Question Number 107947 by I want to learn more last updated on 13/Aug/20 Answered by mr W last updated on 13/Aug/20 $$\left.{a}\right) \\ $$$$\mathrm{10}!=\mathrm{3628800} \\…
Question Number 42408 by LYCON TRIX last updated on 25/Aug/18 $$\sqrt{{a}−\sqrt{{a}+{x}\:}}+\:\sqrt{{a}+\sqrt{{a}−{x}}\:}\:=\:\mathrm{2}{x} \\ $$$${Solve}\:{for}\:{x}\:{in}\:{terms}\:{of}\:{a} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 25/Aug/18 $${really}\:{excellent}\:{problem}…{searching}\:{way}\:{to}\:{solve} \\ $$…
Question Number 107945 by bemath last updated on 13/Aug/20 $$\:\:\:\:\:\:\frac{\circ\mathbb{B}{e}\mathbb{M}{ath}\circ}{\wedge\smile\wedge} \\ $$$$\:\:\:\begin{cases}{{x}^{\mathrm{4}} +\frac{\mathrm{1}}{{x}^{\mathrm{4}} }\:=\:\mathrm{23}}\\{{x}^{\mathrm{3}} −\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\:=\:?}\end{cases} \\ $$ Answered by $@y@m last updated on 13/Aug/20…
Question Number 173445 by AgniMath last updated on 11/Jul/22 Answered by Rasheed.Sindhi last updated on 11/Jul/22 $$\frac{{a}}{\mathrm{3}}=\frac{{a}+{b}}{\mathrm{4}}=\frac{{a}+{b}+{c}}{\mathrm{5}}=\frac{{a}+{b}+{c}+{d}}{\mathrm{6}}={k} \\ $$$${a}=\mathrm{3}{k} \\ $$$${a}+{b}=\mathrm{4}{k}\Rightarrow{b}=\mathrm{4}{k}−\mathrm{3}{k}={k} \\ $$$${a}+{b}+{c}=\mathrm{5}{k}\Rightarrow\mathrm{4}{k}+{c}=\mathrm{5}{k}\Rightarrow{c}={k} \\ $$$${a}+{b}+{c}+{d}=\mathrm{6}{k}\Rightarrow\mathrm{5}{k}+{d}=\mathrm{6}{k}\Rightarrow{d}={k}…
Question Number 42375 by Joel578 last updated on 24/Aug/18 $$\mathrm{Find}\:\mathrm{value}\:\mathrm{of}\:\:\alpha\:\mathrm{such}\:\mathrm{that}\:\mathrm{the}\:\mathrm{following}\:\mathrm{system} \\ $$$$\mathrm{has}\:\mathrm{infinite}\:\mathrm{many}\:\mathrm{solutions} \\ $$$$ \\ $$$${x}\:−\:\mathrm{3}{z}\:=\:−\mathrm{3} \\ $$$$−\mathrm{2}{x}\:−\:\alpha{y}\:+\:{z}\:=\:\mathrm{2} \\ $$$${x}\:+\:\mathrm{2}{y}\:+\:\alpha{z}\:=\:\mathrm{1} \\ $$ Commented by Joel578…
Question Number 173431 by mnjuly1970 last updated on 11/Jul/22 Commented by Rasheed.Sindhi last updated on 11/Jul/22 $$\left({a},{b}\right)=\left(\mathrm{10},\mathrm{13}\right),\left(\mathrm{13},\mathrm{10}\right); \\ $$$${n}=\mathrm{3197}=\mathrm{23}×\mathrm{139} \\ $$ Commented by mr W…
Question Number 173430 by dragan91 last updated on 11/Jul/22 Commented by Rasheed.Sindhi last updated on 11/Jul/22 $${a}=\mathrm{0},\:{b}={c}=\mathrm{2} \\ $$$${a}=−\mathrm{1},\left({b},{c}\right)=\left(\mathrm{0},\mathrm{1}\right),\left(\mathrm{1},\mathrm{0}\right),\left(\mathrm{1},\mathrm{1}\right) \\ $$ Commented by dragan91 last…
Question Number 173426 by Shrinava last updated on 11/Jul/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{the}\:\mathrm{following}\:\mathrm{relationship} \\ $$$$\mathrm{holds}: \\ $$$$\left(\mathrm{a}^{\mathrm{3}} +\mathrm{b}^{\mathrm{3}} +\mathrm{c}^{\mathrm{3}} \right)\left(\mathrm{h}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{3}} +\mathrm{h}_{\boldsymbol{\mathrm{b}}} ^{\mathrm{3}} +\mathrm{h}_{\boldsymbol{\mathrm{c}}} ^{\mathrm{3}} \right)\:\geqslant\:\mathrm{5832}\:\sqrt{\mathrm{3}}\:\mathrm{r}^{\mathrm{6}} \\ $$…
Question Number 173420 by AgniMath last updated on 11/Jul/22 Answered by Rasheed.Sindhi last updated on 11/Jul/22 $${x}+{y}+{z}=\mathrm{0}; \\ $$$$\frac{\mathrm{1}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{z}^{\mathrm{2}} }+\frac{\mathrm{1}}{{y}^{\mathrm{2}} +{z}^{\mathrm{2}} −{x}^{\mathrm{2}} }+\frac{\mathrm{1}}{{z}^{\mathrm{2}}…
Question Number 173421 by Shrinava last updated on 11/Jul/22 $$\mathrm{In}\:\mathrm{triangle}\:\:\mathrm{ABC},\:\mathrm{AD}\:\mathrm{is}\:\mathrm{the}\:\mathrm{bisector} \\ $$$$\mathrm{of}\:\:\angle\mathrm{A}\:\:\mathrm{meets}\:\:\mathrm{BC}\:\mathrm{at}\:\mathrm{D},\:\mathrm{if}\:\:\mathrm{2}\angle\mathrm{C}=\angle\mathrm{B} \\ $$$$\mathrm{and}\:\mathrm{AB}=\mathrm{DC}.\:\mathrm{Find}\:\angle\mathrm{BAC} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com