Question Number 109004 by Don08q last updated on 20/Aug/20 $$\overset{} {\:}\:\:{Solve}\:\:\:\:\mid\mathrm{3}{x}+\mathrm{5}\mid\:=\:\mid\mathrm{4}{x}−\mathrm{3}\mid \\ $$$$\:\:\:{where}\:{x}\:\in\:\mathbb{R} \\ $$$$ \\ $$ Answered by bemath last updated on 20/Aug/20 $$\Rightarrow\:\left(\mathrm{3}{x}+\mathrm{5}+\mathrm{4}{x}−\mathrm{3}\right)\left(\mathrm{3}{x}+\mathrm{5}−\mathrm{4}{x}+\mathrm{3}\right)=\mathrm{0}…
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Question Number 174538 by infinityaction last updated on 03/Aug/22 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{and} \\ $$$$\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:“\mathrm{x}''\:\mathrm{if} \\ $$$$\mathrm{x}+\mathrm{y}+\mathrm{z}\:=\:\mathrm{6},\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} \:=\:\mathrm{18}, \\ $$$$\mathrm{for}\:\mathrm{real}\:\mathrm{values}\:\mathrm{of}\:“\mathrm{x},\mathrm{y}\:\mathrm{and}\:\mathrm{z}'' \\ $$ Commented by JDamian last…
Question Number 174533 by mnjuly1970 last updated on 03/Aug/22 Answered by behi834171 last updated on 03/Aug/22 $$\boldsymbol{{x}}^{\mathrm{2}} =\mathrm{2}\boldsymbol{{x}}+\mathrm{1}\Rightarrow\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{2}\boldsymbol{{x}}−\mathrm{1}=\mathrm{0}\Rightarrow\begin{cases}{\boldsymbol{\alpha}+\boldsymbol{\beta}=\mathrm{2}}\\{\boldsymbol{\alpha}.\boldsymbol{\beta}=−\mathrm{1}}\end{cases} \\ $$$$\boldsymbol{{x}}^{\mathrm{3}} =\mathrm{2}\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{x}}=\mathrm{5}\boldsymbol{{x}}+\mathrm{2} \\ $$$$\boldsymbol{{x}}^{\mathrm{4}}…
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Question Number 108984 by bemath last updated on 20/Aug/20 $$\:\:\:\underset{\approx} {\mathcal{B}}{e}\underset{\approx} {\mathcal{M}}{at}\underset{\approx} {{h}} \\ $$$$\left(\mathrm{1}\right)\underset{{n}\:=\:\mathrm{1}} {\overset{\mathrm{100}} {\sum}}\left[\:\frac{\mathrm{2}}{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{1}}\:\right]\:? \\ $$$$\left(\mathrm{2}\right)\:\frac{\mathrm{2}}{\mathrm{4}.\mathrm{9}}\:+\:\frac{\mathrm{2}}{\mathrm{9}.\mathrm{14}}\:+\:\frac{\mathrm{2}}{\mathrm{14}.\mathrm{19}}\:+\:…\:+\:\frac{\mathrm{2}}{\mathrm{49}.\mathrm{54}}\:? \\ $$$$\left(\mathrm{3}\right)\:{Given}\:{a}\:{quadratic}\:{equation} \\ $$$${x}^{\mathrm{2}} \left(\underset{{i}\:=\:\mathrm{1}}…
Question Number 43449 by ajfour last updated on 10/Sep/18 Answered by MJS last updated on 10/Sep/18 $${y}={ax}^{\mathrm{3}} +{bx}^{\mathrm{2}} +{cx}+{d} \\ $$$${y}'=\mathrm{3}{ax}^{\mathrm{2}} +\mathrm{2}{bx}+{c} \\ $$$${P}=\begin{pmatrix}{−\mathrm{1}}\\{\mathrm{2}}\end{pmatrix}\:\:{Q}=\begin{pmatrix}{\mathrm{3}}\\{−\mathrm{1}}\end{pmatrix} \\…
Question Number 174512 by ahdal last updated on 03/Aug/22 $${how}\:{many}\:{integer}\:{a},{b}\in{z}^{+} \\ $$$${a}^{\mathrm{5}} −{b}^{\mathrm{5}} =\mathrm{10}\left({b}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{9} \\ $$$$ \\ $$ Answered by MJS_new last updated on…
Question Number 108967 by bobhans last updated on 20/Aug/20 $$\:\:\overset{\bigstar} {{b}}\overset{\bigstar} {{o}}\overset{\bigstar} {{b}}\overset{\sim} {{h}}\overset{\sim} {{a}}\overset{\sim} {{n}}\overset{\sim} {{s}} \\ $$$$\mathrm{1}+\frac{\mathrm{4}}{\mathrm{11}}+\frac{\mathrm{9}}{\mathrm{121}}+\frac{\mathrm{16}}{\mathrm{1331}}+\frac{\mathrm{25}}{\mathrm{14641}}+… \\ $$ Answered by john santu…
Question Number 43416 by peter frank last updated on 10/Sep/18 Commented by peter frank last updated on 15/Sep/18 $${help} \\ $$ Terms of Service Privacy…