Question Number 41866 by Tawa1 last updated on 14/Aug/18 Answered by MJS last updated on 14/Aug/18 $${m}=\mathrm{4}{d} \\ $$$${b}={d}+\mathrm{6} \\ $$$${b}:{d}:{e}=\mathrm{5}:\mathrm{3}:\mathrm{2} \\ $$$${e}=\frac{\mathrm{2}}{\mathrm{3}}{d} \\ $$$$…
Question Number 41860 by SmNayon11 last updated on 14/Aug/18 $$\left(\mathrm{1},\mathrm{2},\mathrm{3},……..\mathrm{100}\right){are}\:{given}\:{number} \\ $$$${find}\:{the}\:{value}\:{of}\:\Sigma\left(\mathrm{1}×\mathrm{2}\right) \\ $$ Commented by MJS last updated on 14/Aug/18 $$\mathrm{sorry}\:\mathrm{but}\:“\Sigma\left(\mathrm{1}×\mathrm{2}\right)''\:\mathrm{isn}'\mathrm{t}\:\mathrm{proper}\:\mathrm{math}\:\mathrm{language} \\ $$$$\mathrm{what}\:\mathrm{does}\:\mathrm{it}\:\mathrm{mean}\:“\mathrm{sum}\:\mathrm{of}\:\mathrm{one}\:\mathrm{multiplicated}\:\mathrm{with}\:\mathrm{two}''? \\…
Question Number 172929 by pete last updated on 03/Jul/22 $$\mathrm{A}\:\mathrm{man}\:\mathrm{purchased}\:\mathrm{180}\:\mathrm{copies}\:\mathrm{of}\:\mathrm{a}\:\mathrm{book} \\ $$$$\mathrm{at}\:\$\mathrm{250}.\mathrm{00}\:\boldsymbol{\mathrm{each}}.\:\mathrm{He}\:\mathrm{sold}\:{y}\:\mathrm{copies}\:\mathrm{at}\:\$\mathrm{300}.\mathrm{00} \\ $$$$\mathrm{each}\:\mathrm{and}\:\mathrm{the}\:\mathrm{rest}\:\mathrm{at}\:\mathrm{a}\:\mathrm{discount}\:\mathrm{of}\:\mathrm{5}\:\mathrm{cents}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{dollar}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cost}\:\mathrm{price}.\:\mathrm{If}\:\mathrm{he}\:\mathrm{made}\:\mathrm{a}\:\mathrm{profit} \\ $$$$\mathrm{of}\:\$\mathrm{7},\mathrm{125}.\mathrm{00},\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{y}? \\ $$ Commented by Rasheed.Sindhi last updated…
Question Number 107385 by bemath last updated on 10/Aug/20 $$\:\:\:\:\:\iddots\mathcal{B}{e}\mathcal{M}{ath}\iddots \\ $$$${Given}\:\mathrm{6}{x}^{\mathrm{2}} −\mathrm{6}{px}+\mathrm{14}{p}−\mathrm{2}=\mathrm{0} \\ $$$${has}\:{the}\:{roots}\:{are}\:\:{u}\:\&\:{v}\:{where}\:{u},{v}\:\notin\mathbb{Z} \\ $$$${If}\:{u},{v}\:\geqslant\:\mathrm{1}\:,\:{then}\:{the}\:{value}\:{of}\:\mid{u}−{v}\mid\:. \\ $$$$\left({a}\right)\mathrm{14}\:\:\:\:\:\left({b}\right)\mathrm{15}\:\:\:\:\:\left({c}\right)\mathrm{16}\:\:\:\:\:\left({d}\right)\mathrm{17}\:\:\:\left({e}\right)\:\mathrm{18} \\ $$ Commented by Her_Majesty last…
Question Number 172912 by mnjuly1970 last updated on 03/Jul/22 Answered by FongXD last updated on 03/Jul/22 $$\bigstar\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{f}\left(\mathrm{x}+\mathrm{4n}\right) \\ $$$$\Rightarrow\:\mathrm{f}'\left(\mathrm{x}\right)=\mathrm{f}'\left(\mathrm{x}+\mathrm{4n}\right) \\ $$$$\bigstar\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{f}\left(\mathrm{x}+\mathrm{1}\right)+\mathrm{f}\left(\mathrm{3x}+\mathrm{2}\right) \\ $$$$\Rightarrow\:\mathrm{f}'\left(\mathrm{x}\right)=\mathrm{f}'\left(\mathrm{x}+\mathrm{1}\right)+\mathrm{3f}'\left(\mathrm{3x}+\mathrm{2}\right) \\ $$$$\bullet\:\mathrm{x}=\mathrm{1},\:\mathrm{f}'\left(\mathrm{1}\right)=\mathrm{f}'\left(\mathrm{2}\right)+\mathrm{3f}'\left(\mathrm{5}\right)=\mathrm{f}'\left(\mathrm{2}\right)+\mathrm{3f}'\left(\mathrm{1}\right)…
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Question Number 107352 by bemath last updated on 10/Aug/20 $$\:\:\:\:\:\:\:\:\circledcirc\mathcal{B}{e}\mathcal{M}{ath}\circledcirc \\ $$$$\left(\mathrm{1}\right)\mathrm{1}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{4}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{6}}}+…=? \\ $$$$\left(\mathrm{2}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\mathrm{1}+\mathrm{sin}\:{x}\right)^{\frac{\mathrm{1}}{{x}}} \:? \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 41813 by Tawa1 last updated on 13/Aug/18 $$\mathrm{Any}\:\mathrm{workings}\:\mathrm{for}\:\mathrm{this}\:\mathrm{simultaneous}\:\mathrm{equation}\:? \\ $$$$\:\:\:\:\:\:\:\:\mathrm{x}^{\mathrm{x}} \:+\:\mathrm{y}^{\mathrm{y}} \:=\:\mathrm{31}\:\:……..\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:+\:\mathrm{y}\:=\:\mathrm{5}\:\:\:\:\:\:……..\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 13/Aug/18…
Question Number 41798 by Tawa1 last updated on 12/Aug/18 $$\mathrm{Solve}:\:\:\:\mathrm{x}^{\mathrm{3}} \:−\:\mathrm{3x}\:+\:\mathrm{4}\:=\:\mathrm{0} \\ $$$$\mathrm{how}\:\mathrm{can}\:\mathrm{i}\:\mathrm{know}\:\mathrm{when}\:\mathrm{to}\:\mathrm{use}:\:\:\:\:\mathrm{let}\:\mathrm{x}\:=\:\mathrm{y}\:+\:\frac{\mathrm{1}}{\mathrm{y}} \\ $$ Commented by math khazana by abdo last updated on 13/Aug/18…
Question Number 172862 by dragan91 last updated on 02/Jul/22 Commented by MJS_new last updated on 02/Jul/22 $$\mathrm{obviously}\:{x}={y}={z}=\mathrm{2} \\ $$$$\left(\mathrm{and}\:{x}={y}={z}=−\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$ Commented by Mikenice last…