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Category: Algebra

Q-a-n-is-an-arithmatic-sequence-a-first-term-and-d-difference-such-that-a-a-a-d-a-ad-find-a-n-no

Question Number 173926 by mnjuly1970 last updated on 21/Jul/22 $$ \\ $$$$\:\:\:\:\:{Q}: \\ $$$$\:\:\:\:\:\:\:{a}_{\:{n}\:} \:\:{is}\:{an}\:{arithmatic}\:{sequence}. \\ $$$$\:\:\:\:\:\:\:\:\:\:{a}\:\left(\:{first}\:{term}\right)\:{and}\:\:{d}\:\left({difference}\:\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:{such}\:{that}\:,\:\:{a}_{\:{a}} \:+\:{a}_{\:{d}} \:=\:{a}_{\:{ad}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{find}\:\:\::\:\:\:\:{a}_{\:{n}} \:\:=? \\…

prove-1-

Question Number 173917 by Michaelfaraday last updated on 21/Jul/22 $${prove}: \\ $$$$\left(−\mathrm{1}\right)! \\ $$ Commented by Frix last updated on 21/Jul/22 $$\mathrm{I}\:\mathrm{promise}\:\mathrm{to}\:\mathrm{prove}\:\left(−\mathrm{1}\right)!\:\mathrm{if}\:\mathrm{you}\:\mathrm{prove}\:\frac{\pi}{\mathrm{7}}. \\ $$ Commented…

If-10-6-2-5-3-2-2-a-b-then-a-b-

Question Number 173869 by mnjuly1970 last updated on 20/Jul/22 $$ \\ $$$$\:{If},\:\:\:\left(\:\frac{\sqrt{\mathrm{10}}\:+\sqrt{\mathrm{6}}+\mathrm{2}}{\:\sqrt{\mathrm{5}}\:−\sqrt{\mathrm{3}\:}\:+\:\sqrt{\mathrm{2}}}\:\right)^{\:\mathrm{2}} =\:{a}\:+\:\sqrt{{b}} \\ $$$$\:\:\:\:\:\:\:\:{then}.\:\:\:\:\:\:\:\:{a}\:\:,\:\:\:{b}\:=\:? \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$ Commented by infinityaction last updated on…

BeMath-If-x-4-x-2-11-5-find-the-value-of-x-1-x-1-1-3-x-1-x-1-1-3-

Question Number 108316 by bemath last updated on 16/Aug/20 $$\:\:\:\:\frac{\bigtriangledown\mathcal{B}{e}\mathcal{M}{ath}\bigtriangledown}{\bigtriangleup} \\ $$$${If}\:{x}^{\mathrm{4}} +{x}^{\mathrm{2}} \:=\:\frac{\mathrm{11}}{\mathrm{5}}\:,\:{find}\:{the}\:{value}\:{of} \\ $$$$\Omega\:=\:\sqrt[{\mathrm{3}}]{\frac{{x}+\mathrm{1}}{{x}−\mathrm{1}}}\:+\:\sqrt[{\mathrm{3}}]{\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}}\: \\ $$ Answered by bobhans last updated on 16/Aug/20…

Solve-q-4-40q-2-q-384-0-

Question Number 42776 by Tawa1 last updated on 02/Sep/18 $$\mathrm{Solve}:\:\:\:\:\:\mathrm{q}^{\mathrm{4}} \:−\:\mathrm{40q}^{\mathrm{2}} \:+\:\mathrm{q}\:+\:\mathrm{384}\:=\:\mathrm{0} \\ $$ Answered by MJS last updated on 02/Sep/18 $$\mathrm{I}\:\mathrm{found}\:\mathrm{no}\:\mathrm{useable}\:\mathrm{exact}\:\mathrm{solution} \\ $$$${q}_{\mathrm{1}} \approx−\mathrm{4}.\mathrm{95762}…