Question Number 109369 by I want to learn more last updated on 23/Aug/20 Answered by floor(10²Eta[1]) last updated on 23/Aug/20 $$\left(\mathrm{x}+\mathrm{y}+\mathrm{z}\right)^{\mathrm{2}} =\mathrm{4}=\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} +\mathrm{2}\left(\mathrm{xy}+\mathrm{xz}+\mathrm{yz}\right)…
Question Number 174879 by mnjuly1970 last updated on 13/Aug/22 $$ \\ $$$$\:\:\:\boldsymbol{\mathrm{Q}}\::\:\left(\boldsymbol{{an}}\:\:\mathscr{E}\:\boldsymbol{{lementary}}\:\boldsymbol{{to}}\:\boldsymbol{{abstract}}\:\boldsymbol{{algebra}}\:\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\boldsymbol{{prove}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\:\boldsymbol{{order}}\:\:\boldsymbol{{of}}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\boldsymbol{{an}}\:\:\boldsymbol{{element}}\:\:\boldsymbol{{in}}''\:\boldsymbol{{quotient}}\:\boldsymbol{{group}}\:''\:\left(\mathbb{Q}\:,\:\oplus\right)/\left(\mathbb{Z}\:,\:\oplus\right)\:\boldsymbol{{is}}\:\boldsymbol{{finite}}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\boldsymbol{{Notice}}:\:\:\left(\mathbb{Q}\:,\:\oplus\right)/\left(\mathbb{Z}\:,\:\oplus\right)\:=\:\left\{\:\frac{\boldsymbol{{a}}}{\boldsymbol{{b}}}\:+\:\mathbb{Z}\:\mid\:\:\boldsymbol{{a}},\boldsymbol{{b}}\:\in\:\mathbb{Z}\:,\:\boldsymbol{{b}}\:\neq\mathrm{0}\:\right\}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\succ\:\boldsymbol{{Source}}:\:\boldsymbol{{John}}\:\boldsymbol{{B}}\:.\boldsymbol{{F}}\:\boldsymbol{{raleigh}}\:\boldsymbol{{book}}\:\prec\:\:\:\: \\ $$$$ \\ $$ Commented…
Question Number 43804 by vuckintv last updated on 15/Sep/18 $${solve}\:{for}\:\epsilon \\ $$$$ \\ $$$${s}\left(\mathrm{1}−\alpha\right)=\left(\mathrm{1}−\epsilon\right)\sigma{T}^{\mathrm{4}} \\ $$ Answered by MJS last updated on 16/Sep/18 $$\frac{{s}\left(\mathrm{1}−\alpha\right)}{\sigma{T}^{\mathrm{4}} }=\mathrm{1}−\epsilon…
Question Number 174859 by Shrinava last updated on 12/Aug/22 Commented by Frix last updated on 12/Aug/22 $$\frac{{a}}{{b}}={k}\:\Leftrightarrow\:{a}={bk}\:\mathrm{etc}.\:\Rightarrow\:{a}+\mathrm{2}{c}+\mathrm{3}{e}=\left({b}+\mathrm{2}{d}+\mathrm{3}{f}\right){k} \\ $$$$\mathrm{answer}\:\mathrm{is}\:{k} \\ $$ Answered by behi834171 last…
Question Number 109307 by john santu last updated on 22/Aug/20 Answered by mr W last updated on 22/Aug/20 $${x}^{\mathrm{2}} +\mathrm{2}{yz}−\mathrm{2}\left({y}+{z}\right)=\mathrm{82} \\ $$$${y}^{\mathrm{2}} +\mathrm{2}{zx}−\mathrm{2}\left({z}+{x}\right)=\mathrm{83} \\ $$$${z}^{\mathrm{2}}…
Question Number 174837 by mnjuly1970 last updated on 12/Aug/22 $$ \\ $$$$\:\:\:\:\:{sin}\left({A}\right)+\:{sin}\left({B}\:\right)+\:{sin}\left({C}\right)\leqslant\:\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\succ\:\:\:{Solution}\:\prec\:\:\:\:\:\:\left(\:{A}+{B}\:+{C}\:=\pi\:\right) \\ $$$$\:\:\:\:\:\:{l}.{h}.{s}\:=\:\mathrm{2}{sin}\left(\frac{{A}+{B}}{\mathrm{2}}\:\right){cos}\left(\frac{{A}−{B}}{\mathrm{2}}\right)+\mathrm{2}{sin}\left(\frac{{C}}{\mathrm{2}}\right){cos}\left(\frac{{C}}{\mathrm{2}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{2}{cos}\:\left(\frac{{C}}{\mathrm{2}}\right)\left\{\mathrm{2}{cos}\frac{{A}}{\mathrm{2}}\:.{cos}\left(\frac{{B}}{\mathrm{2}}\:\right)\right\} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{4}{cos}\left(\frac{{A}}{\mathrm{2}}\right).{cos}\left(\frac{{B}}{\mathrm{2}}\right).{cos}\left(\frac{{C}}{\mathrm{2}}\right)\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:{l}.{h}.{s}\:\underset{{post}} {\overset{{previoue}} {\leqslant}}\:\mathrm{4}\:\left(\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{8}}\:\right)=\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}} \\…
Question Number 43759 by ajfour last updated on 15/Sep/18 Answered by MrW3 last updated on 15/Sep/18 $${eqn}.\:{of}\:{line}: \\ $$$${x}=\frac{{y}}{{m}}+{a} \\ $$$${b}^{\mathrm{2}} {y}={x}\left({x}^{\mathrm{2}} −{a}^{\mathrm{2}} \right) \\…
Question Number 43756 by ajfour last updated on 15/Sep/18 $$\:\:\boldsymbol{{x}}^{\mathrm{3}} +\boldsymbol{{px}}+\boldsymbol{{q}}\:=\:\mathrm{0} \\ $$$$\boldsymbol{{If}}\:\boldsymbol{{equation}}\:\boldsymbol{{has}}\:\boldsymbol{{all}}\:\boldsymbol{{its}}\:\boldsymbol{{roots}} \\ $$$$\boldsymbol{{real}},\:\boldsymbol{{find}}\:\boldsymbol{{them}}. \\ $$ Answered by ajfour last updated on 15/Sep/18 $$\:\:{A}\:{poor}\:{self}\:{attempt}\::…
Question Number 43757 by Rauny last updated on 15/Sep/18 $$\mathrm{Probably}\:\mathrm{if}\:{x}^{{n}} ={Am}\:\left(\frac{{a}}{{b}}\pi\right),\:{x}={e}^{\frac{\mathrm{2}{k}+{a}}{{bn}}{i}\pi} \\ $$$$\mathrm{about}\:\mathrm{0}<\left({k}\in\mathbb{N}\cup\left\{\mathrm{0}\right\}\right)<\left({n}\in\mathbb{N}\right)\:\mathrm{and}\:{b}\neq\mathrm{0}. \\ $$$$\mathrm{p}.\mathrm{s}.\:{Am}\:\left(\mathrm{0}°\right)=\mathrm{1},\:{Am}\:\left(\mathrm{90}°\right)={i}\:\mathrm{etc}., \\ $$$$\mathrm{and}\:{s}°=\frac{\pi}{\mathrm{180}}{s}\:\mathrm{rad}\left(\mathrm{ians}\right)=\frac{\pi}{\mathrm{180}}{s}. \\ $$ Terms of Service Privacy Policy Contact:…
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