Category: Algebra

Question Number 212573 by hardmath last updated on 17/Oct/24 $$\mathrm{Prove}\mathrm{that}:\frac{{5\mathrm{m}}^2-\mathrm{n}}{{\mathrm{n}}^2+3\mathrm{m}}=1$$ Commented by Frix last updated on 18/Oct/24 $$\mathrm{Prove}\mathrm{what}\mathrm{exactly}?$$ Commented…

Question Number 212552 by mnjuly1970 last updated on 17/Oct/24 $$$$$$\stackrel{\mathrm{Q}:}{}\mathrm{In}\mathrm{A}\stackrel{\mathrm{\Delta }}{\mathrm{B}C}:cos\left(\mathrm{A}\right)+cos\left(\mathrm{B}\right)+2cos\left(\mathrm{C}\right)=2$$$$$$$$\mathrm{show}\mathrm{that}:a+b=2c\mathrm{<img\; draggable="false"\; role="img"\; class="emoji"\; alt="◼"\; src="https://s.w.org/images/core/emoji/15.1.0/svg/25fc.svg">}$$$$$$ Answered by Ghisom…

Question Number 212550 by mnjuly1970 last updated on 17/Oct/24 $$$$$$thefollowingequationhas$$$$noroot.findtherelationship$$$$betweena,b,c:$$$$1:c⩽2$$$$2:c>2$$$$3:c>ab$$$$\:\:\:\:\mathrm{4}:\:{c}\leqslant\:{ab} \…

Question Number 212531 by RojaTaniya last updated on 16/Oct/24 Answered by a.lgnaoui last updated on 17/Oct/24 $$\boldsymbol{\mathrm{x}}=\mathrm{1}+^{\mathrm{7}} \sqrt{\mathrm{2}}\:+\left(^{\mathrm{7}} \sqrt{\mathrm{2}}\:\right)^{\mathrm{2}} +\left(^{\mathrm{7}} \sqrt{\mathrm{2}}\:\right)^{\mathrm{3}} +\left(^{\mathrm{7}} \sqrt{\mathrm{2}\:}\:\right)^{\mathrm{4}} +\left(^{\mathrm{7}} \sqrt{\mathrm{2}}\:\right)^{\mathrm{5}}…

Question Number 212522 by Nadirhashim last updated on 16/Oct/24 $$\mathit{i}\mathit{n}\mathit{h}\mathit{o}\mathit{w}\mathit{m}\mathit{a}\mathit{n}\mathit{y}\mathit{w}\mathit{a}\mathit{y}\mathit{s}\mathit{w}\mathit{e}$$$$\mathit{c}\mathit{a}\mathit{n}\mathit{d}\mathit{i}\mathit{s}\mathit{t}\mathit{r}\mathit{i}\mathit{b}\mathit{u}\mathit{t}\mathit{e}6\mathit{d}\mathit{i}\mathit{s}\mathit{t}\mathit{i}\mathit{n}\mathit{c}\mathit{t}$$$$\mathit{b}\mathit{a}\mathit{l}\mathit{l}\mathit{s}\mathit{i}\mathit{n}3\mathit{i}\mathit{d}\mathit{e}\mathit{n}\mathit{t}\mathit{i}\mathit{c}\mathit{a}\mathit{l}\mathit{b}\mathit{o}\mathit{x}\mathit{e}\mathit{s}$$ Answered by mehdee7396 last updated on 16/Oct/24 $$\:\mathrm{6}/\mathrm{0}/\mathrm{0}\:{or}\:\mathrm{5}/\mathrm{1}/\mathrm{0}\:{or}\:\mathrm{4}/\mathrm{2}/\mathrm{0}\:\:{or}\:\mathrm{4}/\mathrm{1}/\mathrm{1}\:{or}\:\mathrm{3}/\mathrm{3}/\mathrm{0}/\:{or}\:\mathrm{3}/\mathrm{2}/\mathrm{1}\:{or}\:\mathrm{2}/\mathrm{2}/\mathrm{2} \…