Question Number 176095 by Shrinava last updated on 12/Sep/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{the}\:\mathrm{following}\:\mathrm{relationship}\:\mathrm{holds}: \\ $$$$\mathrm{an}_{\boldsymbol{\mathrm{a}}} \:\geqslant\:\left(\mathrm{s}\:\left(\mathrm{b}\:+\:\mathrm{c}\right)\:−\:\mathrm{2bc}\right)\:\mathrm{cos}\:\frac{\mathrm{A}}{\mathrm{2}} \\ $$ Commented by a.lgnaoui last updated on 12/Sep/22 $$ \\ $$$$\mathrm{n}_{\mathrm{a}}…
Question Number 45014 by peter frank last updated on 07/Oct/18 $$\mathrm{6}\boldsymbol{\div}\mathrm{2}\left(\mathrm{1}+\mathrm{2}\right)?\:\mathrm{which}\:\boldsymbol{\mathrm{ans}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{correct}}\:\boldsymbol{\mathrm{between}}\:\mathrm{1}\boldsymbol{\mathrm{or}}\:\mathrm{9} \\ $$$$\boldsymbol{\mathrm{why}}\:\boldsymbol{\mathrm{do}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{look}}\:\boldsymbol{\mathrm{at}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{mobile}}\:\boldsymbol{\mathrm{phone}}\:\boldsymbol{\mathrm{calculator}}\:\boldsymbol{\mathrm{is}}\:\mathrm{9}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{when}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{check}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{scientific}}\:\boldsymbol{\mathrm{calculator}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{ans}}\:\boldsymbol{\mathrm{is}}\:\mathrm{1}.\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{want}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{clarify}}\:\boldsymbol{\mathrm{correctly}}\:\boldsymbol{\mathrm{where}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{are}}. \\ $$ Commented by peter frank last updated on 07/Oct/18 $$\mathrm{ajfour},\mathrm{tanmay},\mathrm{MJS},\mathrm{Mr}_{\:} \underset{\mathrm{3}}…
Question Number 176083 by Linton last updated on 11/Sep/22 $${can}\:{you}\:{find}\:{f}\left({x}\right)? \\ $$$${f}\left({x}\right)−{f}\left(\mathrm{1}−{x}\right)=\:{x} \\ $$ Answered by Rasheed.Sindhi last updated on 11/Sep/22 $${f}\left({x}\right)−{f}\left(\mathrm{1}−{x}\right)=\:{x}\:\:\:\:\:\:\:{f}\left({x}\right)? \\ $$$${Replace}\:{x}\:{by}\:\mathrm{1}−{x}: \\…
Question Number 110545 by peter frank last updated on 29/Aug/20 Commented by Dwaipayan Shikari last updated on 29/Aug/20 $$\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{2}−\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}} \\ $$ Commented by Dwaipayan Shikari…
Question Number 176058 by Shrinava last updated on 11/Sep/22 $$\mathrm{22}^{\mathrm{22}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{hte}\:\mathrm{last}\:\mathrm{digit}? \\ $$ Answered by BaliramKumar last updated on 11/Sep/22 $$\mathrm{4} \\ $$ Commented…
Question Number 176037 by Shrinava last updated on 11/Sep/22 $$\mathrm{If}\:\:\:\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{a}\:+\:\mathrm{b}\right)\:=\:\mathrm{13} \\ $$$$\mathrm{Find}\:\:\:\mathrm{2a}\:+\:\mathrm{b}\:=\:? \\ $$ Commented by Rasheed.Sindhi last updated on 11/Sep/22 $$\mathrm{20} \\ $$ Answered…
Question Number 44965 by Tawa1 last updated on 06/Oct/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{series}:\:\:\:\:\frac{\mathrm{1}}{\mathrm{1}.\mathrm{2}.\mathrm{3}}\:+\:\frac{\mathrm{1}}{\mathrm{4}.\mathrm{5}.\mathrm{6}}\:+\:\frac{\mathrm{1}}{\mathrm{7}.\mathrm{8}.\mathrm{9}}\:\:+\:…\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 110490 by ManojMaity last updated on 29/Aug/20 $$ \\ $$$${e}^{\mathrm{i}\pi} \:=\:−\mathrm{1} \\ $$ Answered by nimnim last updated on 29/Aug/20 $$\mathrm{We}\:\mathrm{have},\:\:\:\mathrm{e}^{{i}\mathrm{x}} =\mathrm{cosx}+{i}\mathrm{sinx}\: \\…
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Question Number 110471 by abdullahquwatan last updated on 29/Aug/20 $$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{x}\:\mathrm{values} \\ $$$$\left({x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{9}\right)^{\frac{{x}−\mathrm{3}}{{x}−\mathrm{1}}} \:=\:\left({x}−\mathrm{3}\right)^{\left({x}−\mathrm{4}\right)} \\ $$ Answered by Rasheed.Sindhi last updated on 29/Aug/20 $$\left({x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{9}\right)^{\frac{{x}−\mathrm{3}}{{x}−\mathrm{1}}}…