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Question Number 47986 by behi83417@gmail.com last updated on 17/Nov/18 Commented by maxmathsup by imad last updated on 18/Nov/18 $$\left.\mathrm{2}\right)\:\left({e}\right)\:\Leftrightarrow\:\frac{\mathrm{1}−{x}^{\mathrm{8}} }{\mathrm{1}−{x}}\:=\mathrm{0}\:\:\Leftrightarrow\:{x}^{\mathrm{8}} =\mathrm{1}\:\:\:{and}\:{x}\neq\mathrm{1}\:\:\:{x}={r}\:{e}^{{i}\theta} \:\Rightarrow{r}^{\mathrm{8}} \:{e}^{{i}\mathrm{8}\theta} ={e}^{{i}\mathrm{2}{k}\pi} \:\Rightarrow…
Question Number 179058 by sciencestudent last updated on 24/Oct/22