Question Number 170832 by Shrinava last updated on 01/Jun/22 Commented by mr W last updated on 01/Jun/22 $${T}={AM}+{BN}\geqslant\sqrt{{AB}^{\mathrm{2}} +{MN}^{\mathrm{2}} }=\sqrt{\mathrm{1}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} }=\sqrt{\mathrm{34}} \\…
Question Number 105234 by Josias last updated on 27/Jul/20 $${f}:\mathbb{R}\rightarrow\mathbb{R}\:\:{x},{y}\in\mathbb{R} \\ $$$${f}\left({f}\left({x}\right){f}\left({y}\right)\right)+{f}\left({x}+{y}\right)={f}\left({xy}\right) \\ $$$${f}\left({x}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 105222 by qwerty111 last updated on 26/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170738 by Tawa11 last updated on 30/May/22 Commented by Tawa11 last updated on 30/May/22 $$\mathrm{How}\:\mathrm{to}\:\mathrm{get}\:\mathrm{the}\:\mathrm{second}\:\mathrm{step}\:\mathrm{please}???? \\ $$$$\mathrm{S}\:\:\:=\:\:\:\frac{\mathrm{1}}{\mathrm{8}}\underset{\mathrm{n}\:=\:\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{3}}{\left(\mathrm{3n}\:+\:\mathrm{1}\right)\left(\mathrm{3n}\:+\:\mathrm{2}\right)}\:\:−\:\:\frac{\mathrm{5}}{\left(\mathrm{3n}\:+\:\mathrm{2}\right)\left(\mathrm{3n}\:+\:\mathrm{3}\right)}\:\:+\:\:\frac{\mathrm{2}}{\left(\mathrm{3n}\:+\:\mathrm{3}\right)\left(\mathrm{3n}\:+\:\mathrm{1}\right)} \\ $$$$\mathrm{From}\:\mathrm{the}\:\mathrm{question}\:… \\ $$…
Question Number 170729 by solomonwells last updated on 30/May/22 Commented by phamkhanhhuong last updated on 30/May/22 $$\Leftrightarrow\sqrt{{x}−\mathrm{1}+\mathrm{2}\sqrt{{x}−\mathrm{1}}+\mathrm{1}}+\sqrt{{x}−\mathrm{1}−\mathrm{2}\sqrt{{x}−\mathrm{1}}+\mathrm{1}}={x}−\mathrm{1} \\ $$$$\Leftrightarrow\sqrt{\left(\sqrt{{x}−\mathrm{1}}+\mathrm{1}\right)^{\mathrm{2}} }+\sqrt{\left(\sqrt{{x}−\mathrm{1}}−\mathrm{1}\right)^{\mathrm{2}} }={x}−\mathrm{1} \\ $$$$\Leftrightarrow\mid\sqrt{{x}−\mathrm{1}}+\mathrm{1}\mid+\mid\sqrt{{x}−\mathrm{1}}−\mathrm{1}\mid={x}−\mathrm{1}\left(\ast\right) \\ $$$$\sqrt{{x}−\mathrm{1}}+\mathrm{1}>\mathrm{0}\:\forall{x}\in\left[\mathrm{1};+\infty\right).…
Question Number 105189 by qwertyu last updated on 26/Jul/20 Commented by floor(10²Eta[1]) last updated on 26/Jul/20 $$\mathrm{hey}\:\mathrm{chill}\:\mathrm{out}\:\mathrm{man}\:\mathrm{you}\:\mathrm{don}'\mathrm{t}\:\mathrm{need}\:\mathrm{to} \\ $$$$\mathrm{care}\:\mathrm{about}\:\mathrm{this}\:\mathrm{guy},\:\mathrm{we}\:\mathrm{still}\:\mathrm{need}\:\mathrm{you}\:\mathrm{to} \\ $$$$\mathrm{help}\:\mathrm{us}\:\mathrm{in}\:\mathrm{the}\:\mathrm{forum}.\: \\ $$$$ \\ $$$$…
Question Number 39639 by jasno91 last updated on 09/Jul/18 Answered by $@ty@m last updated on 09/Jul/18 $${length}\:{of}\:{lace}=\mathrm{2}\left(\mathrm{2}.\mathrm{25}+\mathrm{1}.\mathrm{75}\right) \\ $$$$=\mathrm{8}{m} \\ $$$${cost}=\mathrm{8}×\mathrm{14}.\mathrm{50} \\ $$$$={Rs}.\:\mathrm{116} \\ $$…
Question Number 39636 by math khazana by abdo last updated on 09/Jul/18 $${let}\:{P}_{\alpha} \left({x}\right)\:={x}^{\mathrm{3}} \:\:+\mathrm{2}\alpha\:{x}\:−\mathrm{3} \\ $$$$\left.\mathrm{1}\right)\:{determine}\:{the}\:{roots}\:{of}\:{P}_{\alpha} \\ $$$$\left.\mathrm{2}\right)\:{determine}\:{the}\:{roots}\:{of}\:\:{P}_{−\mathrm{1}} \\ $$ Answered by ajfour last…
Question Number 170706 by help12345 last updated on 29/May/22 $$ \\ $$Between 10:PM and 7:45AM the water level in a swimming pool decreased by 13÷16…
Question Number 170701 by help12345 last updated on 29/May/22 $$ \\ $$In the first week of July, a record 1060 people went to the local…