Question Number 34680 by math khazana by abdo last updated on 09/May/18 $${decompose}\:{inside}\:{C}\left({x}\right)\:{the}\:{fraction} \\ $$$${F}\left({x}\right)\:=\:\:\:\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{2}} {cos}\left(\mathrm{2}{a}\right)\:+\mathrm{1}}\:. \\ $$ Terms of Service Privacy Policy…
Question Number 165751 by cortano1 last updated on 07/Feb/22 $$\:\mathrm{x}^{\mathrm{3}} +\mathrm{6x}−\mathrm{9}=\mathrm{0}\:\Rightarrow\mathrm{x}=? \\ $$ Answered by MJS_new last updated on 08/Feb/22 $${x}_{\mathrm{1}} =\sqrt[{\mathrm{3}}]{\frac{\mathrm{9}+\sqrt{\mathrm{113}}}{\mathrm{2}}}−\sqrt[{\mathrm{3}}]{\frac{−\mathrm{9}+\sqrt{\mathrm{113}}}{\mathrm{2}}}\approx\mathrm{1}.\mathrm{20695981419} \\ $$$${x}_{\mathrm{2}} =\omega\sqrt[{\mathrm{3}}]{\frac{\mathrm{9}+\sqrt{\mathrm{113}}}{\mathrm{2}}}−\omega^{\mathrm{2}}…
Question Number 165744 by mnjuly1970 last updated on 07/Feb/22 Answered by TheSupreme last updated on 07/Feb/22 $$\lfloor{x}\rfloor−\lfloor{x}^{\mathrm{2}} \rfloor\geqslant\mathrm{0} \\ $$$$\lfloor{x}^{\mathrm{2}} \rfloor=\lfloor\left(\lfloor{x}\rfloor+\left\{{x}\right\}\right)^{\mathrm{2}} \rfloor= \\ $$$$\lfloor\lfloor{x}\rfloor^{\mathrm{2}} +\mathrm{2}\lfloor{x}\rfloor\left\{{x}\right\}+\left\{{x}\right\}^{\mathrm{2}}…
Question Number 34673 by math khazana by abdo last updated on 09/May/18 $${solve}\:\left(\frac{\mathrm{1}+{iz}}{\mathrm{1}−{iz}}\right)^{{n}} \:=\:\frac{\mathrm{1}+{itan}\alpha}{\mathrm{1}−{itan}\alpha}\:\:{with}\:−\frac{\pi}{\mathrm{2}}<\alpha<\frac{\pi}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 34669 by math khazana by abdo last updated on 09/May/18 $${let}\:{P}\left({x}\right)=\left(\mathrm{1}+{x}+{ix}^{\mathrm{2}} \right)^{{n}} \:−\left(\mathrm{1}+{x}\:−{ix}^{\mathrm{2}} \right)^{{n}} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{roots}\:{of}\:{P}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{factorize}\:{inside}\:{C}\left[{x}\right]\:{P}\left({x}\right) \\ $$$$\left.\mathrm{3}\right)\:{factorize}\:{indide}\:{R}\left[{x}\right]\:{P}\left({x}\right). \\ $$ Commented…
Question Number 34668 by math khazana by abdo last updated on 09/May/18 $${find}\:{the}\:{roots}\:{of}?{p}\left({x}\right)\:=\:{x}^{\mathrm{2}{n}} \:−\mathrm{2}{x}^{{n}} \:{cos}\left({n}\theta\right)\:+\mathrm{1} \\ $$$$\left.\mathrm{2}\right)?{factorize}\:{p}\left({x}\right)\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 34667 by math khazana by abdo last updated on 09/May/18 $${solve}\:\:\left({x}+\mathrm{1}\right)^{{n}} \:=\:{e}^{\mathrm{2}{ina}} \:\:\:{then}\:{find}\:{the}\:{value}\:{of} \\ $$$${P}_{{n}} =\:\prod_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{sin}\left({a}\:+\frac{{k}\pi}{{n}}\right) \\ $$ Terms of Service…
Question Number 100198 by I want to learn more last updated on 25/Jun/20 Commented by Dwaipayan Shikari last updated on 25/Jun/20 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{172}° \\ $$$$\mathrm{m}+\mathrm{n}=\mathrm{172}° \\…
Question Number 100193 by bobhans last updated on 25/Jun/20 $$\sqrt{\mathrm{7}+\mathrm{2}\sqrt{\mathrm{7}−\mathrm{2}\sqrt{\mathrm{7}+\mathrm{2}\sqrt{\mathrm{7}−\mathrm{2}\sqrt{\mathrm{7}+…}}}}}\:? \\ $$ Commented by bobhans last updated on 25/Jun/20 $${x}\:=\sqrt{\mathrm{7}+\mathrm{2}{y}}\:;\:\mathrm{y}=\sqrt{\mathrm{7}−\mathrm{2}{x}} \\ $$$$\Leftrightarrow{x}^{\mathrm{2}} \:=\:\mathrm{7}+\mathrm{2}{y}\:\_\left(\mathrm{1}\right) \\ $$$$\Leftrightarrow\mathrm{y}^{\mathrm{2}}…
Question Number 34653 by rick97799779 last updated on 09/May/18 Terms of Service Privacy Policy Contact: info@tinkutara.com