Question Number 116056 by Study last updated on 30/Sep/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{5}^{{n}} }{{n}!}=? \\ $$ Answered by Dwaipayan Shikari last updated on 30/Sep/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty}…
Question Number 181590 by pete last updated on 27/Nov/22 $$\mathrm{Mr}.\:\mathrm{Jibril}\:\mathrm{is}\:\mathrm{four}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old}\:\mathrm{as}\:\mathrm{his}\:\mathrm{son}. \\ $$$$\mathrm{Four}\:\mathrm{years}\:\mathrm{ago},\:\mathrm{he}\:\mathrm{was}\:\mathrm{seven}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old} \\ $$$$\mathrm{as}\:\mathrm{his}\:\mathrm{son}.\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{years}\:\mathrm{will}\:\mathrm{Mr} \\ $$$$\mathrm{Jibril}'\mathrm{s}\:\mathrm{age}\:\mathrm{be}\:\mathrm{twice}\:\mathrm{his}\:\mathrm{son}'\mathrm{s}\:\mathrm{age}? \\ $$ Answered by Acem last updated on 27/Nov/22…
Question Number 50511 by behi83417@gmail.com last updated on 17/Dec/18 $${refer}\:{to}\:{question}\:#\mathrm{50278} \\ $$$$\sqrt{{a}+\sqrt{{a}−{x}}}+\sqrt{{a}−\sqrt{{a}+{x}}}=\mathrm{2}{x} \\ $$ Answered by behi83417@gmail.com last updated on 17/Dec/18 Commented by behi83417@gmail.com last…
Question Number 181541 by mr W last updated on 26/Nov/22 $${solve}\:{for}\:{f}\left({x}\right)\:{such}\:{that} \\ $$$$\mathrm{f}'\left(\mathrm{x}\right)=\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right) \\ $$ Commented by a.lgnaoui last updated on 26/Nov/22 $$\left[{f}^{−\mathrm{1}} \left({x}\right)\right]^{'}…
Question Number 181524 by Rasheed.Sindhi last updated on 26/Nov/22 $${f}\left({x}+\frac{\mathrm{1}}{{x}}\right)={x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}} }\:;\:{f}\left(\mathrm{3}\right)=? \\ $$$${Q}#\mathrm{181447}\:{reposted}\:{for}\:{a}\:\boldsymbol{{different}}\:{answer}. \\ $$ Answered by Rasheed.Sindhi last updated on 26/Nov/22 $${f}\left({x}+\frac{\mathrm{1}}{{x}}\right)={x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}}…
Question Number 181521 by CrispyXYZ last updated on 26/Nov/22 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{x}\:\:\mathrm{such}\:\mathrm{that} \\ $$$$\begin{cases}{\mathrm{sin}{x}>\mathrm{0}}\\{\sqrt{\mathrm{3}}\mathrm{sin}{x}+\mathrm{cos}{x}>\mathrm{0}}\\{\mathrm{0}<{x}<\mathrm{2}\pi}\end{cases} \\ $$ Answered by mr W last updated on 26/Nov/22 $$\mathrm{sin}\:{x}\:>\mathrm{0}\:\Rightarrow\mathrm{0}<{x}<\pi \\ $$$$\sqrt{\mathrm{3}}\:\mathrm{sin}\:{x}+\mathrm{cos}\:{x}>\mathrm{0}\:\Rightarrow\mathrm{cot}\:{x}>−\sqrt{\mathrm{3}}…
Question Number 115986 by bemath last updated on 30/Sep/20 Answered by MJS_new last updated on 30/Sep/20 $$\sqrt{\mathrm{5}−{x}}=\mathrm{5}−{x}^{\mathrm{2}} \\ $$$$\mathrm{5}−{x}\geqslant\mathrm{0}\:\Rightarrow\:{x}\leqslant\mathrm{5} \\ $$$$\mathrm{5}−{x}^{\mathrm{2}} \geqslant\mathrm{0}\:\Rightarrow\:−\sqrt{\mathrm{5}}\leqslant{x}\leqslant\sqrt{\mathrm{5}} \\ $$$$\Rightarrow\:−\sqrt{\mathrm{5}}\leqslant{x}\leqslant\sqrt{\mathrm{5}} \\…
Question Number 50446 by ANTARES VY last updated on 16/Dec/18 Commented by JDlix last updated on 16/Dec/18 $${is}\:{the}\:{biggest}\:{triangle}\:{right}\:{angled}\:{triangle}? \\ $$ Commented by mr W last…
Question Number 181489 by Shrinava last updated on 25/Nov/22 $$\boldsymbol{\mathrm{a}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{b}}\:\mathrm{are}\:\mathrm{mutuallly}\:\mathrm{prime}\:\mathrm{numbers} \\ $$$$\mathrm{If}\:\:\:\frac{\mathrm{3}}{\mathrm{8}}\:<\:\frac{\boldsymbol{\mathrm{a}}}{\boldsymbol{\mathrm{b}}}\:<\:\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\mathrm{Find}\:\:\:\left(\boldsymbol{\mathrm{b}}−\boldsymbol{\mathrm{a}}\right)_{\boldsymbol{\mathrm{min}}} \\ $$ Answered by mr W last updated on 26/Nov/22 $$\frac{\mathrm{3}}{\mathrm{8}}<\frac{{a}}{{b}}<\frac{\mathrm{2}}{\mathrm{5}}…
Question Number 50387 by Abdo msup. last updated on 16/Dec/18 $${E}\:{is}\:{a}\:{euclidian}\:{space}\:{and}\:{f}\:\:{from}\:{E}\:{to}\:{E}\:{verify} \\ $$$$\forall\left({x},{y}\right)\:\in{E}^{\mathrm{2}} \:\:\:\:\left({x}\:\mid{f}\left({y}\right)\right)=\left({f}\left({x}\right)\mid{y}\right)\:{prove}\:{that}\:{f}\:{is}\:{linear}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com