Question Number 172787 by mnjuly1970 last updated on 01/Jul/22 $$ \\ $$$$\:\:\:\mathrm{In}\:\:\mathrm{A}\overset{\Delta} {\mathrm{B}C}\:\:,\:\mathrm{prove}\:\:\mathrm{that}\: \\ $$$$\:{sin}\left(\frac{\mathrm{A}}{\mathrm{2}}\right).{sin}\left(\frac{\mathrm{B}}{\mathrm{2}}\right).{sin}\left(\frac{\mathrm{C}}{\mathrm{2}}\right)\:\leqslant\:\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\:\:\:−−−−−−−− \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 41710 by Tawa1 last updated on 11/Aug/18 $$\mathrm{Factorize}:\:\:\mathrm{60x}^{\mathrm{3}} \mathrm{y}\:+\:\mathrm{115x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \:−\:\mathrm{120xy}^{\mathrm{3}} \\ $$ Answered by alex041103 last updated on 11/Aug/18 $$\mathrm{60x}^{\mathrm{3}} \mathrm{y}\:+\:\mathrm{115x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}}…
Question Number 107242 by mnjuly1970 last updated on 09/Aug/20 $$\:\:\:\:\:…{question}… \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{prove}\:{that}: \\ $$$$\:{if}\:\:{a},{b},{c}\in\mathbb{R}^{+} \:{then}: \\ $$$$\:\:\:\:\:\clubsuit\:\:\:\sqrt{{a}}\:+\sqrt{{b}}+\sqrt{{c}}>\:\sqrt{{a}+{b}+{c}}\:\clubsuit\: \\ $$$$\:\:\:\:\:\:\:….{sincerly}\:{yours}… \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:…\:\mathscr{M}.\mathscr{N}… \\ $$$$\:\: \\ $$…
Question Number 172775 by Shrinava last updated on 01/Jul/22 Answered by mahdipoor last updated on 02/Jul/22 $${get}\:{side}\:{of}\:{square}\:=\:{a} \\ $$$${and}\:{cotB}+{cotC}={b} \\ $$$$, \\ $$$${BQ}={MQ}.{cotB}={a}.{cotB} \\ $$$${PC}={NP}.{cotC}={a}.{cotC}…
Question Number 107234 by O Predador last updated on 09/Aug/20 Answered by floor(10²Eta[1]) last updated on 09/Aug/20 $$\mathrm{x}^{\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}}}} +\frac{\mathrm{7}}{\mathrm{x}^{\frac{\sqrt{\mathrm{7}}}{\mathrm{7}}} }=\mathrm{8} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}}}=\frac{\sqrt{\mathrm{7}}}{\mathrm{7}} \\ $$$$\mathrm{x}^{\frac{\mathrm{1}}{\:\sqrt{\mathrm{7}}}} =\mathrm{y}\Rightarrow\mathrm{y}+\frac{\mathrm{7}}{\mathrm{y}}=\mathrm{8}\Rightarrow\mathrm{y}^{\mathrm{2}}…
Question Number 172744 by Adilali last updated on 30/Jun/22 Answered by aleks041103 last updated on 30/Jun/22 $${obv}.\:{x}=\mathrm{0}\:{is}\:{a}\:{solution}. \\ $$$${if}\:{x}<\mathrm{0}\rightarrow{obv}.\:{no}\:{soln}. \\ $$$${if}\:{x}>\mathrm{0}: \\ $$$$\mathrm{2}^{{x}} {ln}\left({x}\right)={ln}\left(\mathrm{2}\right)+{ln}\left({x}\right) \\…
Question Number 172709 by fabyfb last updated on 30/Jun/22 Answered by Mathspace last updated on 30/Jun/22 $${L}\left({f}\left({x}\right)\right)=\int_{\mathrm{0}} ^{\infty} \:\:{f}\left({t}\right){e}^{−{xt}} {dt} \\ $$$$=\int_{\mathrm{0}} ^{\infty} \:\frac{{e}^{−{xt}} }{{t}^{\mathrm{2}}…
Question Number 172704 by mathlove last updated on 30/Jun/22 $${if}\:\left({x}^{\mathrm{2}} +\mathrm{11}{x}\right)+\frac{\mathrm{5}}{\left({x}^{\mathrm{2}} −{x}\right)}=−\mathrm{30} \\ $$$${then}\:{faind}:\left({x}+\mathrm{2}\right)\left({x}+\mathrm{3}\right)=? \\ $$ Answered by mahdipoor last updated on 30/Jun/22 $$\Rightarrow{x}\neq\mathrm{0},\mathrm{1}\:\&\:{A}=\left({x}+\mathrm{2}\right)\left({x}+\mathrm{3}\right)={x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{6}…
Question Number 172703 by mathlove last updated on 30/Jun/22 $${if}\:\sqrt{\frac{{x}}{{y}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}=\sqrt{\frac{{y}}{{x}}}\:{and}\:\mathrm{2}{x}^{\mathrm{2}} =\mathrm{7} \\ $$$${thin}\:{faind}\:{volue}\:{of}\:{x}\centerdot{y}=? \\ $$ Answered by Rasheed.Sindhi last updated on 30/Jun/22 $$\sqrt{\frac{{x}}{{y}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}=\sqrt{\frac{{y}}{{x}}}\:{and}\:\mathrm{2}{x}^{\mathrm{2}} =\mathrm{7}\:;\:{xy}=? \\…
Question Number 172694 by Shrinava last updated on 30/Jun/22 $$\mathrm{I}-\mathrm{incenter} \\ $$$$\mathrm{AB}\:,\:\mathrm{BE}\:,\:\mathrm{CF}-\mathrm{internal}\:\mathrm{bisectors}\:\mathrm{in}\:\bigtriangleup\mathrm{ABC} \\ $$$$\mathrm{Prove}\:\mathrm{that} \\ $$$$\mathrm{8}\:\leqslant\:\frac{\mathrm{AI}}{\mathrm{DI}}\:\centerdot\:\frac{\mathrm{BI}}{\mathrm{EI}}\:\centerdot\:\frac{\mathrm{CI}}{\mathrm{FI}}\:\leqslant\:\frac{\mathrm{4R}}{\mathrm{r}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com