Question Number 170276 by mnjuly1970 last updated on 19/May/22 Commented by Rasheed.Sindhi last updated on 19/May/22 $${See}\:{Q}#\mathrm{170054} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 104717 by 1549442205PVT last updated on 24/Jul/20 $$\mathrm{In}\:\mathrm{the}\:\mathrm{a}\:\:\mathrm{sport}\:\mathrm{camp},\:\mathrm{65\%}\:\mathrm{children}\:\mathrm{know} \\ $$$$\mathrm{playing}\:\mathrm{the}\:\mathrm{football},\mathrm{70\%}−\mathrm{in}\:\mathrm{voleyball},\mathrm{75\%}−\mathrm{in} \\ $$$$\mathrm{basketball}.\mathrm{What}\:\mathrm{is}\:\mathrm{least}\:\mathrm{number}\:\mathrm{of}\:\mathrm{children}\:\mathrm{who} \\ $$$$\mathrm{know}\:\mathrm{playing}\:\mathrm{all}\:\mathrm{above}\:\mathrm{three}\:\mathrm{sport}\:\mathrm{games}? \\ $$$$\left(\mathrm{Answer}\:\mathrm{10\%}\right) \\ $$ Terms of Service Privacy Policy…
Question Number 104706 by Skabetix last updated on 23/Jul/20 $${find}\:{the}\:{value}\:{of}\:\:{p}\:\left({pls}\:{help}\right) \\ $$$$\mathrm{1}^{\mathrm{3}} +\mathrm{3}^{\mathrm{3}} +\mathrm{5}^{\mathrm{3}} +…+{p}^{\mathrm{3}} =\mathrm{8128} \\ $$$$ \\ $$ Commented by mr W last…
Question Number 104696 by nimnim last updated on 23/Jul/20 Answered by Rasheed.Sindhi last updated on 23/Jul/20 $${A}'{s}\:{age}\:{at}\:{present}\:{x}\:{years} \\ $$$${B}'{s}\:{age}\:{at}\:{present}\:{y}\:{years} \\ $$$$\:\:\:\:{x}−\mathrm{7}=\:\mathrm{5}\left({y}−\mathrm{7}\right)^{\mathrm{2}} …….\left({i}\right) \\ $$$$\:\:\:{y}+\mathrm{3}=\frac{\mathrm{2}}{\mathrm{5}}\left({x}+\mathrm{3}\right)………\left({ii}\right) \\…
Question Number 104676 by qwertyu last updated on 23/Jul/20 Commented by Dwaipayan Shikari last updated on 23/Jul/20 $${cos}\mathrm{36}°+{cos}\mathrm{108}°={cos}\mathrm{36}°−{cos}\mathrm{72}° \\ $$$$=\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{4}}−\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented by OlafThorendsen…
Question Number 104657 by bobhans last updated on 23/Jul/20 $$\left({x}+{yi}\right)^{\mathrm{3}} \:=\:\frac{\mathrm{10}\left(\mathrm{2}{y}+\mathrm{8}{i}\right)^{\mathrm{2}} }{\mathrm{3}−{i}} \\ $$$${find}\:{x}\:\&\:{y} \\ $$ Answered by bramlex last updated on 23/Jul/20 $$\left({x}+{yi}\right)^{\mathrm{3}} \:=\:\frac{\mathrm{10}\left(\mathrm{2}{y}+\mathrm{8}{i}\right)^{\mathrm{2}}…
Question Number 170185 by mathlove last updated on 18/May/22 Commented by MJS_new last updated on 18/May/22 $${x}=\mathrm{0} \\ $$$${x}\approx.\mathrm{874961088208} \\ $$ Terms of Service Privacy…
Question Number 170187 by infinityaction last updated on 18/May/22 Commented by MJS_new last updated on 18/May/22 $$\mathrm{it}'\mathrm{s}\:\mathrm{a}\:\mathrm{number}\:\mathrm{with}\:\mathrm{609}\:\mathrm{digits}\:\mathrm{starting}\:\mathrm{with} \\ $$$$\mathrm{550355}…\:\mathrm{and}\:\mathrm{ending}\:\mathrm{with}\:…\mathrm{570632} \\ $$ Commented by infinityaction last…
Question Number 104621 by ajfour last updated on 22/Jul/20 $$\frac{\mathrm{1}}{\left(\mathrm{1}−{x}\right)^{\mathrm{2}} }−\frac{\mathrm{4}}{\left(\mathrm{1}+{x}\right)^{\mathrm{2}} }=\mathrm{1} \\ $$ Answered by prakash jain last updated on 22/Jul/20 $$\left(\mathrm{1}+{x}\right)^{\mathrm{2}} −\mathrm{4}\left(\mathrm{1}−{x}\right)^{\mathrm{2}} =\left(\mathrm{1}−\mathrm{2}{x}+{x}^{\mathrm{2}}…
Question Number 170148 by Shrinava last updated on 17/May/22 Answered by mr W last updated on 20/May/22 Commented by mr W last updated on 20/May/22…