Question Number 178240 by Shrinava last updated on 14/Oct/22 $$\frac{\mathrm{a}^{\boldsymbol{\mathrm{n}}+\mathrm{1}} \:+\:\mathrm{b}^{\boldsymbol{\mathrm{n}}+\mathrm{1}} }{\mathrm{a}^{\boldsymbol{\mathrm{n}}} \:+\:\mathrm{b}^{\boldsymbol{\mathrm{n}}} }\:=\:\sqrt{\mathrm{ab}}\:\:\:\mathrm{find}\:\:\:\mathrm{n}=? \\ $$ Answered by Rasheed.Sindhi last updated on 14/Oct/22 $$\mathrm{a}^{\boldsymbol{\mathrm{n}}+\mathrm{1}} \:+\:\mathrm{b}^{\boldsymbol{\mathrm{n}}+\mathrm{1}}…
Question Number 178219 by Acem last updated on 14/Oct/22 $${How}\:{many}\:{different}\:{words}\:{of}\:\mathrm{4}\:{letters}\:{can} \\ $$$$\:{be}\:{formed}\:{from}\:{the}\:{word}\:\boldsymbol{{Flat}}\:\boldsymbol{{earth}} \\ $$$$ \\ $$ Commented by Acem last updated on 14/Oct/22 $$\:{I}\:{sweep}\:{it}\:{over}\:{the}\:{planet} \\…
Question Number 47139 by Tawa1 last updated on 05/Nov/18 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{n}:\:\:\:\:\:\:\mathrm{4}^{\mathrm{n}} \:+\:\mathrm{2}^{\mathrm{n}} \:−\:\mathrm{6}\:=\:\left(\mathrm{2}^{\mathrm{n}} \:−\:\mathrm{4}\right)^{\mathrm{3}} \:+\:\left(\mathrm{4}^{\mathrm{n}} \:−\:\mathrm{2}\right)^{\mathrm{3}} \:…. \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 05/Nov/18…
Question Number 178213 by Acem last updated on 14/Oct/22 $${Let}\:{S}=\:\left\{\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{4},\:…,\:\mathrm{28},\:\mathrm{29},\:\mathrm{30}\right\} \\ $$$$\:{How}\:{many}\:{subgroups}\:{of}\:\mathrm{3}\:{elements}\:{are}\:{in}\:{the}\:{S} \\ $$$$\:\:{so}\:{that}\:{their}\:{sum}\:{is}\:{a}\:{multiple}\:{of}\:\mathrm{3} \\ $$$$ \\ $$$$\:{The}\:{answer}\:{is}\:\mathrm{1}\:\mathrm{360}\:{subgroup}\mathrm{s} \\ $$$$ \\ $$ Commented by Acem…
Question Number 178200 by Shrinava last updated on 13/Oct/22 Answered by Frix last updated on 14/Oct/22 $${f}\left({x}\right)=\mathrm{e}^{\mathrm{2}{x}/\mathrm{3}} \\ $$$${f}\left({x}\right)×{f}\left({x}/\mathrm{2}\right)=\mathrm{e}^{\mathrm{2}{x}/\mathrm{3}} \mathrm{e}^{{x}/\mathrm{3}} =\mathrm{e}^{{x}} \\ $$$$\Omega=−\infty\:\left[\mathrm{limit}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{exist}\right] \\ $$…
Question Number 178180 by mathlove last updated on 13/Oct/22 $${x}+\frac{\mathrm{1}}{{x}}=−\mathrm{1}\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{1377}} =? \\ $$ Commented by saboorhalimi last updated on 13/Oct/22 Answered by saboorhalimi last updated…
Question Number 112624 by Aina Samuel Temidayo last updated on 09/Sep/20 $$\mathrm{Minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}−\mathrm{3}\:\mathrm{is} \\ $$ Answered by MJS_new last updated on 09/Sep/20 $${x}^{\mathrm{2}} +\mathrm{1}+\frac{\mathrm{1}}{{x}^{\mathrm{2}}…
Question Number 112626 by Aina Samuel Temidayo last updated on 09/Sep/20 Answered by som(math1967) last updated on 09/Sep/20 $$\left.\mathrm{a}\right)\frac{\mathrm{x}−\mathrm{y}}{\mathrm{b}−\mathrm{a}}=\frac{\mathrm{y}−\mathrm{z}}{\mathrm{c}−\mathrm{b}}=\frac{\mathrm{z}−\mathrm{x}}{\mathrm{a}−\mathrm{c}} \\ $$ Commented by Aina Samuel…
Question Number 112625 by Aina Samuel Temidayo last updated on 09/Sep/20 $$\mathrm{If}\:\mathrm{a}+\mathrm{b}=\mathrm{5},\:\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} =\mathrm{13},\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{a}−\mathrm{b}\:\left(\mathrm{where}\:\mathrm{a}>\mathrm{b}\right)\:\mathrm{is} \\ $$ Commented by MJS_new last updated on 09/Sep/20…
Question Number 47068 by 143jesus last updated on 04/Nov/18 $$\left(\mathrm{a}−\mathrm{b}\right)^{\mathrm{2}} \\ $$ Answered by ajfour last updated on 04/Nov/18 $$=\:\left({a}−{b}\right)\left({a}−{b}\right) \\ $$$$=\:{a}\left({a}−{b}\right)−{b}\left({a}−{b}\right) \\ $$$$=\:{a}^{\mathrm{2}} −{ab}−{ba}+{b}^{\mathrm{2}}…