Question Number 42553 by bshahid010@gmail.com last updated on 27/Aug/18 Commented by Tinkutara last updated on 28/Aug/18 a Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173624 by mr W last updated on 15/Jul/22 $${find}\:{f}\left({x}\right)\:{such}\:{that}\:{f}'\left({x}\right)={f}^{−\mathrm{1}} \left({x}\right). \\ $$ Commented by infinityaction last updated on 15/Jul/22 $$\:\:\:{f}'\left({x}\right)\:=\:{f}^{−\mathrm{1}} \left({x}\right) \\ $$$$\:\:\:{f}\left\{{f}'\left({x}\right)\right\}\:=\:{x}\:\:\:\:,\:\:{f}\left({x}\right)\:\:\:=\:\:{ax}^{{b}}…
Question Number 173613 by mr W last updated on 14/Jul/22 $${if}\:{f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{2}, \\ $$$${solve}\:\underset{{n}\:{times}} {{f}\left({f}\left({f}\left({f}\left(…{f}\left({x}\right)\right)\right)\right)\right)}=\mathrm{0} \\ $$ Answered by mahdipoor last updated on 14/Jul/22 $${f}\left({x}\right)=\left({x}+\mathrm{2}\right)^{\mathrm{2}}…
Question Number 173609 by infinityaction last updated on 14/Jul/22 Commented by Tawa11 last updated on 15/Jul/22 $$\mathrm{Great}\:\mathrm{sirs} \\ $$ Commented by universe last updated on…
Question Number 173610 by AgniMath last updated on 14/Jul/22 Answered by okbruh123 last updated on 14/Jul/22 $$\boldsymbol{\mathrm{M}{ethod}}\:\mathrm{1}\:: \\ $$$${as}\:{far}\:{as}\:{i}\:{know},\:{this}\:{is}\:{problem}\:{of}\:{prmo}. \\ $$$${its}\:{objective}\:{exam},\:{so}\:{take}\:{any}\:{a},{b},{c}\:{following}\:\Sigma{a}=\mathrm{0} \\ $$$${let}'{s}\:{say}\:−\mathrm{3},+\mathrm{1},+\mathrm{2} \\ $$$${youll}\:{get}\:\frac{\mathrm{9}}{\mathrm{2}}+\frac{\mathrm{1}}{−\mathrm{6}}+\frac{\mathrm{4}}{−\mathrm{3}}=\frac{\mathrm{27}−\mathrm{1}−\mathrm{8}}{\mathrm{6}}=\mathrm{3}…
Question Number 42516 by Akashuac last updated on 27/Aug/18 $$\left(\mathrm{x}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{a}\right),\left(\mathrm{x}−\frac{\mathrm{5}}{\mathrm{2}}\mathrm{a}\right)=? \\ $$$$\mathrm{Solve}\:\mathrm{Please}. \\ $$ Commented by maxmathsup by imad last updated on 27/Aug/18 $$=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{2}{x}−{a}\right)\left(\mathrm{2}{x}−\mathrm{5}{a}\right)\:=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{4}{x}^{\mathrm{2}} \:−\mathrm{10}{ax}\:−\mathrm{2}{ax}\:+\mathrm{5}{a}^{\mathrm{2}}…
Question Number 42514 by jbm last updated on 27/Aug/18 $${calculate}\:\:{d}\left({x}!\right)/{dx}=\:? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 27/Aug/18 $${y}={x}! \\ $$$${y}={x}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}−\mathrm{3}\right)…\mathrm{1} \\ $$$${lny}={lnx}+{ln}\left({x}−\mathrm{1}\right)+{ln}\left({x}−\mathrm{2}\right)+…+\mathrm{1} \\…
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Question Number 42507 by maxmathsup by imad last updated on 26/Aug/18 $${let}\:{j}\:={e}^{\frac{{i}\mathrm{2}\pi}{\mathrm{3}}} \:\:\:{and}\:\:\:{p}\left({x}\right)\:=\left(\mathrm{1}+{xj}\right)^{{n}} \:−\left(\mathrm{1}−{xj}\right)^{{n}} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{roots}\:{of}\:{p}\left({x}\right)\:{and}\:{factorize}\:{inside}\:{C}\left[{x}\right]\:{p}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{decompose}\:{inside}\:{C}\left({x}\right)\:{the}\:{fration}\:{F}\left({x}\right)\:=\frac{\mathrm{1}}{{p}\left({x}\right)}\:. \\ $$ Commented by maxmathsup by imad…
Question Number 173572 by mnjuly1970 last updated on 13/Jul/22 $$\: \\ $$$$\:\:\mathrm{S}{olve}\:\:\:{equation} \\ $$$$ \\ $$$$\:\:\:\:\:\:\mathrm{2}\lfloor{x}\rfloor\:=\:\frac{{x}^{\:\mathrm{2}} }{\mathrm{2}}\:\:\:\:\:\:\:\:\:\left({x}\:\in\:\mathbb{R}\:\right) \\ $$$$ \\ $$ Answered by MJS_new last…