Question Number 105414 by qwertyu last updated on 28/Jul/20 Commented by qwertyu last updated on 28/Jul/20 $$\boldsymbol{{please}} \\ $$ Commented by PRITHWISH SEN 2 last…
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Question Number 170945 by Rasheed.Sindhi last updated on 04/Jun/22 $$ \\ $$$${y}=\sqrt[{\mathrm{3}}]{\mathrm{9}}\:+\sqrt[{\mathrm{3}}]{\mathrm{3}}\:+\mathrm{4}\:\:\:;\:\:\:\left(\mathrm{1}+\frac{\mathrm{1}}{{y}}\right)^{\mathrm{3}} =? \\ $$$$ \\ $$ Answered by cortano1 last updated on 04/Jun/22 $$\:{y}−\mathrm{3}=\sqrt[{\mathrm{3}}]{\mathrm{9}}\:+\sqrt[{\mathrm{3}}]{\mathrm{3}}\:+\mathrm{1}…
Question Number 39868 by math2018 last updated on 12/Jul/18 $${a},{b},{c}>\mathrm{0},{if} \\ $$$$\frac{\mathrm{8}{a}^{\mathrm{2}} }{{a}^{\mathrm{2}} +\mathrm{9}}={b},\:\:\frac{\mathrm{10}{b}^{\mathrm{2}} }{{b}^{\mathrm{2}} +\mathrm{16}}={c},\:\:\frac{\mathrm{6}{c}^{\mathrm{2}} }{{c}^{\mathrm{2}} +\mathrm{25}}={a}, \\ $$$${then},{what}\:{is}\:{the}\:{minimum}\:{value}\:{of}\:\:{a}+{b}+{c}? \\ $$ Answered by tanmay.chaudhury50@gmail.com…
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Question Number 170909 by mathlove last updated on 03/Jun/22 $$\mathrm{1}!+\mathrm{2}!+\mathrm{3}!+….+\mathrm{20000}!=? \\ $$ Commented by MJS_new last updated on 04/Jun/22 $$\mathrm{are}\:\mathrm{you}\:\mathrm{serious}?\:\mathrm{even}\:\mathrm{if}\:\mathrm{somebody}\:\mathrm{could}\:\mathrm{give} \\ $$$$\mathrm{you}\:\mathrm{the}\:\mathrm{exact}\:\mathrm{number},\:\mathrm{what}\:\mathrm{would}\:\mathrm{you}\:\mathrm{use} \\ $$$$\mathrm{it}\:\mathrm{for}? \\…
Question Number 39814 by pieroo last updated on 11/Jul/18 $$\mathrm{kwame},\:\mathrm{ama}\:\mathrm{and}\:\mathrm{yaw}\:\mathrm{shared}\:\mathrm{an}\:\mathrm{amount}\:\mathrm{of}\:\mathrm{money} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{3}:\mathrm{4}:\mathrm{5}.\:\mathrm{if}\:\mathrm{ama}\:\mathrm{had}\:\$\mathrm{8},\mathrm{400}\:\mathrm{more}\:\mathrm{than}\:\mathrm{kwame}. \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{total}\:\mathrm{amount}\:\mathrm{shared}. \\ $$ Answered by ajfour last updated on 11/Jul/18 $${K}=\mathrm{3}{x}\:\:,\:{A}=\mathrm{4}{x}\:,\:{Y}=\mathrm{5}{x} \\…
Question Number 105340 by Ar Brandon last updated on 27/Jul/20 $$\mathrm{1}\backslash\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{polynomial},\:\mathrm{P}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{n}} +\mathrm{ax}+\mathrm{b},\:\mathrm{n}\geqslant\mathrm{2} \\ $$$$\left(\mathrm{a},\mathrm{b}\right)\in\mathbb{R}^{\mathrm{2}} \:\mathrm{has}\:\mathrm{at}\:\mathrm{most}\:\mathrm{3}\:\mathrm{real}\:\mathrm{distinct}\:\mathrm{roots}. \\ $$$$\mathrm{2}\backslash\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{x}^{\mathrm{4}} +\mathrm{4ax}+\mathrm{b}=\mathrm{0}\:\mathrm{has}\:\mathrm{no} \\ $$$$\mathrm{more}\:\mathrm{than}\:\mathrm{2}\:\mathrm{real}\:\mathrm{distinct}\:\mathrm{roots}. \\ $$ Answered by LifeOnMars…
Question Number 105345 by bemath last updated on 28/Jul/20 $${If}\:{the}\:{point}\:\left(\sqrt{\mathrm{2}}\:,{p}\right)\:{and}\:\left(−\sqrt{\mathrm{2}},{q}\right) \\ $$$${lie}\:{on}\:{the}\:{graph}\:{y}={x}^{\mathrm{3}} +{ax}^{\mathrm{2}} +{bx}+{c} \\ $$$${and}\:{q}−{p}\:=\:\mathrm{3}\:,\:{then}\:{what}\:{the} \\ $$$${value}\:{of}\:{b}\:?\: \\ $$ Answered by ajfour last updated…
Question Number 170868 by Tawa11 last updated on 01/Jun/22 $$\mathrm{Solve}:\:\:\:\mid\mathrm{x}\:\:\:−\:\:\:\mathrm{1}\mid\:\:\:\:+\:\:\:\mid\mathrm{x}\:\:\:\:−\:\:\:\mathrm{2}\mid\:\:\:\:\geqslant\:\:\:\:\mathrm{4} \\ $$ Answered by thfchristopher last updated on 02/Jun/22 $$\Rightarrow\mid{x}−\mathrm{1}\mid\geqslant\mathrm{4}−\mid{x}−\mathrm{2}\mid \\ $$$$\Rightarrow{x}−\mathrm{1}\geqslant\mathrm{4}−\mid{x}−\mathrm{2}\mid\:\:\mathrm{or}\:\:{x}−\mathrm{1}\leqslant\mid{x}−\mathrm{2}\mid−\mathrm{4} \\ $$$$\mathrm{Case}\:\mathrm{1}: \\…