Question Number 171979 by Shrinava last updated on 22/Jun/22 Answered by puissant last updated on 23/Jun/22 $${sin}\theta+{icos}\theta=\frac{−{i}}{−{i}}\bullet{sin}\theta+{icos}\theta \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\frac{−{isin}\theta+{cos}\theta}{−{i}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:−\frac{{e}^{−{i}\theta} }{{i}} \\ $$ Terms…
Question Number 171966 by Shrinava last updated on 22/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171954 by Shrinava last updated on 22/Jun/22 $$\mathrm{Find}\:\mathrm{without}\:\mathrm{softs}: \\ $$$$\int_{\frac{\mathrm{1}}{\boldsymbol{\mathrm{e}}}} ^{\:\boldsymbol{\mathrm{e}}} \:\frac{\mathrm{dx}}{\left(\mathrm{1}\:+\:\mathrm{x}^{\mathrm{2}} \right)\left(\mathrm{1}\:+\:\mathrm{x}\:\mathrm{log}^{\mathrm{7}} \:\mathrm{x}\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171944 by infinityaction last updated on 22/Jun/22 $${if} \\ $$$${a}+{b}+{c}=\mathrm{2196} \\ $$$$\sqrt[{\mathrm{3}}]{{a}}\:+{b}+{c}=\mathrm{2076} \\ $$$${a}+\sqrt[{\mathrm{3}}]{{b}}\:+{c}=\mathrm{1860} \\ $$$${a}+{b}+\sqrt[{\mathrm{3}}]{{c}}\:=\mathrm{480},\:{determine}\:{the}\:{value}\:{of} \\ $$$${a}^{\frac{\mathrm{2}}{\mathrm{3}}} +{b}^{\frac{\mathrm{2}}{\mathrm{3}}} +{c}^{\frac{\mathrm{2}}{\mathrm{3}}} ,\:{if}\:{a},{b},{c}\:{are}\:{all}\:{integer}. \\ $$…
Question Number 171941 by infinityaction last updated on 22/Jun/22 $$\sqrt{{a}}+\sqrt{{b}}=\sqrt{\mathrm{2009}}.\:{find}\:{a}\:{and}\:{b}. \\ $$ Commented by infinityaction last updated on 22/Jun/22 $${repost}\:{of}\:{que}.\:{no}\:\mathrm{171866} \\ $$ Commented by infinityaction…
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Question Number 171927 by Mikenice last updated on 21/Jun/22 $${solve}: \\ $$$${x}^{\sqrt{{x}}} =\left(\sqrt[{\mathrm{4}}]{{x}}\right)^{\mathrm{1}+\sqrt{{x}}} \\ $$ Answered by aleks041103 last updated on 22/Jun/22 $${x}^{\sqrt{{x}}} ={x}^{\frac{\mathrm{1}+\sqrt{{x}}}{\mathrm{4}}} \\…
Question Number 171921 by Mikenice last updated on 21/Jun/22 $$\frac{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} −\mathrm{9}}}{\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{3}}}=\mathrm{3},\:{find}\:{x} \\ $$ Answered by FelipeLz last updated on 22/Jun/22 $$\frac{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} −\mathrm{9}}}{\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{3}}}\:=\:\mathrm{3} \\ $$$$\frac{{x}^{\mathrm{2}} −\mathrm{9}}{\:{x}+\mathrm{3}}\:=\:\mathrm{3}^{\mathrm{3}}…
Question Number 171922 by Mikenice last updated on 21/Jun/22 $${if}\:\alpha\:{and}\:\beta\:{are}\:{the}\:{positive}\:{roots}\:{of}\:{the}\:{eqn} \\ $$$${x}^{\mathrm{2}} +{px}+{q}=\mathrm{0},\:{find}\:{the}\:{sum}\:{M}=\sqrt[{\mathrm{4}}]{\alpha}\:+\sqrt[{\mathrm{4}}]{\beta} \\ $$ Commented by kaivan.ahmadi last updated on 22/Jun/22 $${we}\:{now}\:{S}=\alpha+\beta=−{p}\:,\:{P}=\alpha\beta={q} \\ $$$${M}^{\mathrm{2}}…
Question Number 171919 by Mikenice last updated on 21/Jun/22 $${if} \\ $$$${a}+{b}+{c}=\mathrm{2196} \\ $$$$\sqrt[{\mathrm{3}}]{{a}}\:+{b}+{c}=\mathrm{2076} \\ $$$${a}+\sqrt[{\mathrm{3}}]{{b}}\:+{c}=\mathrm{1860} \\ $$$${a}+{b}+\sqrt[{\mathrm{3}}]{{c}}\:=\mathrm{480},\:{determine}\:{the}\:{value}\:{of} \\ $$$${a}^{\frac{\mathrm{2}}{\mathrm{3}}} +{b}^{\frac{\mathrm{2}}{\mathrm{3}}} +{c}^{\frac{\mathrm{2}}{\mathrm{3}}} ,\:{if}\:{a},{b},{c}\:{are}\:{all}\:{integer}. \\ $$…