Question Number 109569 by bemath last updated on 24/Aug/20 Answered by john santu last updated on 24/Aug/20 $$\:\:\:\frac{\leftrightharpoons{JS}\rightleftharpoons}{\spadesuit} \\ $$$${let}\:\:\frac{{x}−\mathrm{1}}{{x}}={t}\:\rightarrow{x}=\frac{\mathrm{1}}{\mathrm{1}−{t}} \\ $$$$\left(\mathrm{1}\right){f}\left(\frac{\mathrm{1}}{\mathrm{1}−{t}}\right)+{f}\left({t}\right)\:=\:\frac{\mathrm{1}}{\mathrm{1}−{t}}+\mathrm{1}=\frac{\mathrm{2}−{t}}{\mathrm{1}−{t}} \\ $$$${set}\:{x}\:=\:\frac{{t}−\mathrm{1}}{{t}} \\…
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Question Number 175081 by Shrinava last updated on 18/Aug/22 $$\mathrm{If}\:\mathrm{in}\:\bigtriangleup\mathrm{ABC}\:,\:\mathrm{m}\left(\sphericalangle\mathrm{B}\right)=\mathrm{3m}\left(\sphericalangle\mathrm{C}\right)\:\mathrm{then}: \\ $$$$\mathrm{a}\:=\:\left(\mathrm{b}\:−\:\mathrm{c}\right)\:\sqrt{\frac{\mathrm{b}}{\mathrm{c}}\:+\:\mathrm{1}}\:\:,\:\:\mathrm{b}\:>\:\mathrm{a}\:+\:\frac{\mathrm{c}}{\mathrm{2}} \\ $$$$\mathrm{R}\:=\:\sqrt{\frac{\mathrm{c}^{\mathrm{3}} }{\mathrm{3c}\:−\:\mathrm{b}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 175080 by mnjuly1970 last updated on 18/Aug/22 $$ \\ $$$$\:\:\:\boldsymbol{{calculate}}\:.. \\ $$$$\:\boldsymbol{{lim}}_{\:\boldsymbol{{x}}\rightarrow\:\mathrm{0}^{\:+} } \int_{\mathrm{0}} ^{\:\frac{\boldsymbol{\pi}}{\mathrm{2}}} \boldsymbol{{J}}_{\mathrm{0}} \:\left(\:\boldsymbol{{x}}.\boldsymbol{{cos}}\left(\boldsymbol{\emptyset}\:\right)\right).\boldsymbol{{cos}}\left(\boldsymbol{\emptyset}\right)\boldsymbol{{d}\emptyset}\:=\:? \\ $$$$\:\:\:\boldsymbol{{where}}\:: \\ $$$$\:\:\:\:\:\boldsymbol{{J}}_{\boldsymbol{\nu}} \:\left(\:\boldsymbol{{x}}\:\right)=\:\boldsymbol{{x}}^{\:\boldsymbol{{v}}} .\underset{\boldsymbol{{n}}=\mathrm{0}}…
Question Number 109544 by 1549442205PVT last updated on 25/Aug/20 $$\mathrm{Exclude}\:\mathrm{m}\:\mathrm{and}\:\mathrm{n}\:\mathrm{from}\:\mathrm{the}\:\mathrm{equalities}: \\ $$$$\mathrm{a}=\mathrm{m}+\mathrm{n},\mathrm{b}^{\mathrm{3}} =\mathrm{m}^{\mathrm{3}} +\mathrm{n}^{\mathrm{3}} ,\mathrm{c}^{\mathrm{5}} =\mathrm{m}^{\mathrm{5}} +\mathrm{n}^{\mathrm{5}} \\ $$ Commented by Her_Majesty last updated on…
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Question Number 109516 by ajfour last updated on 24/Aug/20 $$\mathrm{cos}\:\left(\mathrm{1}−{i}\right)={a}+{ib} \\ $$$${Find}\:\:{a},\:{b}. \\ $$ Answered by Dwaipayan Shikari last updated on 24/Aug/20 $${cos}\left(\mathrm{1}−{i}\right)=\frac{{e}^{{i}\left(\mathrm{1}−{i}\right)} +{e}^{−{i}\left(\mathrm{1}−{i}\right)} }{\mathrm{2}}=\frac{{e}^{\mathrm{1}+{i}}…
Question Number 175049 by mnjuly1970 last updated on 17/Aug/22 $$ \\ $$$$\:\:\:\:\:\:\mathbb{Z}_{\:{p}} \:,\:{is}\:\:{a}\:\:{field}\:…\left(\:\:{p}\:{is}\:{prime}\:\right) \\ $$$$\:\:\:\:\:\: \\ $$ Commented by kaivan.ahmadi last updated on 17/Aug/22 $${we}\:{show}\:{that}\:{every}\:{element}…
Question Number 43971 by LYCON TRIX last updated on 19/Sep/18 Answered by MJS last updated on 19/Sep/18 $$\mathrm{2}{x}^{\mathrm{2}} +{x}=\mathrm{3}{y}^{\mathrm{2}} +{y} \\ $$$${x}={y}+{a} \\ $$$${y}^{\mathrm{2}} −\mathrm{4}{ay}−{a}\left(\mathrm{2}{a}+\mathrm{1}\right)=\mathrm{0}…
Question Number 109500 by john santu last updated on 24/Aug/20 $${Given}\:\begin{cases}{{a}^{\mathrm{2}} +{ab}+{bc}+{ac}={a}+{c}}\\{{b}^{\mathrm{2}} +{ab}+{bc}+{ac}={b}+{a}}\\{{c}^{\mathrm{2}} +{ab}+{bc}+{ac}={c}+{b}}\end{cases} \\ $$$${find}\:{the}\:{value}\:{of}\:{a}+{b}+{c}\: \\ $$ Answered by bemath last updated on 24/Aug/20…