Question Number 172262 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}}\:=\sqrt{{n}}\:>\mathrm{0} \\ $$$$\left(\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}}\:\right)^{\mathrm{3}} =\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\ $$$$\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}\:=\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\ $$$$\mathrm{3}\sqrt{{n}}=\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\…
Question Number 172244 by mr W last updated on 24/Jun/22 $${solve}\: \\ $$$$\mathrm{2}^{{x}^{\mathrm{2}} } −\mathrm{40}{x}=\mathrm{0} \\ $$$$ \\ $$$$\left[{Q}#\mathrm{172086}\:{reposted}\right] \\ $$ Commented by mr W…
Question Number 41167 by Cheyboy last updated on 02/Aug/18 $${The}\:{LCM}\:{and}\:{the}\:{GCF}\:{of}\:{three} \\ $$$${intergers}\:{are}\:\mathrm{180}\:{and}\:\mathrm{3}\:{respectively}. \\ $$$${Two}\:{numbers}\:{are}\:\mathrm{45}\:{and}\:\mathrm{60}. \\ $$$${What}\:{is}\:{the}\:{third}\:{number} \\ $$ Answered by MJS last updated on 02/Aug/18…
Question Number 41160 by behi83417@gmail.com last updated on 02/Aug/18 Commented by behi83417@gmail.com last updated on 02/Aug/18 $${solve}\:{for}\:{x}\neq{y}\neq{z}. \\ $$ Commented by MJS last updated on…
Question Number 172214 by Shrinava last updated on 24/Jun/22 $$\mathrm{If}\:\:\mathrm{in}\:\:\bigtriangleup\mathrm{ABC}\:,\:\mathrm{m}\left(\sphericalangle\mathrm{BAC}\right)>\mathrm{90}°\:\:\mathrm{then}: \\ $$$$\mathrm{cosA}\:+\:\mathrm{cosB}\:\mathrm{cosC}\:=\:\frac{\mathrm{F}}{\mathrm{aR}} \\ $$ Commented by mr W last updated on 24/Jun/22 $${please}\:{check}!\:{maybe}\:{you}\:{meant} \\ $$$$\mathrm{cosA}\:+\:\mathrm{cosB}\:\mathrm{cosC}\:=\:\frac{{aR}}{{F}}…
Question Number 106659 by Ar Brandon last updated on 06/Aug/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{terms}\:\mathrm{has}\:\mathrm{the}\:\mathrm{polynomial}; \\ $$$$\left(\mathrm{X}_{\mathrm{1}} +\mathrm{2X}_{\mathrm{2}} −\mathrm{X}_{\mathrm{3}} +\mathrm{34}\right)^{\mathrm{10}} \:? \\ $$ Answered by bobhans last updated on…
Question Number 106655 by Algoritm last updated on 06/Aug/20 Commented by prakash jain last updated on 06/Aug/20 $${x}_{\mathrm{1}} ={kx}_{\mathrm{2}} \\ $$$${k}^{\mathrm{9}} =−\mathrm{1}\Rightarrow{k}=−\mathrm{1}\left({e}^{{i}\mathrm{2}\pi{m}/\mathrm{9}} \right)\:\:\left({m}=\mathrm{0}..\mathrm{8}\right)\:\left({I}\right) \\ $$$${k}^{\mathrm{15}}…
Question Number 172184 by Mikenice last updated on 23/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 172186 by Mikenice last updated on 23/Jun/22 Commented by kaivan.ahmadi last updated on 24/Jun/22 $${A}={x}^{{x}^{{x}^{….} } } \\ $$$${li}\underset{{x}\rightarrow\mathrm{1}} {{m}}\frac{{lnxA}}{{x}^{\mathrm{2}} −\mathrm{1}}\:\:\:\overset{{Hop}} {=}\:\:\:{li}\underset{{x}\rightarrow\mathrm{1}} {{m}}\:\frac{\frac{\mathrm{1}}{{x}}{A}+{lnx}.{A}'}{\mathrm{2}{x}}=…
Question Number 172182 by Mikenice last updated on 23/Jun/22 $${solve} \\ $$$$\mathrm{6}^{{x}} +\mathrm{6}^{{y}} =\mathrm{42} \\ $$$${x}+{y}=\mathrm{3} \\ $$ Answered by mr W last updated on…