Question Number 177856 by mathlove last updated on 10/Oct/22 $${p}\left({x}\right)+{p}\left({x}−\mathrm{1}\right)=\mathrm{2}{x}+\mathrm{4} \\ $$$${p}\left({x}\right)=? \\ $$ Answered by blackmamba last updated on 10/Oct/22 $$\:\:{p}\left({x}\right)={ax}+{b}\: \\ $$$$\:\:{p}\left({x}−\mathrm{1}\right)={a}\left({x}−\mathrm{1}\right)+{b}={ax}+{b}−{a} \\…
Question Number 46785 by Tawa1 last updated on 31/Oct/18 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{30}\:\:\:\:\:\:\:\:\:…..\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\frac{\mathrm{x}}{\mathrm{3}}\:+\:\frac{\mathrm{y}}{\mathrm{2}}\:+\:\mathrm{2z}\:\:=\:\:\mathrm{30}\:\:\:\:\:……\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\:\: \\ $$ Answered by MJS last updated on 31/Oct/18…
Question Number 177826 by mathlove last updated on 09/Oct/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 177822 by cortano1 last updated on 09/Oct/22 $$\:\:\:\mathrm{what}\:\mathrm{is}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} \:\mathrm{in}\: \\ $$$$\:\:\:\left(\mathrm{1}−\mathrm{x}\right)\left(\mathrm{1}+\mathrm{2x}\right)\left(\mathrm{1}−\mathrm{3x}\right)\left(\mathrm{1}+\mathrm{4x}\right)\left(\mathrm{1}−\mathrm{5x}\right) \\ $$$$\:\:\:\:…\:\left(\mathrm{1}+\mathrm{14x}\right)\left(\mathrm{1}−\mathrm{15x}\right)\:? \\ $$ Commented by mr W last updated on 10/Oct/22…
Question Number 112280 by bemath last updated on 07/Sep/20 $$\:\:\mathrm{If}\:\mathrm{15}\:\leqslant\:\mid\mathrm{10}−\frac{\mathrm{1}}{\mathrm{3}}\mathrm{a}\mid\:<\:\mathrm{20}\: \\ $$$$\mathrm{find}\:\mathrm{a}\:\in\:\mathbb{R} \\ $$ Answered by john santu last updated on 07/Sep/20 $$\Rightarrow\:\mid\mathrm{10}−\frac{\mathrm{1}}{\mathrm{3}}{a}\mid\:\geqslant\mathrm{15}\:\wedge\:\mid\mathrm{10}−\frac{\mathrm{1}}{\mathrm{3}}{a}\mid\:<\:\mathrm{20} \\ $$$$\left(\mathrm{1}\right)\:\mid\mathrm{10}−\frac{\mathrm{1}}{\mathrm{3}}{a}\mid\:\geqslant\:\mathrm{15}\:…
Question Number 177812 by Spillover last updated on 09/Oct/22 Answered by JDamian last updated on 09/Oct/22 $$\mathrm{cosh}\:\left(\mathrm{ln}\:{x}\right)=\frac{{e}^{\mathrm{ln}\:{x}} +{e}^{−\mathrm{ln}\:{x}} }{\mathrm{2}}=\frac{{x}+\frac{\mathrm{1}}{{x}}}{\mathrm{2}}=\frac{{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2}{x}}\:={A} \\ $$$$\mathrm{sinh}\:\:\left(\mathrm{ln}\:{x}\right)=\frac{{e}^{\mathrm{ln}\:{x}} −{e}^{−\mathrm{ln}\:{x}} }{\mathrm{2}}=\frac{{x}−\frac{\mathrm{1}}{{x}}}{\mathrm{2}}=\frac{{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{x}}={B}…
Question Number 177815 by infinityaction last updated on 09/Oct/22 Answered by mahdipoor last updated on 09/Oct/22 $$\Rightarrow\begin{cases}{{xy}+{yy}+{zy}=\mathrm{2}{y}}\\{{xx}+{yx}+{zx}=\mathrm{2}{x}}\\{{xy}+{yz}+{zx}=\mathrm{1}}\end{cases}\Rightarrow{i}+{ii}−{iii}\Rightarrow \\ $$$${xy}+{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{2}\left({y}+{x}\right)−\mathrm{1}\Rightarrow \\ $$$${g}\left({x},{y}\right)={xy}+{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}\left({x}+{y}\right)=−\mathrm{1}\Rightarrow…
Question Number 46738 by Umar last updated on 30/Oct/18 $${please}\:{help} \\ $$$$ \\ $$$${Write}\:{an}\:{algorithm}\:{that}\:{will}\:{find} \\ $$$${the}\:{solution}\:{of}\:{the}\:{equation} \\ $$$$\:\:\:\:\:\:\:\:\:\:{f}\left({x}\right)=\begin{cases}{−{x},\:{when}\:{x}<\mathrm{0}}\\{{x},\:\:\:\:\:{when}\:{x}\geqslant\mathrm{0}}\end{cases} \\ $$ Commented by hassentimol last updated…
Question Number 177811 by Spillover last updated on 09/Oct/22 Answered by CElcedricjunior last updated on 09/Oct/22 $$\boldsymbol{\mathrm{Tan}}\:\boldsymbol{\mathrm{x}}=\boldsymbol{\mathrm{sinh}\theta}=\frac{\boldsymbol{{e}}^{\boldsymbol{\theta}} −\boldsymbol{{e}}^{−\boldsymbol{\theta}} }{\mathrm{2}} \\ $$$$=>\boldsymbol{\mathrm{e}}^{\mathrm{2}\boldsymbol{\theta}} −\mathrm{2}\boldsymbol{{e}}^{\boldsymbol{\theta}} \boldsymbol{\mathrm{tanx}}−\mathrm{1}=\mathrm{0} \\ $$$$\boldsymbol{\Delta}=\mathrm{4}\boldsymbol{\mathrm{tan}}^{\mathrm{2}}…
Question Number 177810 by Spillover last updated on 09/Oct/22 Answered by Beginner last updated on 09/Oct/22 Commented by Spillover last updated on 09/Oct/22 $$\mathrm{thanks} \\…