Question Number 173027 by Shrinava last updated on 05/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173024 by Shrinava last updated on 05/Jul/22 $$\mathrm{Find}\:\:\mathrm{A},\mathrm{B}\subset\mathbb{N}^{\ast} \\ $$$$\mathrm{Such}\:\mathrm{that}\:\:\mathrm{A}\cap\mathrm{B}=\varnothing\:,\:\mathrm{cardB}=\mathrm{cardA}+\mathrm{1}\geqslant\mathrm{8} \\ $$$$\mathrm{and}\:\:\underset{\boldsymbol{\mathrm{x}}\in\boldsymbol{\mathrm{A}}} {\sum}\:\mathrm{x}^{\mathrm{3}} \:=\:\underset{\boldsymbol{\mathrm{x}}\in\boldsymbol{\mathrm{B}}} {\sum}\:\mathrm{x}^{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 107486 by bemath last updated on 11/Aug/20 $$\:\:\:\:\:\:\nparallel\mathcal{B}{e}\mathcal{M}{ath}\nparallel \\ $$$$\frac{\mathrm{2}}{\mathrm{5}}+\frac{\mathrm{5}}{\mathrm{25}}+\frac{\mathrm{8}}{\mathrm{125}}+\frac{\mathrm{11}}{\mathrm{625}}+\frac{\mathrm{14}}{\mathrm{3125}}+…\:=\:? \\ $$ Commented by bemath last updated on 11/Aug/20 $${thank}\:{you}\:{all}.\:{cooll}.. \\ $$ Answered…
Question Number 107483 by john santu last updated on 11/Aug/20 $$\:\:\:\:\:\:\:\:\divideontimes\mathcal{JS}\divideontimes \\ $$$$\:\:\:\:\:\mid\mathrm{1}+\frac{\mathrm{1}}{{x}}\:\mid−\mid{x}−\mathrm{3}\mid\:>\:\mathrm{2}\: \\ $$$${find}\:{solution}\:{set}. \\ $$$$\left({A}\right)\:\mathrm{3}−\sqrt{\mathrm{10}}\:<\:{x}\:<\:\mathrm{2}−\sqrt{\mathrm{3}}\:;\:{x}\neq\mathrm{0} \\ $$$$\left({B}\right)\:\mathrm{3}−\sqrt{\mathrm{10}}\:<\:{x}\:<\:\mathrm{3}+\sqrt{\mathrm{10}}\:;\:{x}\neq\mathrm{0} \\ $$$$\left({C}\right)\:\mathrm{3}−\sqrt{\mathrm{10}}\:<\:{x}\:<\:\mathrm{2}+\sqrt{\mathrm{10}}\:;\:{x}\neq\mathrm{0} \\ $$$$\left({D}\right)\:\mathrm{2}+\sqrt{\mathrm{10}}\:<\:{x}\:<\:\mathrm{3}+\sqrt{\mathrm{10}}\:;\:{x}\neq\mathrm{0} \\ $$$$\left({E}\right)\:{none}\:{of}\:{these}\:…
Question Number 107484 by bemath last updated on 11/Aug/20 $$\:\:\:\:\:\nparallel\mathcal{B}{e}\mathcal{M}{ath}\nparallel \\ $$$$\sqrt{{x}+\sqrt{{x}+\sqrt{{x}+\sqrt{{x}+…}}}}\:=\:\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}…}}}} \\ $$$${x}=?\: \\ $$ Answered by john santu last updated on 11/Aug/20 $$\:\:\:\:\:\:\:\:\:\:\:\divideontimes\mathcal{JS}\divideontimes…
Question Number 173018 by dragan91 last updated on 04/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173008 by Mikenice last updated on 04/Jul/22 Answered by pnuvu last updated on 04/Jul/22 $$\frac{\mathrm{4}\left({x}^{\mathrm{2}} −{y}^{\mathrm{2}} \right)}{{x}−{y}}=\frac{\mathrm{4}\left({x}+{y}\right)\left({x}−{y}\right)}{{x}−{y}}=\mathrm{4}\left({x}+{y}\right) \\ $$ Answered by Skabetix last…
Question Number 173004 by Mikenice last updated on 04/Jul/22 Commented by MJS_new last updated on 04/Jul/22 $$\mathrm{the}\:\mathrm{sequence}\:\mathrm{is}\:\mathrm{not}\:\mathrm{clear} \\ $$$$\mathrm{10}+\mathrm{6}=\mathrm{16}+\mathrm{6}=\mathrm{22}+\mathrm{6}… \\ $$$$\mathrm{but}\:\mathrm{9}+\mathrm{16}=\mathrm{25}+\mathrm{16}=\mathrm{31}?\:\mathrm{or}\:\mathrm{3}^{\mathrm{2}} =\mathrm{9},\:\mathrm{5}^{\mathrm{2}} =\mathrm{25},\:\mathrm{7}^{\mathrm{2}} =\mathrm{49}? \\…
Question Number 173000 by Mikenice last updated on 04/Jul/22 Commented by MJS_new last updated on 04/Jul/22 $$\mathrm{2}^{{x}+{y}} =\mathrm{6}\:\Rightarrow\:{x}+{y}=\frac{\mathrm{ln}\:\mathrm{6}}{\mathrm{ln}\:\mathrm{2}}={a} \\ $$$$\mathrm{3}^{{x}+{y}} =\mathrm{4}\:\Rightarrow\:{x}+{y}=\frac{\mathrm{ln}\:\mathrm{4}}{\mathrm{ln}\:\mathrm{3}}={b} \\ $$$${a}\neq{b}\:\Rightarrow\:\mathrm{no}\:\mathrm{solution} \\ $$…
Question Number 173001 by Mikenice last updated on 04/Jul/22 Answered by pnuvu last updated on 04/Jul/22 $${abc}=\mathrm{6} \\ $$$$\left({a},{b},{c}\right)=\left(\mathrm{1},\mathrm{2},\mathrm{3}\right) \\ $$ Answered by MJS_new last…