Question Number 169130 by pete last updated on 24/Apr/22 $$\mathrm{If}\:\left(\mathrm{0}.\mathrm{3}\right)^{\mathrm{x}} =\left(\mathrm{0}.\mathrm{5}\right)^{\mathrm{8}} ,\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$ Answered by MikeH last updated on 24/Apr/22 $${x}\:=\:\frac{\mathrm{8}\:\mathrm{log}\:\mathrm{0}.\mathrm{5}}{\mathrm{log}\:\mathrm{0}.\mathrm{3}}\:=\mathrm{4}.\mathrm{6057} \\ $$ Commented…
Question Number 169120 by mnjuly1970 last updated on 24/Apr/22 $$ \\ $$$$\:\:\:\:{solve}\:\:{in}\:\mathbb{R} \\ $$$$\: \\ $$$$\:\:\:\:\:\lfloor\:\mathrm{log}_{\:\mathrm{2}} \left({x}\right)\:\rfloor=\:\mathrm{5}\:\mathrm{log}_{\:\mathrm{8}} \left(\sqrt{{x}}\:\right) \\ $$$$ \\ $$ Answered by aleks041103…
Question Number 169117 by infinityaction last updated on 24/Apr/22 Answered by greougoury555 last updated on 24/Apr/22 $$\:{f}\left({x},{y},\lambda\right)=\:\left({x}^{\mathrm{3}} +\mathrm{1}\right)\left({y}^{\mathrm{3}} +\mathrm{1}\right)+\lambda\left({x}+{y}−\mathrm{1}\right) \\ $$$$\:\frac{\partial{f}}{\partial{x}}\:=\:\mathrm{3}{x}^{\mathrm{2}} \left({y}^{\mathrm{3}} +\mathrm{1}\right)+\lambda=\mathrm{0} \\ $$$$\:\frac{\partial{f}}{\partial{y}}\:=\:\mathrm{3}{y}^{\mathrm{2}}…
Question Number 169092 by Shrinava last updated on 24/Apr/22 Answered by mr W last updated on 24/Apr/22 Commented by mr W last updated on 24/Apr/22…
Question Number 37991 by Fawomath last updated on 20/Jun/18 $$\mathrm{1}.\:{Find}\:{the}\:{sum} \\ $$$$\:\:\:\:{s}_{{n}} =\mathrm{1}+\mathrm{2}{x}+\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{x}^{\mathrm{3}} +…+{nx}^{{n}−\mathrm{1}} \\ $$$${Hence},{or}\:{otherwise},\:{find}\:{the}\:{sum} \\ $$$$\:\:\:\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}.\mathrm{2}^{{k}} \\ $$$$\mathrm{2}.\:{Simplify}\:{the}\:{following} \\ $$$${i}.\:\underset{{r}=\mathrm{0}}…
Question Number 37953 by ajfour last updated on 19/Jun/18 Commented by ajfour last updated on 19/Jun/18 $${Find}\:{the}\:{area}\:{in}\:{blue}.\:{z}_{{i}} \:{are}\: \\ $$$${complex}\:{numbers}\:{on}\:{the}\:\mathbb{C}\:{plane}. \\ $$ Terms of Service…
Question Number 169004 by mathlove last updated on 23/Apr/22 $$\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\left(\frac{{sinx}−\mathrm{1}}{{x}−\frac{\pi}{\mathrm{2}}}\right)=? \\ $$ Commented by infinityaction last updated on 23/Apr/22 $$\:\:\:\:\:\:\:\:\:\:\:\left({let}\right){p}\:\:\:\:\:\:\:\:=\:\:\:\:\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\left(\frac{\mathrm{sin}\:{x}−\mathrm{sin}\:\frac{\pi}{\mathrm{2}}}{{x}−\frac{\pi}{\mathrm{2}}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{p}\:\:\:\:=\:\:\:\:\:\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\left\{\frac{\mathrm{2cos}\:\left(\frac{{x}+\pi/\mathrm{2}}{\mathrm{2}}\right)\mathrm{sin}\:\left(\frac{{x}−\pi/\mathrm{2}}{\mathrm{2}}\right)}{\mathrm{2}\left(\frac{{x}−\pi/\mathrm{2}}{\mathrm{2}}\right)}\right\}…
Question Number 37906 by mondodotto@gmail.com last updated on 19/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 19/Jun/18 $${join}\:{oB}\:{so}\:<{OBC}=\mathrm{90}^{{o}} \\ $$$$<{BEO}=<{OBE}={x}\left\{{since}\:{OB}={OE}={radius}\right\} \\ $$$${x}+\mathrm{18}^{{o}} +\mathrm{90}^{{o}} +{x}=\mathrm{180}^{{o}} \\ $$$$\mathrm{2}{x}=\mathrm{72}^{{o}}…
Question Number 103436 by bramlex last updated on 15/Jul/20 $$\underset{\mathrm{n}\:=\:\mathrm{3}} {\overset{\infty} {\prod}}\left(\mathrm{1}−\frac{\mathrm{4}}{\mathrm{n}^{\mathrm{2}} }\right)\:=\:? \\ $$ Answered by Worm_Tail last updated on 15/Jul/20 $$\underset{\mathrm{3}} {\overset{{oo}} {\prod}}\left(\mathrm{1}−\frac{\mathrm{4}}{{n}^{\mathrm{2}}…
Question Number 168968 by infinityaction last updated on 22/Apr/22 Terms of Service Privacy Policy Contact: info@tinkutara.com