Question Number 175399 by Engr_Jidda last updated on 29/Aug/22 $${if}\:\left({x}+\mathrm{1}\right)^{\mathrm{4}} \sqrt{\mathrm{4}}={x}+\mathrm{1}\:\:{find}\:{x} \\ $$ Commented by Frix last updated on 29/Aug/22 $$\left({x}+\mathrm{1}\right)^{\mathrm{4}} ×\sqrt{\mathrm{4}}\:\mathrm{or}\:\left({x}+\mathrm{1}\right)×\sqrt[{\mathrm{4}}]{\mathrm{4}}? \\ $$ Commented…
Question Number 175393 by Engr_Jidda last updated on 29/Aug/22 $${if}\:\left({x}+\mathrm{1}\right)_{\sqrt{\mathrm{4}}} ^{\mathrm{4}} ={x}+\mathrm{1}\:\:{find}\:{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 175373 by infinityaction last updated on 28/Aug/22 $$\:\:\mathrm{if}\:\:\:\:{x}^{\mathrm{6}} \:+\:{y}^{\mathrm{6}} \:=\:\mathrm{9} \\ $$$$\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{4}} \:+\:{y}^{\mathrm{4}} \:=\:\mathrm{5} \\ $$$$\:\mathrm{then}\:\:\:\:{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} \:=? \\ $$ Answered by mr…
Question Number 175375 by Linton last updated on 28/Aug/22 Answered by mr W last updated on 28/Aug/22 $${g}_{{n}+\mathrm{1}} −\mathrm{3}{g}_{{n}} +\mathrm{2}{g}_{{n}−\mathrm{1}} =\mathrm{0} \\ $$$${r}^{\mathrm{2}} −\mathrm{3}{r}+\mathrm{2}=\mathrm{0} \\…
Question Number 175374 by MikeH last updated on 28/Aug/22 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\underset{{i}\:=\:\mathrm{1}} {\overset{{n}} {\sum}}\frac{{i}+{j}}{{i}^{\mathrm{2}} +{j}^{\mathrm{2}} }−\left(\frac{\pi}{\mathrm{2}}+\:\mathrm{ln}\:\mathrm{2}\right){n}\:+\:\mathrm{ln}\:{n}\right)\:=\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 175333 by mnjuly1970 last updated on 27/Aug/22 $$ \\ $$$$\:\:\:{solve}\:\left({x}\:\in\:\mathbb{R}\:\right). \\ $$$$ \\ $$$$\:\:\lfloor\:\frac{\:\mathrm{2}^{\:{x}} \:+\mathrm{1}}{\mathrm{3}}\:\rfloor\:+\:\lfloor\:\mathrm{4}^{\:\frac{{x}}{\mathrm{2}}} \:\rfloor\:=\:\mathrm{4} \\ $$$$\:\:\:\:−−−−−−\: \\ $$ Answered by mr…
Question Number 109754 by joki last updated on 25/Aug/20 $$\mathrm{1}.{specify}\:{value}\:{absolute}\:{x}\:{if}\:? \\ $$$$ \\ $$$${b}.\mid\mathrm{2}{x}+\mathrm{3}\mid+{x}−\mathrm{3}=\mathrm{0} \\ $$$$ \\ $$ Answered by Her_Majesty last updated on 25/Aug/20…
Question Number 175284 by zzzrot last updated on 26/Aug/22 Answered by MJS_new last updated on 26/Aug/22 $$\frac{\mathrm{92}{x}+\mathrm{89}{y}}{{x}+{y}}=\mathrm{91} \\ $$$$\mathrm{92}{x}+\mathrm{89}{y}=\mathrm{91}{x}+\mathrm{91}{y} \\ $$$${x}=\mathrm{2}{y} \\ $$$$\frac{{x}}{{y}}=\mathrm{2} \\ $$…
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Question Number 44200 by Tawa1 last updated on 23/Sep/18 Commented by MJS last updated on 23/Sep/18 $${A} \\ $$$${term}\mathrm{1}×{term}\mathrm{2}=\mathrm{0}\:\Leftrightarrow\:{term}\mathrm{1}=\mathrm{0}\:\vee\:{term}\mathrm{2}=\mathrm{0} \\ $$$$\mathrm{e}^{{x}} −\mathrm{e}^{\pi} =\mathrm{0}\:\Rightarrow\:{x}=\pi \\ $$$$\mathrm{e}^{{x}}…