Question Number 169860 by Shrinava last updated on 11/May/22 $$\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{1} \\ $$$$\mathrm{y}\:=\:\mathrm{0} \\ $$$$\mathrm{x}\:=\:-\:\mathrm{1} \\ $$$$\mathrm{x}\:=\:\mathrm{2} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{object}\:\mathrm{obtained} \\ $$$$\mathrm{by}\:\mathrm{rotating}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{bounded}\:\mathrm{by}\:\mathrm{lines} \\ $$$$\mathrm{around}\:\mathrm{the}\:\mathrm{abscissa}\:\mathrm{axis} \\ $$…
Question Number 169852 by Shrinava last updated on 10/May/22 $$\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{2} \\ $$$$\mathrm{y}\:=\:-\:\mathrm{x} \\ $$$$\mathrm{x}\:=\:\mathrm{0} \\ $$$$\mathrm{x}\:=\:\mathrm{1} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{bounded}\:\mathrm{by} \\ $$$$\mathrm{lines} \\ $$ Answered by…
Question Number 38786 by Rio Mike last updated on 29/Jun/18 Commented by Rio Mike last updated on 29/Jun/18 $${Three}\:{triangles}\:{are}\:{colined}\:{or}\:{lined} \\ $$$${on}\:{a}\:{line}\:{with}\:{equation}\: \\ $$$${y}\:=\:\mathrm{3}{x}\:+\:\mathrm{1}\:{as}\:{shown}\:{above}. \\ $$$${the}\:{height}\:{of}\:{the}\:{triangles}\:{are}…
Question Number 169855 by Shrinava last updated on 11/May/22 Answered by thfchristopher last updated on 11/May/22 $$=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{sin}\:\left(\mathrm{3}{x}−{x}\right){dx} \\ $$$$=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{sin}\:\mathrm{2}{xdx} \\ $$$$−\frac{\mathrm{1}}{\mathrm{2}}\left[\mathrm{cos}\:\mathrm{2}{x}\right]_{\mathrm{0}}…
Question Number 169842 by mathlove last updated on 10/May/22 Answered by Rasheed.Sindhi last updated on 10/May/22 $${f}^{\:\mathrm{2}} \left({x}\right).{f}\left(\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}\right)={x}^{\mathrm{2}} ………….\left(\mathrm{A}\right) \\ $$$$\left(\mathrm{A}\right)^{\mathrm{2}} :\:\:{f}^{\:\:\mathrm{4}} \left({x}\right).{f}^{\:\mathrm{2}} \left(\frac{\mathrm{1}−{x}}{\mathrm{1}+{x}}\right)={x}^{\mathrm{4}} \\…
Question Number 104294 by Anindita last updated on 20/Jul/20 $$\mathrm{1}.\:\:\frac{\mathrm{1}\frac{\mathrm{1}}{\mathrm{2}}+\mathrm{2}\frac{\mathrm{6}}{\mathrm{7}}}{\mathrm{2}\frac{\mathrm{2}}{\mathrm{3}}−\mathrm{3}\frac{\mathrm{4}}{\mathrm{5}}}=? \\ $$$$\mathrm{2}.\:\:\mathrm{4}×\Pi×\Pi=? \\ $$$$\mathrm{3}.\:\:\boldsymbol{\mathrm{Transfer}}\:\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{fractions}}: \\ $$$$\:\:\:\:\:\:\mathrm{5}.\overset{.} {\mathrm{8}}\overset{.} {\mathrm{9}},\:\mathrm{9}.\overset{.} {\mathrm{6}},\:\mathrm{78}.\mathrm{5}\overset{.} {\mathrm{7}}\overset{.} {\mathrm{8}} \\ $$ Answered by…
Question Number 104297 by Anindita last updated on 20/Jul/20 $$\frac{\mathrm{3}{a}^{\mathrm{2}} {b}^{\mathrm{3}} {c}}{\mathrm{5}{b}^{\mathrm{4}} {c}}+\frac{\mathrm{6}{xy}^{\mathrm{3}} {z}^{\mathrm{16}} }{\mathrm{10}{x}^{\mathrm{2}} {y}^{\mathrm{2}} {z}^{\mathrm{10}} }\:=\:? \\ $$$$\boldsymbol{\mathrm{Can}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}? \\ $$ Answered by bemath…
Question Number 169831 by Shrinava last updated on 10/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104278 by Anindita last updated on 20/Jul/20 $${x}−\left(−\left(−{x}+\left(−{x}+{x}\right)\right)\right)=\:? \\ $$ Answered by bramlex last updated on 20/Jul/20 $${x}−\left(−\left(−{x}+\mathrm{0}\right)\right)={x}−\left(−\left(−{x}\right)\right) \\ $$$$={x}−\left({x}\right)=\mathrm{0} \\ $$ Terms…
Question Number 104270 by Study last updated on 20/Jul/20 $${sgn}\left(\mid{x}\mid\right)=? \\ $$ Answered by mr W last updated on 20/Jul/20 $${sgn}\left(\mid{x}\mid\right)=\mathrm{0},\:{if}\:{x}=\mathrm{0} \\ $$$${sgn}\left(\mid{x}\mid\right)=\mathrm{1},\:{if}\:{x}\neq\mathrm{0} \\ $$…