Question Number 171296 by dragan91 last updated on 11/Jun/22 Commented by Rasheed.Sindhi last updated on 13/Jun/22 $${For}\:{x}>\mathrm{5}\:\:\:\:{xy}^{\mathrm{3}} +{xy}^{\mathrm{3}} +\mathrm{2022}<\mathrm{20}{x}!+\mathrm{22}{y}! \\ $$$${For}\:{y}>\mathrm{5}\:\:\:\:{xy}^{\mathrm{3}} +{xy}^{\mathrm{3}} +\mathrm{2022}<\mathrm{20}{x}!+\mathrm{22}{y}! \\ $$$${this}\:{means}\:{we}'{ve}\:{to}\:{search}\:{values}…
Question Number 171289 by mathlove last updated on 11/Jun/22 $$\left({x},{y}\right)\in{R}\:\:\:{x}^{\mathrm{2}} −{xy}−\mathrm{12}{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\frac{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{4}{y}^{\mathrm{2}} }{{xy}}=? \\ $$ Answered by mr W last updated on…
Question Number 40222 by byaw last updated on 17/Jul/18 $$\mathrm{please}\:\mathrm{help} \\ $$$$\mathrm{Kate}\:\mathrm{was}\:\mathrm{given}\:\mathrm{602}.\mathrm{00}\:\mathrm{dollas}\:\mathrm{for}\: \\ $$$$\mathrm{shopping}.\:\mathrm{She}\:\mathrm{spent}\:\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{on}\:\mathrm{chocolate} \\ $$$$\mathrm{and}\:\mathrm{later}\:\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{on}\:\mathrm{goods}.\:\mathrm{How}\:\mathrm{much} \\ $$$$\mathrm{money}\:\mathrm{was}\:\mathrm{left}? \\ $$ Answered by Joel578 last updated…
Question Number 171244 by mathlove last updated on 11/Jun/22 $$\frac{{x}}{{y}}+\frac{{y}}{{x}}=\frac{\mathrm{26}}{\mathrm{5}} \\ $$$$\frac{{x}+{y}}{{x}−{y}}=? \\ $$$$\frac{}{} \\ $$ Commented by infinityaction last updated on 11/Jun/22 $$\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Solve-the-following-system-of-equations-x-3-y-x-3-y-2-2x-2-y-2-x-2-y-3-xy-3-30-x-2-y-xy-x-y-xy-2-11-
Question Number 105704 by 1549442205PVT last updated on 31/Jul/20 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{following}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equations}: \\ $$$$\begin{cases}{\mathrm{x}^{\mathrm{3}} \mathrm{y}+\mathrm{x}^{\mathrm{3}} \mathrm{y}^{\mathrm{2}} +\mathrm{2x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} +\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{3}} +\mathrm{xy}^{\mathrm{3}} =\mathrm{30}}\\{\mathrm{x}^{\mathrm{2}} \mathrm{y}+\mathrm{xy}+\mathrm{x}+\mathrm{y}+\mathrm{xy}^{\mathrm{2}} =\mathrm{11}}\end{cases} \\ $$ Commented…
Question Number 171243 by mathlove last updated on 11/Jun/22 Commented by infinityaction last updated on 11/Jun/22 $$\mathrm{6}??? \\ $$ Commented by mathlove last updated on…
Question Number 171237 by eman_64 last updated on 10/Jun/22 Commented by cherokeesay last updated on 10/Jun/22 $${Nice} \\ $$$${thank}\:{you} \\ $$ Commented by cortano1 last…
Question Number 171226 by SLVR last updated on 10/Jun/22 $${Possible}\:{number}\:{of}\:{order}\:{pairs} \\ $$$${satisfy}\:\mathrm{16}^{{x}^{\mathrm{2}} +{y}} +\mathrm{16}^{{y}^{\mathrm{2}} +{x}} =\mathrm{1}\:{is} \\ $$ Commented by SLVR last updated on 11/Jun/22…
Question Number 105686 by bramlex last updated on 31/Jul/20 $${solve}\:\mathrm{7}^{{x}} \:+\:\mathrm{24}^{{x}} \:=\:\mathrm{25}^{{x}} \: \\ $$ Answered by Rasheed.Sindhi last updated on 31/Jul/20 $$\left(\frac{\mathrm{7}}{\mathrm{25}}\right)^{{x}} +\left(\frac{\mathrm{24}}{\mathrm{25}}\right)^{{x}} =\mathrm{1}…
Question Number 105687 by bramlex last updated on 31/Jul/20 $$\begin{cases}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \:=\:\mathrm{13}}\\{{x}^{\mathrm{3}} +{y}^{\mathrm{3}} \:=\:\mathrm{35}\:}\end{cases} \\ $$ Answered by john santu last updated on 31/Jul/20 $${set}\:{x}+{y}\:=\:{u}\:\wedge\:{xy}\:=\:{v}\:…