Question Number 103914 by bobhans last updated on 18/Jul/20 $$\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)^{{x}^{\mathrm{2}} } \:+\:\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{{x}^{\mathrm{2}} } \:=\:\mathrm{4}\: \\ $$ Commented by som(math1967) last updated on 18/Jul/20 $$\mathrm{let}\:\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)^{\mathrm{x}^{\mathrm{2}} }…
Question Number 103921 by Rio Michael last updated on 18/Jul/20 $$\mathrm{Prove}\:\mathrm{that}\:\forall\:{x}\:\in\:\bar {\mathbb{R}}\:,\:\mid\:\mathrm{cos}\:{x}\:\mid\:\leqslant\:\mathrm{1}\:−\:\mathrm{sin}^{\mathrm{2}} \:{x} \\ $$ Answered by Worm_Tail last updated on 18/Jul/20 $${cosx}=\sqrt{\mathrm{1}−{sin}^{\mathrm{2}} {x}\:\:\:\:\:\:\:\:} \\…
Question Number 169445 by infinityaction last updated on 30/Apr/22 $$ \\ $$$$\:\:\:\mathrm{let}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:\mathrm{be}\:\mathrm{positive}\:\mathrm{reals}\:\mathrm{such}\:\mathrm{that} \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:+\:\left(\mathrm{x}+\mathrm{y}\right)^{\mathrm{3}} \:+\mathrm{30xy}\:=\:\mathrm{2000} \\ $$$$\:\:\:\:\mathrm{show}\:\mathrm{that}\:\mathrm{x}+\mathrm{y}\:=\:\mathrm{10} \\ $$ Commented by mr W…
Question Number 169439 by Giantyusuf last updated on 30/Apr/22 Answered by mr W last updated on 30/Apr/22 $${a}^{\mathrm{2}} {x}^{\mathrm{2}} +{a}^{\mathrm{2}} {y}^{\mathrm{2}} +{b}^{\mathrm{2}} {x}^{\mathrm{2}} +{b}^{\mathrm{2}} {y}^{\mathrm{2}}…
Question Number 169432 by mathlove last updated on 30/Apr/22 $${n}\left({A}\right)=\mathrm{7} \\ $$$${n}\left({A}\cap{B}\right)=\mathrm{4} \\ $$$$\mathrm{3}{n}\left({A}−{B}\right)={n}\left({B}\right) \\ $$$${n}\left({B}−{A}\right)=? \\ $$ Answered by blackmamba last updated on 30/Apr/22…
Question Number 103888 by mr W last updated on 18/Jul/20 $${find}\:{all}\:{such}\:{numbers}: \\ $$$${if}\:{we}\:{make}\:{its}\:{last}\:{digit},\:{say}\:{k},\:{as}\:{its} \\ $$$${first}\:{digit},\:{the}\:{number}\:{becomes}\:{k} \\ $$$${times}\:{large}\:{as}\:{before}. \\ $$$$\left(\Box\Box…\Box{k}\right)\rightarrow\left({k}\Box\Box…\Box\right)={k}×\left(\Box\Box…\Box{k}\right) \\ $$ Answered by MAB last…
Question Number 169413 by mathlove last updated on 30/Apr/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169407 by Shrinava last updated on 29/Apr/22 Answered by Rasheed.Sindhi last updated on 01/May/22 $$\mathrm{If}\:\mathbb{N}=\left\{\mathrm{0},\mathrm{1},\mathrm{2},…\right\} \\ $$$$\mathrm{M}=\left\{\left(\mathrm{0},\mathrm{0},\mathrm{0},\mathrm{0}\right)\right\} \\ $$$$\Omega=\mathrm{0} \\ $$$$\mathrm{16}^{{x}} +\mathrm{16}^{\frac{\mathrm{1}}{{x}}} =\mathrm{8}\:{has}\:{no}\:{solution}.…
Question Number 169389 by Shrinava last updated on 29/Apr/22 $$\mathrm{1}.\:\mathrm{2}\sqrt{\mathrm{y}}\:\mathrm{dx}\:=\:\mathrm{dy} \\ $$$$\mathrm{2}.\:\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \right)\mathrm{dx}\:=\:\mathrm{2xydy} \\ $$$$\mathrm{3}.\:\mathrm{xdx}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:\mathrm{dy}\:=\:\mathrm{0} \\ $$$$\mathrm{4}.\:\mathrm{dy}\:=\:\mathrm{3x}^{\mathrm{2}} \:\mathrm{dx} \\ $$$$\mathrm{5}.\:\mathrm{2y}^{\mathrm{2}} \mathrm{dx}\:+\:\mathrm{x}\left(\mathrm{1}\:+\:\mathrm{y}^{\mathrm{2}} \right)\:\mathrm{dy}\:=\:\mathrm{0} \\ $$$$\mathrm{6}.\:\mathrm{4x}^{\mathrm{3}}…
Question Number 169391 by mathlove last updated on 29/Apr/22 Commented by infinityaction last updated on 29/Apr/22 $$\mathrm{0} \\ $$ Commented by mathlove last updated on…