Category: Algebra

Question Number 50279 by Saorey last updated on 15/Dec/18 $$\{\begin{array}{l}\mathrm{x}+\mathrm{y}=6\\ \mathrm{y}+\mathrm{z}=10\end{array}(\mathrm{x},\mathrm{y},\mathrm{z}>0)$$ Answered by mr W last updated on 15/Dec/18 $$ifx,y,zareintegers,then$$$$(x,y,z)=(1,5,5)/(2,4,6)/(3,3,7)/(4,2,8)/(5,1,9)$$$${if}\:{x},{y},{z}\:{are}\:{real},\:{then}…

Question Number 181318 by mr W last updated on 23/Nov/22 $$ifx+y+z=0,findthemaximumof$$$$\frac{\mid x+2y+3z\mid }{\sqrt{x^2+y^2+z^2}}.$$ Commented by mr W last updated on…

Question Number 115773 by bemath last updated on 28/Sep/20 $$\frac{1-x}{\sqrt{x^2-2x+5}}=\frac{3}{5}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 181279 by mnjuly1970 last updated on 23/Nov/22 Answered by Rasheed.Sindhi last updated on 25/Nov/22 $$\sqrt[3]{x+1}+\sqrt[3]{x+2}+\sqrt[3]{x+3}=0$$$$\overline{)\begin{array}{c}\underset{\Rightarrow a^3+b^3+c^3-3abc=0}{a+b+c=0}\end{array}}$$$${x}+\mathrm{1}+{x}+\mathrm{2}+{x}+\mathrm{3}−\mathrm{3}\sqrt[{\mathrm{3}}]{\left({x}+\mathrm{1}\right)}\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{2}}\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{3}}\:=\mathrm{0}…

Question Number 50163 by Meritguide1234 last updated on 14/Dec/18 Answered by peter frank last updated on 14/Dec/18 $$\mathrm{let}\mathrm{x}=\frac{\mathrm{b}-\mathrm{c}}{\mathrm{a}}$$$$\frac{1}{\mathrm{x}}=\frac{\mathrm{a}}{\mathrm{b}-\mathrm{c}}$$$$\mathrm{y}=\frac{\mathrm{c}-\mathrm{a}}{\mathrm{b}}$$$$\frac{\mathrm{1}}{\mathrm{y}}=\frac{\mathrm{b}}{\mathrm{c}−\mathrm{a}} \…