Question Number 172009 by Mikenice last updated on 23/Jun/22 $${solve}: \\ $$$${if}\:{x}=\mathrm{2017},{y}=\mathrm{2018}\:{and}\:{z}=\mathrm{2019},\: \\ $$$${find}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} −{xy}−{yz}−{zx} \\ $$ Answered by som(math1967) last updated on…
Question Number 172007 by Mikenice last updated on 23/Jun/22 $${solve}: \\ $$$${x}\sqrt{{x}^{\mathrm{2}} +\mathrm{4}}\:−{x}^{\mathrm{2}} =−\mathrm{6} \\ $$ Answered by puissant last updated on 23/Jun/22 $${x}\sqrt{{x}^{\mathrm{2}} +\mathrm{4}}\:=\:{x}^{\mathrm{2}}…
Question Number 172006 by Mikenice last updated on 23/Jun/22 $${solve}: \\ $$$$\sqrt{{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{2}}\:−\sqrt{{x}^{\mathrm{2}} +\mathrm{5}\:}\:=\mathrm{1} \\ $$ Answered by Rasheed.Sindhi last updated on 24/Jun/22 $$\sqrt{{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{2}}\:−\sqrt{{x}^{\mathrm{2}}…
Question Number 171999 by Mikenice last updated on 23/Jun/22 $${resolve}: \\ $$$$\frac{\mathrm{4}\left({x}−\mathrm{4}\right)}{{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{3}}\:{into}\:{partial}\:{fraction} \\ $$ Answered by Rasheed.Sindhi last updated on 23/Jun/22 $$\frac{\mathrm{4}\left({x}−\mathrm{4}\right)}{\left({x}−\mathrm{3}\right)\left({x}+\mathrm{1}\right)}=\frac{{a}}{{x}−\mathrm{3}}+\frac{{b}}{{x}+\mathrm{1}} \\ $$$$\mathrm{4}\left({x}−\mathrm{4}\right)={a}\left({x}+\mathrm{1}\right)+{b}\left({x}−\mathrm{3}\right)…
Question Number 171995 by Mikenice last updated on 23/Jun/22 $${solve}: \\ $$$$\left(\frac{{x}}{\mathrm{12}}\right)^{{log}_{\sqrt{\mathrm{3}}} \:{x}} =\left(\frac{{x}}{\mathrm{18}}\right)^{{log}_{\sqrt{\mathrm{2}}} {x}} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 171989 by Mikenice last updated on 22/Jun/22 $${solve}:\:{A}\:{two}\:{digit}\:{number}\:{is}\:{such} \\ $$$${that}\:\mathrm{4}\:{times}\:{the}\:{unit}\:{digit}\:{is}\:\mathrm{5}\:{more}\: \\ $$$${than}\:{thrice}\:{the}\:{ten}\:{digit}.\:{when}\:{the} \\ $$$${digit}\:{are}\:{reversed}\:{the}\:{number}\:{is}\: \\ $$$${increase}\:{by}\:{nine},\:{find}\:{the}\:{number} \\ $$$$ \\ $$ Answered by Rasheed.Sindhi…
Question Number 171988 by Mikenice last updated on 22/Jun/22 $${solve}: \\ $$$${x}^{\mathrm{2}} =\mathrm{16}^{{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171985 by Shrinava last updated on 22/Jun/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:,\:\mathrm{O}-\mathrm{circumcentr}\:,\:\mathrm{G}-\mathrm{centroid}. \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{OG}\parallel\mathrm{BC}\Leftrightarrow\left(\mathrm{b}^{\mathrm{2}} −\mathrm{c}^{\mathrm{2}} \right)^{\mathrm{2}} =\mathrm{4a}^{\mathrm{2}} \left(\mathrm{9R}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} −\mathrm{b}^{\mathrm{2}} −\mathrm{c}^{\mathrm{2}} \right) \\ $$ Terms…
Question Number 171986 by Shrinava last updated on 22/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171972 by mathlove last updated on 22/Jun/22 Answered by mr W last updated on 22/Jun/22 $${x}\neq\mathrm{1}\:\Rightarrow{x}−\mathrm{1}\neq\mathrm{0} \\ $$$$\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{4}} +{x}^{\mathrm{3}} +{x}^{\mathrm{2}} +{x}+\mathrm{1}\right)=\mathrm{0} \\ $$$${x}^{\mathrm{5}}…