrm{x}\mid<\mathrm{1} \\ $$ Answered by depressiveshrek last updated on…
Question Number 178575 by Spillover last updated on 18/Oct/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x} \\ $$$$\mathrm{e}^{\mathrm{sinh}\:^{−\mathrm{1}} \mathrm{x}} =\mathrm{1}+\mathrm{e}^{\mathrm{cosh}\:^{−\mathrm{1}} \mathrm{x}} \\ $$ Answered by mr W last updated on 19/Oct/22…
Question Number 178572 by Spillover last updated on 18/Oct/22 $$\mathrm{Show}\:\mathrm{that}\: \\ $$$$\sim\left[\mathrm{p}\vee\left(\sim\mathrm{p}\wedge\mathrm{q}\right)\right]\:\mathrm{and}\:\left[\sim\mathrm{p}\wedge\sim\mathrm{q}\right]\:\:\mathrm{are} \\ $$$$\mathrm{logically}\:\mathrm{equivalent} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 178573 by Spillover last updated on 18/Oct/22 $$\mathrm{Use}\:\mathrm{the}\:\mathrm{law}\:\mathrm{of}\:\mathrm{algebra}\:\mathrm{of}\:\mathrm{preposition} \\ $$$$\mathrm{to}\:\mathrm{verify}\:\mathrm{the}\:\mathrm{validity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{argument} \\ $$$$\mathrm{If}\:\mathrm{I}\:\mathrm{study},\mathrm{then}\:\mathrm{I}\:\mathrm{will}\:\mathrm{not}\:\mathrm{fail}\:\mathrm{the}\:\mathrm{examination}. \\ $$$$\mathrm{If}\:\mathrm{I}\:\mathrm{do}\:\mathrm{not}\:\mathrm{play}\:\mathrm{football},\mathrm{then}\:\mathrm{I}\:\mathrm{will}\:\mathrm{study}. \\ $$$$\mathrm{But}\:\mathrm{I}\:\mathrm{fail}\:\mathrm{the}\:\mathrm{examination}. \\ $$$$\mathrm{Therefore},\mathrm{I}\:\mathrm{played}\:\mathrm{football} \\ $$ Answered by Spillover…
Question Number 178568 by Spillover last updated on 18/Oct/22 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{preposition} \\ $$$$\left[\left(\mathrm{p}\rightarrow\mathrm{q}\right)\wedge\left(\mathrm{q}\rightarrow\mathrm{r}\right)\right]\rightarrow\left(\mathrm{p}\rightarrow\mathrm{r}\right) \\ $$$$\mathrm{Write}\:\mathrm{down} \\ $$$$\left(\mathrm{a}\right)\mathrm{Converse} \\ $$$$\left(\mathrm{b}\right)\mathrm{Inverse} \\ $$$$\left(\mathrm{c}\right)\mathrm{Contrapositive} \\ $$ Answered by cortano1…
Question Number 178553 by Acem last updated on 18/Oct/22 $${Solve}\:\mathrm{1}{st}:\:\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{11}>\:\mathrm{0} \\ $$$$\:\mathrm{2}{nd}:\:{x}^{\mathrm{4}} +\:\mathrm{4}{x}^{\mathrm{3}} −\:\mathrm{12}{x}^{\mathrm{2}} \leqslant\:\mathrm{0} \\ $$ Answered by a.lgnaoui last updated on 18/Oct/22…
Question Number 178543 by Acem last updated on 17/Oct/22 $${Find}\:{n}\:,\:{P}_{{n}+\mathrm{2}} ^{\:\mathrm{4}} =\:\mathrm{14}{P}_{{n}} ^{\:\mathrm{3}} \\ $$ Answered by Ar Brandon last updated on 18/Oct/22 $$\overset{{n}+\mathrm{2}} {\:}{P}_{\mathrm{4}}…
Question Number 178533 by Acem last updated on 17/Oct/22 $${Find}\:{values}\:{of}\:{n}\:{for}\:{the}\:\left({x}^{\mathrm{2}} +\frac{\mathrm{1}}{{x}}\right)^{{n}} {can}\:{be}\:{contain} \\ $$$$\:{a}\:{constant}\:{term} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com