Question Number 175443 by Linton last updated on 30/Aug/22 $${solve}\:{for}\:{x} \\ $$$$\mathrm{16}^{{x}} +\mathrm{20}^{{x}} =\:\mathrm{25}^{{x}} \\ $$ Answered by Ar Brandon last updated on 30/Aug/22 $$\mathrm{16}^{{x}}…
Question Number 109901 by ajfour last updated on 26/Aug/20 $${If}\:{first}\:{n}\:{terms}\:{of}\:{an}\:{A}.{P}.\:{is}\:{cn}^{\mathrm{2}} , \\ $$$${find}\:{sum}\:{of}\:{squares}\:{of}\:{its}\:{first} \\ $$$${n}\:{terms}. \\ $$ Answered by mr W last updated on 26/Aug/20…
Question Number 109895 by qwerty111 last updated on 26/Aug/20 Commented by mathdave last updated on 26/Aug/20 $${the}\:{question}\:{does}\:{not}\:{converge} \\ $$ Commented by Her_Majesty last updated on…
Question Number 175430 by mathlove last updated on 30/Aug/22 Commented by infinityaction last updated on 30/Aug/22 $$\frac{{x}}{{y}+{z}}+\mathrm{1}+\frac{{y}}{{z}+{x}}+\mathrm{1}+\frac{{z}}{{x}+{y}}+\mathrm{1}\:=\mathrm{37} \\ $$$${x}+{y}+{z}\left[\frac{\mathrm{1}}{{y}+{z}}+\frac{\mathrm{1}}{{z}+{x}}+\frac{\mathrm{1}}{{x}+{y}}\right]\:=\:\mathrm{37} \\ $$$$\frac{\mathrm{1}}{{y}+{z}}+\frac{\mathrm{1}}{{z}+{x}}+\frac{\mathrm{1}}{{x}+{y}}\:=\:\frac{\mathrm{37}}{\mathrm{2022}} \\ $$ Commented by…
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Question Number 175411 by Rasheed.Sindhi last updated on 29/Aug/22 $$ \\ $$$$\mathrm{7}+\mathrm{67}+\mathrm{667}+\mathrm{6667}+…..\left({n}\:{terms}\right)=? \\ $$$$ \\ $$ Commented by infinityaction last updated on 30/Aug/22 $$\left(\mathrm{6}+\mathrm{1}\right)+\left(\mathrm{66}+\mathrm{1}\right)+\left(\mathrm{666}+\mathrm{1}\right)+…\left({n}\:{terms}\right) \\…
Question Number 175409 by henderson last updated on 29/Aug/22 $$\mathrm{exercise} \\ $$Consider a polygon with an odd number 𝗻 of vertices. We connect any 3…
Question Number 175407 by Stephan last updated on 29/Aug/22 $$\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\underline{\mathrm{Trouver}\:\mathrm{la}\:\mathrm{somme}\:\mathrm{de}\:\mathrm{S}_{{n}} }\:\: \\ $$$$\:\:\:\mathrm{Si}\:\:\:\:\:\:{S}_{{n}} =\mathrm{1}+\mathrm{11}+\mathrm{111}+…+\mathrm{1111}…\mathrm{111}\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 175396 by Shrinava last updated on 29/Aug/22 Answered by mahdipoor last updated on 29/Aug/22 $${x}+{y}^{\mathrm{2}} \sqrt{\frac{\mathrm{2}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }}\geqslant{y}+\sqrt{\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }{\mathrm{2}}}\:\:\:\Leftrightarrow \\ $$$$\left({x}+{y}^{\mathrm{2}} \sqrt{\frac{\mathrm{2}}{{x}^{\mathrm{2}}…
Question Number 175402 by Linton last updated on 29/Aug/22 $${solve}\:{for}\:{x} \\ $$$${x}_{{n}+\mathrm{1}} ={rx}_{{n}} \left(\mathrm{1}−{x}_{{n}} \right) \\ $$ Commented by a.lgnaoui last updated on 31/Aug/22 $${x}_{\mathrm{1}}…