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Category: Algebra

Question-211509

Question Number 211509 by RojaTaniya last updated on 11/Sep/24 Answered by A5T last updated on 11/Sep/24 6a+b6c+d=k=5a+b5c+d6a+b=6ck+dk(i);5a+b=5ck+dk(ii)(i)(ii)a=ck;6(ii)5(i)b=dk7a+b=8(7c+d)7ck+dk=8(7c+d)$$\Rightarrow{k}=\frac{\mathrm{8}\left(\mathrm{7}{c}+{d}\right)}{\mathrm{7}{c}+{d}}=\mathrm{8}…