Question Number 171772 by Mikenice last updated on 20/Jun/22 $${solve}: \\ $$$${x}^{{x}} =\mathrm{27}{x}^{\mathrm{2}} .\:{find}\:{x} \\ $$ Commented by mr W last updated on 21/Jun/22 $${you}\:{can}\:{only}\:{approximate}.…
Question Number 106239 by chichi last updated on 03/Aug/20 $$ \\ $$$$\mathrm{A}\:\mathrm{rope}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10cm}\:\mathrm{is}\:\mathrm{used}\:\mathrm{to}\:\mathrm{form}\:\mathrm{as} \\ $$$$\mathrm{ector}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{35cm}\:\mathrm{What}\:\mathrm{ish} \\ $$$$\mathrm{te}\:\mathrm{size}\:\mathrm{of}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sector} \\ $$ Answered by prakash jain last updated on…
Question Number 171771 by Mikenice last updated on 20/Jun/22 $${solve}: \\ $$$$\mathrm{2}^{{x}} =\mathrm{4}{x}.\:{find}\:{x} \\ $$ Answered by mathocean1 last updated on 20/Jun/22 $${S}_{\mathbb{R}} =\left\{\mathrm{4}\right\} \\…
Question Number 106233 by malwaan last updated on 03/Aug/20 $$\left({x}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({x}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{yz} \\ $$$$\left({y}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({y}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{xz} \\ $$$$\left({z}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({z}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{xy} \\ $$$${x}\:\geqslant\:\mathrm{1}\:;\:{y}\:\geqslant\:\mathrm{1}\:;\:{z}\:\geqslant\:\mathrm{1} \\ $$$${prove}\:{that}\:\:\:{x}\:=\:{y}\:=\:{z}\:= \\…
Question Number 171757 by Mikenice last updated on 20/Jun/22 $${find}\:\left(\mathrm{2}{n}\right)! \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171756 by Mikenice last updated on 20/Jun/22 $${solve}\:{for}\:{real}\:{numbers}: \\ $$$$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{7} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\sqrt{\mathrm{2}}\:{z}\left({x}+{y}\right) \\ $$ Commented by mr…
Question Number 171759 by Mikenice last updated on 20/Jun/22 $${solve}: \\ $$$$\left(\sqrt{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{6}}\:+\:\sqrt{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{4}}\:\right)^{\frac{{x}}{\mathrm{2}}} \:+\:\left(\sqrt{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{6}}\:−\:\sqrt{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{4}}\right)^{\frac{{x}}{\mathrm{2}}} \:=\:\mathrm{2}^{\frac{{x}+\mathrm{2}}{\mathrm{4}}} .\:{find}\:{x} \\ $$ Answered by Rasheed.Sindhi last…
Question Number 171755 by Mikenice last updated on 20/Jun/22 $${make}\:{R}\:{the}\:{subject}\:{of}\:{the}\:{formula}\:{if} \\ $$$${P}=\frac{{M}}{\mathrm{5}}\left({X}+{R}^{\mathrm{2}} \right)+\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171749 by Mikenice last updated on 20/Jun/22 $${if}\:{a}+{b}+{c}=\mathrm{3},{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} =\mathrm{5},{a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} =\mathrm{27}.\:{find}\:{a}^{\mathrm{100}} +{b}^{\mathrm{100}} +{c}^{\mathrm{100}} . \\ $$ Answered by floor(10²Eta[1]) last…
Question Number 171745 by Shrinava last updated on 20/Jun/22 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{in}\:\mathrm{any}\:\mathrm{triangle}\:\:\mathrm{ABC}\:, \\ $$$$\mathrm{with}\:\mathrm{area}\:\:\mathrm{F}\:\:\mathrm{holds}: \\ $$$$\mathrm{7}\left(\mathrm{m}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{2}} \:+\:\mathrm{m}_{\boldsymbol{\mathrm{b}}} ^{\mathrm{2}} \:+\:\mathrm{m}_{\boldsymbol{\mathrm{c}}} ^{\mathrm{2}} \right)\:\geqslant\:\mathrm{36F}\:+\:\mathrm{3}\:\underset{\boldsymbol{\mathrm{cyc}}} {\sum}\left(\mathrm{a}−\mathrm{m}_{\boldsymbol{\mathrm{a}}} ^{\mathrm{2}} \right) \\ $$…