Question Number 104394 by Anindita last updated on 21/Jul/20 Answered by Ritu Jain last updated on 21/Jul/20 $$\mathrm{Sum}\:\mathrm{of}\:\mathrm{internal}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}=\mathrm{180}° \\ $$$$\mathrm{the}\:\mathrm{angle}\:\mathrm{in}\:? \\ $$$$=\mathrm{180}°−\mathrm{30}°−\mathrm{40}°=\mathrm{110}° \\ $$ Terms…
Question Number 104391 by Anindita last updated on 21/Jul/20 $$\left(\boldsymbol{{x}}−\boldsymbol{{a}}\right)\left(\boldsymbol{{x}}−\boldsymbol{{b}}\right)\left(\boldsymbol{{x}}−\boldsymbol{{c}}\right)….\left(\boldsymbol{{x}}−\boldsymbol{{z}}\right)\:=\:? \\ $$ Commented by som(math1967) last updated on 21/Jul/20 $$\mathrm{0} \\ $$ Terms of Service…
Question Number 169923 by mathlove last updated on 12/May/22 $$\underset{{d}\mid\mathrm{6}} {\sum}{d}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169916 by mathlove last updated on 12/May/22 Answered by mahdipoor last updated on 12/May/22 $${ln}\left(\mathrm{2}^{{x}^{\mathrm{2}} } ×\mathrm{3}^{{x}} \right)={ln}\left(\mathrm{2}^{{x}^{\mathrm{2}} } \right)+{ln}\left(\mathrm{3}^{{x}} \right)={ln}\left(\mathrm{6}\right)\:\Rightarrow \\ $$$$\left({ln}\mathrm{2}\right){x}^{\mathrm{2}}…
Question Number 104377 by I want to learn more last updated on 21/Jul/20 $$\mathrm{Solve}:\:\:\:\:\:\mathrm{a}^{\mathrm{2}} \:\:+\:\mathrm{c}^{\mathrm{2}} \:\:=\:\:\mathrm{196}\:\:\:\:\:\:\:\:…\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{b}^{\mathrm{2}} \:\:+\:\:\left(\mathrm{c}\:\:−\:\:\mathrm{a}\right)^{\mathrm{2}} \:\:=\:\:\mathrm{169}\:\:\:…\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{c}^{\mathrm{2}} \:\:+\:\:\left(\mathrm{b}\:\:−\:\:\mathrm{c}\right)^{\mathrm{2}} \:\:=\:\:\mathrm{225}\:\:\:\:\:….\:\left(\mathrm{iii}\right) \\…
Question Number 104369 by quvonchbek3737 last updated on 21/Jul/20 Answered by mr W last updated on 21/Jul/20 $$\mathrm{6}\left(\sqrt[{{x}}]{\mathrm{3}}\right)^{\mathrm{2}} −\mathrm{13}\left(\sqrt[{{x}}]{\mathrm{3}}\right)\left(\sqrt[{{x}}]{\mathrm{2}}\right)+\mathrm{6}\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$$\mathrm{6}\left(\sqrt[{{x}}]{\frac{\mathrm{3}}{\mathrm{2}}}\right)^{\mathrm{2}} −\mathrm{13}\left(\sqrt[{{x}}]{\frac{\mathrm{3}}{\mathrm{2}}}\right)+\mathrm{6}=\mathrm{0} \\ $$$$\sqrt[{{x}}]{\frac{\mathrm{3}}{\mathrm{2}}}=\left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{{x}}…
Question Number 169901 by Shrinava last updated on 12/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 38825 by Sr@2004 last updated on 30/Jun/18 Commented by kunal1234523 last updated on 30/Jun/18 $${sir}\:{Sr}@\mathrm{2004}\:{you}\:{can}\:{write}\:{here}\:{very}\:{easily}. \\ $$ Commented by Sr@2004 last updated on…
Question Number 169865 by mr W last updated on 11/May/22 $${x}+{y}=−\mathrm{2} \\ $$$${xy}=\mathrm{4} \\ $$$${find}\:{x}^{\mathrm{8}} +\mathrm{8}{y}^{\mathrm{5}} =? \\ $$ Commented by cortano1 last updated on…
Question Number 104326 by Anindita last updated on 20/Jul/20 $$\boldsymbol{\mathrm{Suppose}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{had}}\:\boldsymbol{{x}}\:\boldsymbol{\mathrm{rupees}}.\:\boldsymbol{\mathrm{Your}} \\ $$$$\boldsymbol{\mathrm{father}}\:\boldsymbol{\mathrm{gave}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{more}}\:\mathrm{6}\:\boldsymbol{\mathrm{rupees}}.\:\boldsymbol{\mathrm{You}} \\ $$$$\boldsymbol{\mathrm{gave}}\:\boldsymbol{{y}}\:\boldsymbol{\mathrm{rupees}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{your}}\:\boldsymbol{\mathrm{brother}}.\:\boldsymbol{\mathrm{Now}} \\ $$$$\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{many}}\:\boldsymbol{\mathrm{rupees}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{have}}?\:\boldsymbol{\mathrm{You}}\:\boldsymbol{\mathrm{will}} \\ $$$$\boldsymbol{\mathrm{buy}}\:\boldsymbol{\mathrm{three}}\:\boldsymbol{\mathrm{shirts}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{rupees}}\:\boldsymbol{\mathrm{that}} \\ $$$$\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{have}}\:\boldsymbol{\mathrm{now}}.\:\boldsymbol{\mathrm{Write}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{cost}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{each}} \\ $$$$\boldsymbol{\mathrm{shirt}}. \\ $$ Commented…