Question Number 170131 by mathlove last updated on 17/May/22 $$\mathrm{4}^{\mid{x}\mid} ={x}^{\mathrm{4}} \\ $$$${x}=? \\ $$ Answered by mr W last updated on 17/May/22 $$\mid{x}\mid={t}>\mathrm{0} \\…
Question Number 39053 by jasno91 last updated on 02/Jul/18 Answered by $@ty@m last updated on 02/Jul/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104588 by M±th+et+s last updated on 22/Jul/20 $${solve}\:{in}\:\mathbb{R} \\ $$$$\frac{\mathrm{96}{x}−\mathrm{24}}{\mathrm{12}{x}+\mathrm{5}}=\sqrt{−\mathrm{144}{x}^{\mathrm{2}} +\mathrm{72}{x}+\mathrm{7}} \\ $$ Commented by M±th+et+s last updated on 22/Jul/20 $${thanks}\:{both}\:{for}\:{solutions} \\ $$…
Question Number 170117 by mathlove last updated on 16/May/22 $${x}^{\mathrm{2}} =\mathrm{4}^{{x}} \:\:\:\:\:\:{x}=? \\ $$$$ \\ $$$$ \\ $$ Commented by mathlove last updated on 16/May/22…
Question Number 170115 by Shrinava last updated on 16/May/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{then}: \\ $$$$\frac{\mathrm{cos}\:\frac{\mathrm{A}}{\mathrm{2}}\:\centerdot\:\mathrm{cos}\:\frac{\mathrm{B}}{\mathrm{2}}\:\centerdot\:\mathrm{cos}\:\frac{\mathrm{C}}{\mathrm{2}}}{\left(\mathrm{1}\:-\:\mathrm{sin}\:\frac{\mathrm{A}}{\mathrm{2}}\right)\centerdot\left(\mathrm{1}\:-\:\mathrm{sin}\:\frac{\mathrm{B}}{\mathrm{2}}\right)\centerdot\left(\mathrm{1}\:-\:\mathrm{sin}\:\frac{\mathrm{C}}{\mathrm{2}}\right)}\:\geqslant\:\mathrm{3}\sqrt{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170113 by Shrinava last updated on 16/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170110 by mathlove last updated on 16/May/22 $${prove}\:{that} \\ $$$${e}^{{i}\theta} ={cos}\theta+{isin}\theta \\ $$ Commented by ajfour last updated on 16/May/22 $$\mathrm{1}×{e}^{{i}\theta} ={z}\:{is} \\…
Question Number 170100 by mathlove last updated on 16/May/22 Commented by cortano1 last updated on 16/May/22 $$\:{y}=−\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:\mathrm{sin}\:{x}−\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{cos}\:{x} \\ $$$${y}=−\left(\frac{\mathrm{1}}{\mathrm{2}}\mathrm{cos}\:{x}+\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:\mathrm{sin}\:{x}\right) \\ $$$${y}=−\left(\mathrm{sin}\:\frac{\pi}{\mathrm{6}}\:\mathrm{cos}\:{x}\:+\:\mathrm{cos}\:\frac{\pi}{\mathrm{6}}\:\mathrm{sin}\:{x}\right) \\ $$$${y}=−\mathrm{sin}\:\left({x}+\frac{\pi}{\mathrm{6}}\right) \\ $$…
Question Number 39026 by maxmathsup by imad last updated on 01/Jul/18 $${find}\:{the}\:{roots}\:{of}\:\:\mathrm{8}{x}^{\mathrm{3}} \:−\mathrm{4}{x}−\mathrm{1}\:=\mathrm{0} \\ $$ Answered by behi83417@gmail.com last updated on 02/Jul/18 $${x}_{\mathrm{1}} =−\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 170099 by mathlove last updated on 16/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com