Question Number 36115 by Tinkutara last updated on 29/May/18 Commented by Tinkutara last updated on 13/Jun/18 please help Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 36110 by Riazahmedzaib11 last updated on 29/May/18 $$\left\{\Delta\mathrm{1}\:\mathrm{3}\:\mathrm{6}\:/\:×<\lceil+\mathrm{2}/\right. \\ $$$$\mathrm{47} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 167165 by mathlove last updated on 08/Mar/22 Answered by MJS_new last updated on 08/Mar/22 $$\mathrm{no}\:\mathrm{solution}\:\mathrm{for}\:{x},\:{y}\:\in\mathbb{Z} \\ $$$$\mathrm{1}\:\mathrm{solution}\:\mathrm{for}\:{x},\:{y}\:\in\mathbb{Q} \\ $$$$\mathrm{4}\:\mathrm{solutions}\:\mathrm{for}\:{x},\:{y}\:\in\mathbb{R} \\ $$ Terms of…
Question Number 101607 by mahdi last updated on 03/Jul/20 $$\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{2x}+\mathrm{7}}+\mathrm{log}_{\mathrm{3}} \mathrm{x} \\ $$$$\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right)=?\:\:\:\:\:\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167137 by mr W last updated on 07/Mar/22 Answered by som(math1967) last updated on 07/Mar/22 $$\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}\:+\frac{\mathrm{1}}{{c}}=\frac{\mathrm{1}}{{a}+{b}+{c}}\:\:\left[\because\:{a}+{b}+{c}=\mathrm{2022}\right] \\ $$$$\left({a}+{b}+{c}\right)\left({ab}+{bc}+{ca}\right)−{abc}=\mathrm{0} \\ $$$$\left({a}+{b}\right)\left({b}+{c}\right)\left({c}+{a}\right)=\mathrm{0} \\ $$$${if}\:{a}+{b}=\mathrm{0} \\…
Question Number 167119 by mathlove last updated on 07/Mar/22 $$\left({z}+\mathrm{3}{i}\right)^{\mathrm{20}} =? \\ $$ Answered by mr W last updated on 07/Mar/22 $${z}={a}+{bi} \\ $$$$\left({z}+\mathrm{3}{i}\right)^{\mathrm{20}} \\…
Question Number 101568 by Quvonchbek last updated on 03/Jul/20 Answered by mr W last updated on 03/Jul/20 $${x}^{\mathrm{25}} ×\frac{\left(\mathrm{1}+\mathrm{3}\right)\left(\mathrm{1}+\mathrm{3}^{\mathrm{2}} \right)…\left(\mathrm{1}+\mathrm{3}^{\mathrm{25}} \right)}{\mathrm{3}^{\mathrm{1}+\mathrm{2}+…+\mathrm{25}} }=\mathrm{1} \\ $$$${x}^{\mathrm{25}} ×\frac{\left(\mathrm{1}+\mathrm{3}\right)\left(\mathrm{1}+\mathrm{3}^{\mathrm{2}}…
Question Number 167107 by mathlove last updated on 06/Mar/22 Answered by alephzero last updated on 06/Mar/22 $${a}^{{b}^{{x}} } \:=\:{a}^{\sqrt[{\mathrm{3}}]{\frac{{b}}{{b}^{{x}} }}} \\ $$$$\Rightarrow\:{b}^{{x}} \:=\:\sqrt[{\mathrm{3}}]{\frac{{b}}{{b}^{{x}} }} \\…
Question Number 101563 by harckinwunmy last updated on 03/Jul/20 Answered by bramlex last updated on 03/Jul/20 $$\left(\mathrm{2}\right)\:\frac{\mathrm{1}}{\mathrm{y}+\mathrm{z}}\:,\:\frac{\mathrm{1}}{\mathrm{z}+\mathrm{x}}\:,\:\frac{\mathrm{1}}{\mathrm{x}+\mathrm{y}}\:\rightarrow\mathrm{AP} \\ $$$$\Rightarrow\frac{\mathrm{2}}{\mathrm{z}+\mathrm{x}}\:=\:\frac{\mathrm{1}}{\mathrm{y}+\mathrm{z}}\:+\:\frac{\mathrm{1}}{\mathrm{x}+\mathrm{y}} \\ $$$$\frac{\mathrm{2}}{\mathrm{z}+\mathrm{x}}\:=\:\frac{\mathrm{x}+\mathrm{2y}+\mathrm{z}}{\left(\mathrm{y}+\mathrm{z}\right)\left(\mathrm{x}+\mathrm{y}\right)} \\ $$$$\mathrm{2}\left(\mathrm{y}^{\mathrm{2}} +\mathrm{yx}+\mathrm{zx}+\mathrm{zy}\right)=\left(\mathrm{z}+\mathrm{x}\right)\left(\mathrm{x}+\mathrm{2y}+\mathrm{z}\right) \\…
Question Number 167098 by mr W last updated on 06/Mar/22 $${find}\:{the}\:{maximum}\:{of} \\ $$$${f}\left({x}\right)=\mathrm{sin}\:{x}+\mathrm{cos}\:{x}+\mathrm{sin}\:{x}\:\mathrm{cos}\:{x} \\ $$ Answered by cortano1 last updated on 06/Mar/22 $$\:\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\:=\:\sqrt{\mathrm{1}+\mathrm{sin}\:\mathrm{2x}} \\ $$$$\:\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{1}+\mathrm{sin}\:\mathrm{2x}}\:+\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin}\:\mathrm{2x}…