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Category: Algebra

2x-3y-z-7-4x-y-2z-1-x-5y-3z-14-find-x-y-z-

Question Number 212479 by hardmath last updated on 14/Oct/24 {2x+3yz=74xy+2z=1x+5y+3z=14find:x,y,z=? Answered by A5T last updated on 14/Oct/24 3(ii)+(i)14x+5z=10(iv)5(ii)+(iii)19x+13z=19(v)$$\mathrm{13}\left({iv}\right)−\mathrm{5}\left({v}\right)\Rightarrow\mathrm{87}{x}=\mathrm{35}\Rightarrow{x}=\frac{\mathrm{35}}{\mathrm{87}}\Rightarrow{z}=\frac{\mathrm{76}}{\mathrm{87}}\Rightarrow{y}=\frac{\mathrm{205}}{\mathrm{87}} \

Question-212428

Question Number 212428 by Spillover last updated on 13/Oct/24 Answered by Yassine84 last updated on 13/Oct/24 letf(x)=(1+x2)(1+x3)(1+x4)then$${li}\underset{\mathrm{1}} {{m}}\:\frac{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}^{\mathrm{3}} \right)\left(\mathrm{1}+{x}^{\mathrm{4}}…

x-2y-3z-1-2x-y-z-4-3x-y-2z-7-find-x-y-z-

Question Number 212424 by hardmath last updated on 13/Oct/24 {x+2y3z=12xy+z=43x+y+2z=7find:x,y,z=? Answered by A5T last updated on 13/Oct/24 (ii)+(iii)5x+3z=11(iv)2(iii)(i)5x+7z=13(v)$$\left({v}\right)−\left({iv}\right)\Rightarrow\mathrm{4}{z}=\mathrm{2}\Rightarrow{z}=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow{x}=\frac{\mathrm{19}}{\mathrm{10}}\Rightarrow{y}=\frac{\mathrm{3}}{\mathrm{10}} \