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Category: Algebra

Question-46088

Question Number 46088 by Cheyboy last updated on 21/Oct/18 Answered by $@ty@m last updated on 21/Oct/18 $${Let}\:{Solution}\:{set}\:=\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix} \\ $$$${a}+{b}=\mathrm{8}\:…\left(\mathrm{1}\right) \\ $$$${b}+{d}=\mathrm{8}\:…\left(\mathrm{2}\right) \\ $$$$\Rightarrow{a}={d}\:…\left(\mathrm{3}\right) \\ $$$${c}−{d}=\mathrm{6}\:…\left(\mathrm{4}\right)…

x-2-x-3-x-1-2-0-

Question Number 111623 by weltr last updated on 04/Sep/20 $$\left({x}−\mathrm{2}\right)\left({x}+\mathrm{3}\right)\left({x}−\mathrm{1}\right)^{\mathrm{2}} \:\geqslant\:\mathrm{0} \\ $$ Commented by ZiYangLee last updated on 04/Sep/20 $${x}\leqslant−\mathrm{3}\:\cup\:{x}\geqslant\mathrm{2}? \\ $$ Commented by…

Calculas-1-2-2-2-3-2-16-2-16-1-3-2-4-3-5-15-17-

Question Number 177144 by Shrinava last updated on 01/Oct/22 $$\mathrm{Calculas}: \\ $$$$\frac{\mathrm{1}^{\mathrm{2}} \:+\:\mathrm{2}^{\mathrm{2}} \:+\:\mathrm{3}^{\mathrm{2}} \:+\:…\:+\:\mathrm{16}^{\mathrm{2}} \:−\:\mathrm{16}}{\mathrm{1}\centerdot\mathrm{3}\:+\:\mathrm{2}\centerdot\mathrm{4}\:+\:\mathrm{3}\centerdot\mathrm{5}\:+\:…\:+\:\mathrm{15}\centerdot\mathrm{17}} \\ $$ Answered by BaliramKumar last updated on 01/Oct/22…

Question-111601

Question Number 111601 by A8;15: last updated on 04/Sep/20 Answered by bemath last updated on 04/Sep/20 $$\frac{\mathrm{7}.\mathrm{7}^{\mathrm{2004}} +\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}\:=\:\frac{\mathrm{8}.\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}} \\ $$ Terms…

DTM-2020-savollaridan-biri-x-x-t-me-matematik-olimpiadachilar-

Question Number 111586 by Khanacademy last updated on 04/Sep/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{DTM}}−\mathrm{2020}\:\:\boldsymbol{{savollaridan}}\:\:\boldsymbol{{biri}}. \\ $$$$\:\int\boldsymbol{{x}}^{\boldsymbol{{x}}} =\:? \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{{t}}.\boldsymbol{{me}}/\boldsymbol{{matematik\_olimpiadachilar}} \\ $$ Commented by Her_Majesty last updated on 04/Sep/20 $${see}\:{comment}\:{to}\:{question}\:\mathrm{111558}…