Question Number 111175 by 9696147350 last updated on 02/Sep/20 Answered by ajfour last updated on 02/Sep/20 $$\sqrt{{x}}={t} \\ $$$${t}^{\mathrm{4}} −\frac{\mathrm{3}{t}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}=\mathrm{0}\:\:\:\:,\:\:{let} \\ $$$$\left({t}^{\mathrm{2}} +{pt}+{q}\right)\left({t}^{\mathrm{2}} −{pt}+\frac{\mathrm{1}}{\mathrm{2}{q}}\right)=\mathrm{0} \\…
Question Number 176684 by peter frank last updated on 25/Sep/22 Commented by peter frank last updated on 25/Sep/22 $$\mathrm{thank}\:\mathrm{you} \\ $$ Commented by Rasheed.Sindhi last…
Question Number 176676 by Rasheed.Sindhi last updated on 24/Sep/22 $$\mathrm{If}\:\:\mathrm{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{3}} }=\mathrm{1}, \\ $$$$\mathrm{prove}\:\mathrm{that} \\ $$$$\mathrm{x}^{\mathrm{5}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{5}} }=−\left(\mathrm{x}^{\mathrm{4}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{4}} }\right) \\ $$ Answered by mr…
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Question Number 176636 by cortano1 last updated on 23/Sep/22 $$\:\begin{cases}{{p}^{\mathrm{3}} +{q}^{\mathrm{3}} ={r}^{\mathrm{2}} }\\{{p}^{\mathrm{3}} +{r}^{\mathrm{3}} ={q}^{\mathrm{2}} }\\{{q}^{\mathrm{3}} +{r}^{\mathrm{3}} ={p}^{\mathrm{2}} }\end{cases} \\ $$$$\:\Rightarrow\mathrm{20}{pqr}\:=? \\ $$ Commented by…
Question Number 45546 by Tawa1 last updated on 14/Oct/18 $$\mathrm{Simplify}:\:\:\:\:\:\sqrt[{\mathrm{3}}]{\sqrt{\mathrm{5}}\:\:+\:\:\mathrm{2}}\:\:\:+\:\:\:\:\sqrt[{\mathrm{3}}]{\sqrt{\mathrm{5}}\:\:−\:\mathrm{2}}\:\: \\ $$ Commented by Meritguide1234 last updated on 14/Oct/18 $${x}^{\mathrm{3}} =\left(\sqrt{\mathrm{5}}+\mathrm{2}\right)+\left(\sqrt{\mathrm{5}}−\mathrm{2}\right)+\mathrm{3}.{x} \\ $$$$ \\ $$…
Question Number 111062 by malwan last updated on 01/Sep/20 Commented by malwan last updated on 01/Sep/20 $${please} \\ $$$${I}\:{need}\:{all}\:{solutions}\:{for}\:{exam}\: \\ $$ Commented by malwan last…
Question Number 176598 by Rasheed.Sindhi last updated on 22/Sep/22 $${x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}^{\mathrm{3}} }=\mathrm{1} \\ $$$$\frac{\left({x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}} }\right)^{\mathrm{3}} −\mathrm{1}}{{x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}} }}=? \\ $$$${Q}#\mathrm{176387}\:{reposted}\:{for}\:{a}\:{new}\:{answer}. \\ $$ Answered by…
Question Number 176592 by Shrinava last updated on 22/Sep/22 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{3}^{\boldsymbol{\mathrm{x}}} \:−\:\mathrm{4}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{6}^{\boldsymbol{\mathrm{x}}} \:−\:\mathrm{9}^{\boldsymbol{\mathrm{x}}} \:=\:\mathrm{1} \\ $$ Answered by Frix last updated on…