Question Number 111909 by john santu last updated on 05/Sep/20 $${solve}\:\begin{cases}{{x}\sqrt{{x}}+{y}\sqrt{{y}}\:=\:\mathrm{5}}\\{{x}\sqrt{{y}}\:+{y}\sqrt{{x}}\:=\:\mathrm{1}}\end{cases} \\ $$ Answered by bemath last updated on 05/Sep/20 $${let}\:\sqrt{{x}}\:=\:{u}\:;\:\sqrt{{y}}\:=\:{v} \\ $$$$\begin{cases}{{u}^{\mathrm{3}} +{v}^{\mathrm{3}} \:=\:\mathrm{5}\Rightarrow\left({u}+{v}\right)^{\mathrm{3}}…
Question Number 177442 by peter frank last updated on 05/Oct/22 Answered by mr W last updated on 05/Oct/22 $${x}\neq\mathrm{1} \\ $$$$\left({x}−\mathrm{1}\right)\left(\mathrm{1}+{x}+…+{x}^{\mathrm{2013}} \right)=\mathrm{0} \\ $$$${x}^{\mathrm{2014}} −\mathrm{1}=\mathrm{0}…
Question Number 46355 by denil last updated on 24/Oct/18 $${y}/{ax}−{b}={j} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 177375 by a.lgnaoui last updated on 04/Oct/22 $$\mathrm{soit}\:\mathrm{k}\:\mathrm{un}\:\mathrm{entier}\:\mathrm{naturel}\:\mathrm{non}\:\mathrm{nul}\:,\mathrm{S}\:\mathrm{un}\:\mathrm{nombre}\:\mathrm{fini}\:\mathrm{de}\: \\ $$$$\mathrm{nombres}\:\mathrm{premiers}\:\mathrm{impair} \\ $$$$−\mathrm{Demontrer}\:\mathrm{qu}\:\mathrm{il}\:\mathrm{existe}\:\mathrm{au}\:\mathrm{plus}\:\mathrm{une}\:\mathrm{maniere}\left(\mathrm{a}\:\mathrm{rotation}\:\mathrm{et}\:\mathrm{symetrie}\:\mathrm{axiale}\right) \\ $$$$\mathrm{de}\:\mathrm{disposer}\:\mathrm{les}\:\mathrm{elements}\:\mathrm{de}\:\mathrm{S}\:\mathrm{sur}\:\mathrm{un}\:\mathrm{cercle}\:\mathrm{de}\:\mathrm{sorte}\:\mathrm{que}\:\mathrm{le}\:\mathrm{priduit}\:\mathrm{de}\:\mathrm{2}\:\mathrm{nombres}\: \\ $$$$\mathrm{places}\:\mathrm{l}'\mathrm{un}\:\mathrm{a}\:\mathrm{cote}\:\mathrm{de}\:\mathrm{l}'\mathrm{autre}\:\mathrm{soit}\:\mathrm{toujours}\:\mathrm{de}\:\mathrm{la}\:\mathrm{forme}\:\left(\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{k}}\right),\mathrm{x}\:\mathrm{un}\:\mathrm{entier}\:\mathrm{naturel}\:\mathrm{non}\:\mathrm{nul}. \\ $$$$\:\:\:\:\:\:\:{Extrait}\:{de}\:{Olimpiad}\:{de}\:{Mathematiques}\:\left({France}\:\mathrm{2022}\right). \\ $$$$ \\ $$…
Question Number 46297 by pieroo last updated on 23/Oct/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{which}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{one}-\mathrm{eighth} \\ $$$$\mathrm{of}\:\mathrm{its}\:\mathrm{supplement}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 23/Oct/18 $${x}+{y}=\mathrm{180}^{{o}} \\ $$$${x}=\frac{{y}}{\mathrm{8}} \\…
Question Number 46268 by Saorey last updated on 23/Oct/18 $$\mathrm{please}\:\mathrm{help}\:\mathrm{me}! \\ $$$$\mathrm{L}=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left(\frac{\mathrm{p}}{\mathrm{1}−\mathrm{x}^{\mathrm{p}} }−\frac{\mathrm{q}}{\mathrm{1}−\mathrm{x}^{\mathrm{q}} }\right)\:,\:\left(\mathrm{p},\mathrm{q}\in\mathbb{R}\right) \\ $$ Commented by maxmathsup by imad last updated on…
Question Number 177331 by mr W last updated on 03/Oct/22 $${a}+{b}+{c}=\mathrm{0} \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} =\mathrm{4} \\ $$$${a}^{\mathrm{4}} +{b}^{\mathrm{4}} +{c}^{\mathrm{4}} =? \\ $$ Answered by…
Question Number 46245 by rpseelam last updated on 23/Oct/18 $$\frac{\mathrm{1}}{\mathrm{1}.\mathrm{3}.\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{3}.\mathrm{5}.\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{5}.\mathrm{7}.\mathrm{9}}+…..{nth}\:{term} \\ $$ Commented by maxmathsup by imad last updated on 23/Oct/18 $${let}\:{S}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\frac{\mathrm{1}}{\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{2}{k}+\mathrm{3}\right)\left(\mathrm{2}{k}+\mathrm{5}\right)}\:\:\:{let}\:{find}\:\:{S}_{{n}}…
Question Number 177307 by a.lgnaoui last updated on 03/Oct/22 $${Resoudre}\:{l}\:{equation}\: \\ $$$$\frac{{a}}{\mathrm{cos}\:^{\mathrm{3}} {x}}+\frac{{b}}{\mathrm{cos}\:{x}}=\frac{{c}}{\mathrm{sin}\:{x}}\:\:\:\: \\ $$$${a},{b},{c}\:{reels}\:\:\:\:{x}#\left\{{k}\frac{\pi}{\mathrm{2}}\:\:{k}\in\mathbb{Z}\right\} \\ $$ Answered by Frix last updated on 04/Oct/22 $${t}=\mathrm{tan}\:{x}\:\Leftrightarrow\:{x}=\mathrm{tan}^{−\mathrm{1}}…