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Category: Algebra

Find-without-softs-5-3-10-x-sin2x-dx-

Question Number 173529 by Shrinava last updated on 13/Jul/22 $$\mathrm{Find}\:\mathrm{without}\:\mathrm{softs}:\:\:\:\Omega\:=\:\int_{\frac{\boldsymbol{\pi}}{\mathrm{5}}} ^{\:\frac{\mathrm{3}\boldsymbol{\pi}}{\mathrm{10}}} \:\frac{\mathrm{x}}{\mathrm{sin2x}}\:\mathrm{dx} \\ $$ Answered by Ar Brandon last updated on 13/Jul/22 $${I}=\int_{\frac{\pi}{\mathrm{5}}} ^{\frac{\mathrm{3}\pi}{\mathrm{10}}} \frac{{x}}{\mathrm{sin2}{x}}{dx}\:,\:{x}=\frac{\pi}{\mathrm{2}}−{u}\:\Rightarrow{I}=\int_{\frac{\pi}{\mathrm{5}}}…

Question-173535

Question Number 173535 by mnjuly1970 last updated on 13/Jul/22 Answered by mr W last updated on 13/Jul/22 $${in}\:{expansion}\:{of}\:\left({x}_{\mathrm{1}} +{x}_{\mathrm{2}} +{x}_{\mathrm{3}} +…+{x}_{{n}} \right)^{{m}} \\ $$$${the}\:{general}\:{term}\:{is}\:{x}_{\mathrm{1}} ^{{k}_{\mathrm{1}}…

Rewrite-cos6xcos-4x-as-a-sum-or-difference-

Question Number 107976 by anonymous last updated on 13/Aug/20 $${Rewrite}\:\mathrm{cos6}{x}\mathrm{cos}\:\mathrm{4}{x}\:{as}\:{a}\:{sum}\:{or} \\ $$$${difference} \\ $$ Answered by mathmax by abdo last updated on 13/Aug/20 $$\mathrm{cos}\left(\mathrm{4x}\right)\mathrm{cos}\left(\mathrm{6x}\right)\:=\frac{\mathrm{1}}{\mathrm{2}}\left\{\mathrm{cos}\left(\mathrm{10x}\right)\:+\mathrm{cos}\left(\mathrm{2x}\right)\right\} \\…

Question-173504

Question Number 173504 by AgniMath last updated on 12/Jul/22 Answered by behi834171 last updated on 12/Jul/22 $${A}=\sqrt{{x}}+\frac{\mathrm{1}}{\:\sqrt{{x}}}\Rightarrow{A}^{\mathrm{2}} ={x}+\frac{\mathrm{1}}{{x}}+\mathrm{2}=\mathrm{4}\Rightarrow{A}=\mathrm{2}\:\:.\:\:\blacksquare \\ $$ Commented by Rasheed.Sindhi last updated…

Find-without-any-software-x-5-x-1-5-x-2-sin-ln-x-5-x-dx-

Question Number 173500 by Shrinava last updated on 12/Jul/22 $$\mathrm{Find}\:\mathrm{without}\:\mathrm{any}\:\mathrm{software}: \\ $$$$\Omega\:=\:\int\:\left(\mathrm{x}\:+\:\frac{\mathrm{5}}{\mathrm{x}}\right)\left(\mathrm{1}\:−\:\frac{\mathrm{5}}{\mathrm{x}^{\mathrm{2}} }\right)\mathrm{sin}\left(\mathrm{ln}\left(\mathrm{x}\:+\:\frac{\mathrm{5}}{\mathrm{x}}\right)\right)\mathrm{dx} \\ $$ Answered by thfchristopher last updated on 12/Jul/22 $$\mathrm{Let}\:{u}={x}+\frac{\mathrm{5}}{{x}} \\ $$$${du}=\left(\mathrm{1}−\frac{\mathrm{5}}{{x}^{\mathrm{2}}…

Bonus-du-Mardi-12-07-2022-I-0-2-sin-2-x-1-cos-2-x-dx-J-0-2-dx-1-cos-2-x-I-0-2-2-1-cos-2-x-1-cos-2-x-dx-

Question Number 173497 by SIENSE last updated on 12/Jul/22 $$\:\:\: \\ $$$$\:\:{Bonus}\:{du}\:{Mardi}\:\mathrm{12}/\mathrm{07}/\mathrm{2022} \\ $$$$\:\:\:\:{I}=\:\:\int_{\mathrm{0}} ^{\frac{\Pi}{\mathrm{2}}} \:\frac{{sin}^{\mathrm{2}} \left({x}\right)}{\mathrm{1}+{cos}^{\mathrm{2}} \left({x}\right)}{dx}\:=\:? \\ $$$$\:\:\:\:\:\:\:\:\:\:{J}\:\:=\:\int_{\mathrm{0}} ^{\frac{\Pi}{\mathrm{2}}} \:\frac{{dx}}{\mathrm{1}+{cos}^{\mathrm{2}} \left({x}\right)} \\ $$$$\:{I}\:=\:\int_{\mathrm{0}}…

Question-173489

Question Number 173489 by AgniMath last updated on 12/Jul/22 Answered by Rasheed.Sindhi last updated on 12/Jul/22 $${x}+{y}+{z}=\mathrm{0}\:;\:\frac{{x}^{\mathrm{2}} }{{yz}}+\frac{{y}^{\mathrm{2}} }{{zx}}+\frac{{z}^{\mathrm{2}} }{{xy}}=? \\ $$$$\:\frac{{x}^{\mathrm{2}} }{{yz}}+\frac{{y}^{\mathrm{2}} }{{zx}}+\frac{{z}^{\mathrm{2}} }{{xy}}=\:\frac{{x}^{\mathrm{3}}…