Question Number 167800 by cortano1 last updated on 25/Mar/22 $$\:\:\:\:\:\:\mathrm{5}^{\mathrm{2}{x}} \:=\:\mathrm{2}.\mathrm{10}^{{x}} −\mathrm{4}^{\mathrm{2}{x}} \: \\ $$$$\:\:\:\:\:\sqrt[{\left({x}+\mathrm{2}\right)^{−\mathrm{1}} }]{\left({x}−\mathrm{4}\right)^{{x}^{\mathrm{2}} +\mathrm{2}} }=?\: \\ $$ Commented by MJS_new last updated…
Question Number 167777 by infinityaction last updated on 24/Mar/22 Answered by Jamshidbek last updated on 26/Mar/22 $$\boldsymbol{\mathrm{Solution}}. \\ $$$$\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} +\mathrm{z}^{\mathrm{3}} −\mathrm{3xy}=\left(\mathrm{x}+\mathrm{y}+\mathrm{z}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} −\left(\mathrm{xy}+\mathrm{yz}+\mathrm{xz}\right)\right)…
Question Number 167772 by mathlove last updated on 24/Mar/22 $${x}+\sqrt{{x}}=\mathrm{5} \\ $$$${x}+\frac{\mathrm{5}}{\:\sqrt{{x}}}=? \\ $$ Commented by mr W last updated on 24/Mar/22 $$\left(\sqrt{{x}}\right)^{\mathrm{2}} +\sqrt{{x}}−\mathrm{5}=\mathrm{0} \\…
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Question Number 36696 by kumar12513 last updated on 04/Jun/18 $${if}\:{y}={tan}^{−\mathrm{1}} {x}\:{show}\:{that} \\ $$$$\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}_{{n}+\mathrm{2}} +\mathrm{2}\left({n}+\mathrm{1}\right){xy}_{{n}+\mathrm{1}} +{n}\left({n}+\mathrm{1}\right){y}_{{n}} =\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 36691 by Tinkutara last updated on 04/Jun/18 Commented by Rasheed.Sindhi last updated on 05/Jun/18 $${ax}+{cy}+{bz}={X},{cx}+{by}+{az}={Y},{bx}+{ay}+{cz}={Z} \\ $$$$\mathrm{Adding}\:\mathrm{the}\:\mathrm{three}: \\ $$$$\left({a}+{b}+{c}\right)\left({x}+{y}+{z}\right)={X}+{Y}+{Z} \\ $$$$…… \\ $$$$….…
Question Number 36692 by math2018 last updated on 04/Jun/18 $${x}^{\mathrm{3}} +{y}^{\mathrm{3}} =\mathrm{5} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{3} \\ $$ Commented by behi83417@gmail.com last updated on 04/Jun/18…
Question Number 167750 by mathlove last updated on 24/Mar/22 Answered by Rasheed.Sindhi last updated on 24/Mar/22 $${f}\left({x}−{y}\right)={f}\left({x}\right)−{f}\left({y}\right);\:{f}\left(\mathrm{2}\right)=\mathrm{5};\:{f}\left(\mathrm{16}\right)=? \\ $$$$\bullet{x}=\mathrm{2}{y} \\ $$$${f}\left(\mathrm{2}{y}−{y}\right)={f}\left(\mathrm{2}{y}\right)−{f}\left({y}\right) \\ $$$${f}\left({y}\right)={f}\left(\mathrm{2}{y}\right)−{f}\left({y}\right) \\ $$$$\mathrm{2}{f}\left({y}\right)={f}\left(\mathrm{2}{y}\right)…
Question Number 167746 by mathlove last updated on 24/Mar/22 $${log}_{\left({x}^{\mathrm{2}} +\mathrm{2}\right)} \left({x}^{\mathrm{2}} +\mathrm{4}{x}\right)=? \\ $$ Commented by MJS_new last updated on 24/Mar/22 $$\mathrm{log}_{{x}^{\mathrm{2}} +\mathrm{2}} \:\left({x}^{\mathrm{2}}…
Question Number 36676 by tawa tawa last updated on 04/Jun/18 $$\mathrm{if}\:\:\mathrm{z}\:=\:−\:\mathrm{27},\:\:\mathrm{find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{root}\:\mathrm{of}\:\mathrm{z}\:\mathrm{in}\:\mathrm{complex}\:\mathrm{plain} \\ $$ Commented by abdo mathsup 649 cc last updated on 04/Jun/18 $${the}\:{roots}\:{are}?{the}\:{comlex}\:{z}\:/\:{z}^{\mathrm{2}} \:=−\mathrm{27}\:=\left({i}\sqrt{\mathrm{27}}\right)^{\mathrm{2}}…