Question Number 173574 by mr W last updated on 13/Jul/22 $${solve}\:{for}\:{x}\in{R} \\ $$$$\frac{\mathrm{5}{x}−\mathrm{3}}{\mathrm{3}{x}−\mathrm{5}}={x}^{\mathrm{4}} \\ $$ Commented by kaivan.ahmadi last updated on 14/Jul/22 $$\Rightarrow\frac{\mathrm{3}{x}^{\mathrm{5}} −\mathrm{5}{x}^{\mathrm{4}} −\mathrm{5}{x}+\mathrm{3}}{\mathrm{3}{x}−\mathrm{5}}=\mathrm{0}…
Question Number 173556 by dragan91 last updated on 13/Jul/22 $$ \\ $$$$\mathrm{Solve}\:\mathrm{over}\:\mathrm{integer} \\ $$$$\mathrm{a}^{\mathrm{3}} +\mathrm{2a}^{\mathrm{2}} +\mathrm{3a}+\mathrm{4}=\mathrm{b}!+\mathrm{c}! \\ $$ Answered by Rasheed.Sindhi last updated on 14/Jul/22…
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Question Number 107999 by Don08q last updated on 13/Aug/20 Commented by udaythool last updated on 13/Aug/20 $$\Rightarrow\mathrm{4}{x}^{\mathrm{2}} +\mathrm{3}{xy}−{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\Rightarrow\left({x}+{y}\right)\left(\mathrm{4}{x}−{y}\right)=\mathrm{0} \\ $$$$\Rightarrow\mathrm{4}{x}={y};\:\:\:\left(\because\:{x}+{y}\neq\mathrm{0}\right) \\ $$$$\Rightarrow\mathrm{4}{x}^{\mathrm{2}}…