Question Number 166403 by mathls last updated on 19/Feb/22 $${fog}_{\left(\mathrm{3}\right)} =\mathrm{10} \\ $$$${f}\left(\mathrm{3}\right)=\mathrm{4} \\ $$$${g}\left({x}\right)=? \\ $$ Commented by mathls last updated on 19/Feb/22 $$?…
Question Number 166402 by mathls last updated on 19/Feb/22 $${f}\left({x}\right)={x}^{\mathrm{3}} +{x}^{\mathrm{2}} +\mathrm{13} \\ $$$${g}\left({x}\right)=\sqrt{\mathrm{5}} \\ $$$${gof}_{\left({x}\right)} =? \\ $$ Answered by alephzero last updated on…
Question Number 166398 by mathlove last updated on 19/Feb/22 $$\frac{\mathrm{1}}{{x}+\frac{\mathrm{1}}{{y}+\frac{\mathrm{1}}{{z}}}}=\frac{\mathrm{16}}{\mathrm{37}} \\ $$$${then}\:{faind}\:{volve}\:{of}\:\:\:\:{x}+{y}+{z}=? \\ $$ Answered by floor(10²Eta[1]) last updated on 19/Feb/22 $$\frac{\mathrm{16}}{\mathrm{37}}=\frac{\mathrm{1}}{\frac{\mathrm{37}}{\mathrm{16}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{5}}{\mathrm{16}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\frac{\mathrm{16}}{\mathrm{5}}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{5}}}} \\ $$$$\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{10} \\…
Question Number 166391 by mnjuly1970 last updated on 19/Feb/22 $$ \\ $$$$\:\:{solve}\:{in}\:\:\mathbb{R} \\ $$$$\:\:\:\sqrt{{x}.\lfloor{x}\rfloor}\:−\:\sqrt{\lfloor{x}\rfloor}\:=\:\mathrm{1} \\ $$$$\:\:−−−−−−− \\ $$ Answered by mr W last updated on…
Question Number 166372 by mathlove last updated on 19/Feb/22 Answered by MJS_new last updated on 19/Feb/22 $$\mathrm{Yes}\:\mathrm{I}\:\mathrm{can}. \\ $$ Commented by mr W last updated…
Question Number 35291 by 123 45 polytechnicien last updated on 17/May/18 $${solve}\:\:{in}\:{Z}\:\:{x}^{\mathrm{3}} +\mathrm{6}{y}^{\mathrm{3}} =\mathrm{4}{z}^{\mathrm{3}} \\ $$ Commented by 123 45 polytechnicien last updated on 17/May/18…
Question Number 100815 by john santu last updated on 28/Jun/20 Answered by mr W last updated on 28/Jun/20 $${see}\:{Q}\mathrm{47657} \\ $$$$ \\ $$$$\delta=\left(\mathrm{2}+\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(−\mathrm{2}+\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(\mathrm{2}−\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(\mathrm{2}+\mathrm{3}−\sqrt{\mathrm{7}}\right) \\ $$$$=\mathrm{108}…
Question Number 100806 by I want to learn more last updated on 28/Jun/20 Commented by I want to learn more last updated on 28/Jun/20 $$\mathrm{33}\:\:\mathrm{sir}.…
Question Number 100793 by bramlex last updated on 28/Jun/20 Commented by bobhans last updated on 28/Jun/20 $$\mathrm{The}\:\mathrm{perimeter}\:\mathrm{of}\:\mathrm{isosceles}\:\Delta\mathrm{MBC}\:=\:\mathrm{5}+\mathrm{5}+\mathrm{6}\:=\:\mathrm{16}\: \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 100792 by bramlex last updated on 28/Jun/20 Answered by bobhans last updated on 28/Jun/20 $$\frac{{x}+{xy}}{{y}}\:=\:\frac{{y}+{xy}}{{x}}\:\Rightarrow\:{x}^{\mathrm{2}} +{x}^{\mathrm{2}} {y}\:=\:{y}^{\mathrm{2}} +{xy}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} −{y}^{\mathrm{2}} \:=\:{xy}^{\mathrm{2}} −{x}^{\mathrm{2}}…