Question Number 109147 by ajfour last updated on 21/Aug/20 $${The}\:{principal}\:{argument}\:{of} \\ $$$${z}=\mathrm{1}+\mathrm{cos}\:\left(\frac{\mathrm{6}\pi}{\mathrm{5}}\right)+{i}\mathrm{sin}\:\left(\frac{\mathrm{6}\pi}{\mathrm{5}}\right)\:\:\:{is}\:=\:? \\ $$ Answered by Dwaipayan Shikari last updated on 21/Aug/20 $$ \\ $$$${tan}\theta=\frac{{sin}\frac{\mathrm{6}\pi}{\mathrm{5}}}{\mathrm{1}+{cos}\frac{\mathrm{6}\pi}{\mathrm{5}}}={tan}\frac{\mathrm{3}\pi}{\mathrm{5}}…
Question Number 43608 by LYCON TRIX last updated on 12/Sep/18 $$\mathrm{MJS}\:\left[\:\:\mathrm{12}/\mathrm{9}/\mathrm{18}\:\right]\:\mathrm{Code}\:−\:\mathrm{43569}\: \\ $$$$\mathrm{I}\:\mathrm{solved}\:\mathrm{one}\:\mathrm{of}\:\mathrm{these}\:,\:\mathrm{where}\:\mathrm{and}\:\mathrm{how}\:\mathrm{do} \\ $$$$\mathrm{i}\:\mathrm{get}\:\mathrm{the}\:\mathrm{prize}\:?\: \\ $$$$\mathrm{the}\:\mathrm{google}+\:\mathrm{page}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{really}\:\mathrm{tell}. \\ $$$$\mathrm{i}\:\mathrm{cannot}\:\mathrm{see}\:\mathrm{where}\:\mathrm{to}\:\mathrm{send}\:\mathrm{my}\:\mathrm{solution}\: \\ $$$$\mathrm{and}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{see}\:\mathrm{any}\:\mathrm{guarantee}\:\mathrm{to}\:\mathrm{keep}\:\mathrm{my} \\ $$$$\mathrm{copyright}\: \\ $$$$\mathrm{LYCON}\:\mathrm{TRIX}\:−\:…
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Question Number 174674 by Shrinava last updated on 08/Aug/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{the}\:\mathrm{following}\:\mathrm{relationship}\:\mathrm{holds}: \\ $$$$\mathrm{a}^{\mathrm{4}} \:<\:\left(\mathrm{b}^{\mathrm{2}} \:+\:\mathrm{c}^{\mathrm{2}} \right)^{\mathrm{2}} \:+\:\mathrm{9R}^{\mathrm{4}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 174668 by Shrinava last updated on 07/Aug/22 Answered by behi834171 last updated on 08/Aug/22 $$\Sigma\boldsymbol{{secA}}\geqslant\mathrm{3}\sqrt[{\mathrm{3}}]{\Pi\boldsymbol{{secA}}}\geqslant\mathrm{3}\sqrt[{\mathrm{3}}]{\boldsymbol{{sec}}^{\mathrm{3}} \frac{\boldsymbol{\pi}}{\mathrm{3}}}=\mathrm{6} \\ $$$$\Sigma\boldsymbol{{cscA}}\geqslant\mathrm{3}\sqrt[{\mathrm{3}}]{\Pi\boldsymbol{{cscA}}}\geqslant\mathrm{3}\sqrt[{\mathrm{3}}]{\boldsymbol{{csc}}\frac{\boldsymbol{\pi}}{\mathrm{3}}}=\mathrm{2}\sqrt{\mathrm{3}} \\ $$$$\Rightarrow\boldsymbol{{LHS}}\geqslant\sqrt{\mathrm{3}}×\mathrm{6}+\mathrm{9}×\mathrm{2}\sqrt{\mathrm{3}}=\mathrm{24}\sqrt{\mathrm{3}}\:\:.\blacksquare \\ $$ Commented…
Question Number 43587 by peter frank last updated on 12/Sep/18 $${a}\:{and}\:{b}\:\:{are}\:{the}\:{digit}\:{in}\:{a}\:{four}\:{digit} \\ $$$${number}\:\mathrm{12}{ab}.{if}\:\mathrm{12}{ab}\:{is}\:{divisble}\:{by}\: \\ $$$$\mathrm{5}\:{and}\:\mathrm{9}\:.{find}\:{the}\:{sum}\:{of}\:{all}\:{possible} \\ $$$${value}\:{of}\:\:{a}. \\ $$ Answered by MrW3 last updated on…
Question Number 174655 by AgniMath last updated on 06/Aug/22 $$\mathrm{Factorize}\:{a}^{\mathrm{3}} \:−\:\mathrm{16}{a}\:−\:\mathrm{3} \\ $$ Answered by MJS_new last updated on 07/Aug/22 $$\mathrm{LOL}! \\ $$$${a}^{\mathrm{3}} −\mathrm{16}{a}−\mathrm{3}= \\…
Question Number 174654 by AgniMath last updated on 06/Aug/22 $$\mathrm{Factorize}\:{x}^{\mathrm{9}} \:+\:{x}^{\mathrm{7}} \:+\:\mathrm{1} \\ $$ Commented by Frix last updated on 07/Aug/22 $$\mathrm{this}\:\mathrm{polynome}\:\mathrm{is}\:\mathrm{prime}.\:\mathrm{it}\:\mathrm{has}\:\mathrm{got}\:\mathrm{no}\:\mathrm{zeros} \\ $$$$\mathrm{in}\:\mathbb{N},\:\mathbb{Z}\:\mathrm{or}\:\mathbb{Q} \\…
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Question Number 43574 by pieroo last updated on 12/Sep/18 $$\mathrm{Two}\:\mathrm{cyclists}\:\mathrm{Musa}\:\mathrm{and}\:\mathrm{Amadu}\:\mathrm{left}\:\mathrm{point}\:\mathrm{p}\:\mathrm{at}\:\mathrm{the}\: \\ $$$$\mathrm{same}\:\mathrm{time}\:\mathrm{in}\:\mathrm{opposite}\:\mathrm{directions}.\:\mathrm{If}\:\mathrm{their}\:\mathrm{speeds}\:\mathrm{are} \\ $$$$\mathrm{8}\:\mathrm{km}/\mathrm{h}\:\mathrm{and12}\:\mathrm{km}/\mathrm{h}\:\mathrm{respectively};\: \\ $$$$\mathrm{i}.\:\mathrm{how}\:\mathrm{will}\:\mathrm{it}\:\mathrm{take}\:\mathrm{them}\:\mathrm{to}\:\mathrm{be}\:\mathrm{40}\:\mathrm{km}\:\mathrm{apart}? \\ $$$$\mathrm{ii}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{covered}\:\mathrm{by}\:\mathrm{Musa}\:\mathrm{within} \\ $$$$\mathrm{the}\:\mathrm{time}\:\mathrm{in}\:\left(\mathrm{i}\right) \\ $$ Answered by $@ty@m…