Question Number 106774 by bemath last updated on 07/Aug/20 $$\:\:\:\:\overset{@\mathrm{bemath}@} {\:} \\ $$$$\:\left(\mathrm{1}\right)\:\:\:\:\mathrm{3}^{{x}} \:+\:\mathrm{3}^{\sqrt{{x}}\:} =\:\mathrm{90}.\:\mathrm{find}\:{x}\:?\: \\ $$$$\:\:\left(\mathrm{2}\right)\:\mathrm{x}\:\frac{\mathrm{dy}}{\mathrm{dx}}−\left(\mathrm{1}+\mathrm{x}\right)\mathrm{y}\:=\:\mathrm{xy}^{\mathrm{2}} \\ $$ Answered by john santu last updated…
Question Number 106745 by qwertyu last updated on 06/Aug/20 Commented by Her_Majesty last updated on 06/Aug/20 $${always}\:{the}\:{same}\:{questions}… \\ $$$${how}\:{do}\:{you}\:{define}\:“{x}!''? \\ $$ Commented by qwertyu last…
Question Number 172282 by BaliramSingh last updated on 25/Jun/22 $${Find}\:{the}\:{all}\:{valid}\:{value}\:{of}\:\:\:{x} \\ $$$${x}^{\mathrm{2}} \:−\:\sqrt{\mathrm{4}+{x}}\:=\:\mathrm{4} \\ $$ Answered by dumitrel last updated on 25/Jun/22 $${x}^{\mathrm{2}} −\mathrm{4}\geqslant\mathrm{0};{x}+\mathrm{4}\geqslant\mathrm{0} \\…
Question Number 172268 by Mikenice last updated on 25/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 106730 by I want to learn more last updated on 06/Aug/20 Answered by Dwaipayan Shikari last updated on 06/Aug/20 $$\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{n}^{\mathrm{2}} \left({n}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 172267 by Mikenice last updated on 25/Jun/22 Answered by mr W last updated on 25/Jun/22 $$\left({a}\right) \\ $$$${T}={mg}\:\mathrm{sin}\:\theta \\ $$$$\left({b}\right) \\ $$$${N}={mg}\:\mathrm{cos}\:\theta \\…
Question Number 172264 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\mathrm{log}_{\mathrm{2}} \left(\mathrm{log}_{\mathrm{8}} {x}\right)=\mathrm{log}_{\mathrm{8}} \left(\mathrm{log}_{\mathrm{2}} {x}\right)\:\:\:\: \\ $$$$\mathrm{log}_{\mathrm{2}} \left(\frac{\mathrm{log}_{\mathrm{2}} {x}\:}{\mathrm{log}_{\mathrm{2}}…
Question Number 172261 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)^{\mathrm{2016}} \left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)\left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)\right\}^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:\right)^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} \right\}^{\mathrm{2016}} \\…
Question Number 106727 by Algoritm last updated on 06/Aug/20 Answered by Her_Majesty last updated on 06/Aug/20 $${x}=\mathrm{1}\wedge{y}=\mathrm{0}\:\Rightarrow\:{min}\:\left({x}+{y}\right)\:=\mathrm{1} \\ $$ Commented by Her_Majesty last updated on…
Question Number 172259 by mr W last updated on 25/Jun/22 $${solve} \\ $$$${x}^{{x}} =\mathrm{3}^{\frac{\mathrm{1}}{{x}}} \\ $$ Answered by mr W last updated on 25/Jun/22 $${x}\mathrm{ln}\:{x}=\frac{\mathrm{ln}\:\mathrm{3}}{{x}}…