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Category: Algebra

If-x-2-2-2-3-2-1-3-then-prove-that-x-3-6x-2-6x-2-0-

Question Number 173152 by AgniMath last updated on 07/Jul/22 $$\mathrm{If}\:{x}\:=\:\mathrm{2}\:+\:\mathrm{2}^{\frac{\mathrm{2}}{\mathrm{3}}} \:+\:\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} \:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\: \\ $$$${x}^{\mathrm{3}} \:−\:\mathrm{6}{x}^{\mathrm{2}} \:+\:\mathrm{6}{x}\:−\:\mathrm{2}\:=\:\mathrm{0}. \\ $$ Answered by Frix last updated on 07/Jul/22…

Question-173121

Question Number 173121 by dragan91 last updated on 06/Jul/22 Commented by Rasheed.Sindhi last updated on 07/Jul/22 $${Someone}\:{plays}\:{with}\:{the}\:{forum} \\ $$$${like}\:{a}\:{child}!\:{S}/{he}\:{colours}\:{red}\:{to} \\ $$$${some}\:{purposeful}\:{posts}!\:{Perhaps} \\ $$$${he}\:{is}\:{actually}\:{child}! \\ $$…

Question-173123

Question Number 173123 by dragan91 last updated on 06/Jul/22 Commented by MJS_new last updated on 06/Jul/22 $$\mathrm{both}\:\mathrm{are}\:\mathrm{linear}\:\mathrm{for}\:{y} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{solve}\:\mathrm{to}\:\begin{cases}{{y}=\mathrm{term}\:\mathrm{A}}\\{{y}=\mathrm{term}\:\mathrm{B}}\end{cases} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{term}\:\mathrm{A}\:=\mathrm{term}\:\mathrm{B}\:\left(\mathrm{which}\:\mathrm{is}\:\mathrm{a}\:\mathrm{polynome}\right. \\ $$$$\:\:\:\:\:\mathrm{of}\:\mathrm{4}^{\mathrm{th}} \:\mathrm{degree} \\…

a-b-b-c-a-c-abc-a-b-c-

Question Number 173115 by dragan91 last updated on 06/Jul/22 $$\mathrm{a}+\mathrm{b}=\mathrm{b}+\mathrm{c}=\mathrm{a}+\mathrm{c}=\mathrm{abc} \\ $$$$\left(\mathrm{a},\mathrm{b},\mathrm{c}\right)=? \\ $$ Commented by kaivan.ahmadi last updated on 06/Jul/22 $${a}+{b}={b}+{c}\Rightarrow{a}={c} \\ $$$${a}+{b}={a}+{c}\Rightarrow{b}={c} \\…

x-1-x-5-x-5-1-x-5-

Question Number 42030 by Akashuac last updated on 17/Aug/18 $$\mathrm{x}+\frac{\mathrm{1}}{\mathrm{x}}=\mathrm{5}\:\:\:\:\mathrm{x}^{\mathrm{5}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{5}} }=? \\ $$ Commented by maxmathsup by imad last updated on 17/Aug/18 $${x}+\frac{\mathrm{1}}{{x}}=\mathrm{5}\:\Rightarrow\left({x}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{5}} \:=\mathrm{5}^{\mathrm{5}}…

if-a-b-c-2-a-b-2-c-2-a-2-b-c-2-0-then-prove-that-a-c-or-a-c-2b-

Question Number 42009 by 737954 last updated on 16/Aug/18 $$\mathrm{if}\:\left(\mathrm{a}+\mathrm{b}\omega+\mathrm{c}\omega^{\mathrm{2}} \right)+\left(\mathrm{a}\omega+\mathrm{b}\omega^{\mathrm{2}} +\mathrm{c}\right)^{\mathrm{2}} +\left(\mathrm{a}\omega^{\mathrm{2}} +\mathrm{b}+\mathrm{c}\omega\right)^{\mathrm{2}} =\mathrm{0} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\:\mathrm{a}=\mathrm{c}\:\:\mathrm{or}\:\:\:\mathrm{a}+\mathrm{c}=\mathrm{2b} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…

Solve-for-complex-numbers-x-2-3-y-2-5-x-y-2-8-10x-y-7-14i-

Question Number 173072 by Shrinava last updated on 06/Jul/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{complex}\:\mathrm{numbers}: \\ $$$$\begin{cases}{\frac{\mid\mathrm{x}\mid^{\mathrm{2}} }{\mathrm{3}}\:\:+\:\:\frac{\mid\mathrm{y}\mid^{\mathrm{2}} }{\mathrm{5}}\:\:=\:\:\frac{\mid\mathrm{x}\:+\:\mathrm{y}\mid^{\mathrm{2}} }{\mathrm{8}}}\\{\mathrm{10x}\:\:+\:\:\mathrm{y}\:\:=\:\:\mathrm{7}\:\:+\:\:\mathrm{14}\boldsymbol{\mathrm{i}}}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-173078

Question Number 173078 by AgniMath last updated on 06/Jul/22 Answered by som(math1967) last updated on 07/Jul/22 $$\boldsymbol{{let}}\:\boldsymbol{{b}}−\boldsymbol{{c}}=\boldsymbol{{x}}\:,\left(\boldsymbol{{a}}−\boldsymbol{{b}}\right)=\boldsymbol{{y}},\boldsymbol{{c}}−\boldsymbol{{a}}=\boldsymbol{{z}} \\ $$$$\therefore\:\boldsymbol{{x}}+\boldsymbol{{y}}+\boldsymbol{{z}}=\mathrm{0} \\ $$$$\left(\boldsymbol{{x}}+\boldsymbol{{y}}\right)^{\mathrm{2}} =\left(−\boldsymbol{{z}}\right)^{\mathrm{2}} \\ $$$$\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}}…