Question Number 166596 by Tawa11 last updated on 22/Feb/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 101052 by 1549442205 last updated on 30/Jun/20 $$\mathrm{Given}\:\mathrm{a}=\:^{\mathrm{3}} \sqrt{\mathrm{7}+\sqrt{\mathrm{50}}},\mathrm{b}=\:^{\mathrm{3}} \sqrt{\mathrm{7}−\sqrt{\mathrm{50}}}.\mathrm{Prove} \\ $$$$\mathrm{that}\:\mathrm{a}^{\mathrm{7}} +\mathrm{b}^{\mathrm{7}} \mathrm{is}\:\mathrm{an}\:\mathrm{even}\:\mathrm{number}. \\ $$ Answered by MJS last updated on 30/Jun/20…
Question Number 35481 by JOHNMASANJA last updated on 19/May/18 $${if}\:{x}^{{p}} {y}^{{p}} =\left({x}\:+\:{y}\right)\:^{{p}\:+{q}} \:\:\: \\ $$$${prove}\:{that}\:\frac{{dy}}{{dx}}=\frac{{y}}{{x}} \\ $$ Commented by math1967 last updated on 19/May/18 $${plz}\:{check}\:{x}^{{p}}…
Question Number 35475 by Apostle last updated on 19/May/18 $${Is}\:{Rational}\:{Number}\:{Countable}? \\ $$$${If}\:{yes}\:{how}\:{do}\:{we}\:{count}\:{it}\:{with}\:{one}\:{to}\:{one}\:{correspondence}\:{with}\:{set}\:{of}\:{natural}\:{number}\:\mathbb{N}? \\ $$ Answered by MJS last updated on 19/May/18 Terms of Service Privacy…
Question Number 166526 by mathlove last updated on 21/Feb/22 Answered by MJS_new last updated on 21/Feb/22 $$\Rightarrow \\ $$$${x}^{\mathrm{4}} +\frac{\mathrm{7}}{\mathrm{2}}{x}^{\mathrm{3}} +\frac{\mathrm{9}}{\mathrm{2}}{x}^{\mathrm{2}} +\frac{\mathrm{7}}{\mathrm{2}}{x}−\frac{\mathrm{5}}{\mathrm{2}}=\mathrm{0} \\ $$$$\left({x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{1}\right)\left({x}^{\mathrm{2}}…
Question Number 100976 by M±th+et+s last updated on 29/Jun/20 $${find}\:{all}\:{possible}\:{values}\:{of}\:{x},{y},{z}\:{in}\:{terms} \\ $$$${of}\:{a},{b},{c}\:{gor}\:{a}\:{triplet}\:\left({x},{y},{z}\right)\:{that}\:{satisfy} \\ $$$$ \\ $$$${x}+\frac{\mathrm{1}}{{y}}={a} \\ $$$$ \\ $$$${y}+\frac{\mathrm{1}}{{z}}={b} \\ $$$$ \\ $$$${z}+\frac{\mathrm{1}}{{x}}={c} \\…
Question Number 166496 by HongKing last updated on 21/Feb/22 $$\mathrm{Calculas}: \\ $$$$\frac{\mathrm{2}\:\sqrt{\mathrm{6}}}{\:\sqrt{\mathrm{5}}\:+\:\sqrt{\mathrm{3}}\:+\:\sqrt{\mathrm{2}}}\:-\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}\:-\:\sqrt{\mathrm{2}}}\:=\:? \\ $$ Commented by cortano1 last updated on 21/Feb/22 $$\:\frac{\mathrm{2}\sqrt{\mathrm{6}}}{\:\sqrt{\mathrm{5}}+\left(\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}\right)}×\frac{\sqrt{\mathrm{5}}−\left(\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}\right)}{\:\sqrt{\mathrm{5}}−\left(\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}\right)} \\ $$$$=\:\frac{\mathrm{2}\sqrt{\mathrm{6}}\left(\sqrt{\mathrm{5}}−\sqrt{\mathrm{3}}−\sqrt{\mathrm{2}}\right)}{\mathrm{5}−\left(\mathrm{5}+\mathrm{2}\sqrt{\mathrm{6}}\right)}=−\sqrt{\mathrm{5}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}} \\…
Question Number 100960 by john santu last updated on 29/Jun/20 $$\begin{cases}{\sqrt{{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{9}}\:=\:\mathrm{3}−{x}}\\{\sqrt{{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{9}}\:=\:{x}+\mathrm{3}}\end{cases}\: \\ $$ Commented by bobhans last updated on 29/Jun/20 $$\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{6x}+\mathrm{9}}\:=\:\mid\mathrm{x}−\mathrm{3}\mid\:=\:\mathrm{3}−\mathrm{x}\:\rightarrow\:\mathrm{x}\:\leqslant\:\mathrm{3} \\…
Question Number 100954 by bobhans last updated on 29/Jun/20 $$\begin{cases}{\frac{\mathrm{1}}{\mathrm{2}{x}−{y}}\:+\:\sqrt{{y}}\:=\:\mathrm{1}}\\{\frac{\sqrt{{y}}}{\mathrm{2}{x}−{y}}\:=\:−\mathrm{6}}\end{cases} \\ $$ Commented by Dwaipayan Shikari last updated on 29/Jun/20 $$\:\:\:\:\:\:\:\:\:\frac{−\mathrm{6}}{\:\sqrt{{y}}}=\frac{\mathrm{1}}{\mathrm{2}{x}−{y}}\:\:\:\:\:\:\rightarrow\left(\mathrm{1}\right) \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\frac{−\mathrm{6}}{\:\sqrt{{y}}}+\sqrt{{y}}=\mathrm{1}\:\:\:\:\Rightarrow{t}^{\mathrm{2}}…
Question Number 166468 by mathlove last updated on 20/Feb/22 $$\mathrm{1}+\mathrm{3}\sqrt{\mathrm{2}}{x}−\mathrm{18}{x}^{\mathrm{2}} =\mathrm{6}{x}\sqrt{\mathrm{1}−\mathrm{9}{x}^{\mathrm{2}} } \\ $$$${solve}\:\:{in}\:{R} \\ $$ Answered by MJS_new last updated on 20/Feb/22 $$\mathrm{squaring}\:\&\:\mathrm{transforming}\:\Rightarrow \\…