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Category: Algebra

Question-99796

Question Number 99796 by harckinwunmy last updated on 23/Jun/20 Answered by 1549442205 last updated on 30/Jun/20 $$\mathrm{Our}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{the} \\ $$$$\mathrm{system}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equations}:\begin{cases}{\mathrm{y}^{\mathrm{2}} =\mathrm{4}^{\mathrm{x}} \:\left(\mathrm{1}\right)}\\{\mathrm{y}^{\mathrm{x}} =\mathrm{16}\:\left(\mathrm{2}\right)}\end{cases}\:\left(\ast\right) \\ $$$$\left(\mathrm{1}\right)\Leftrightarrow\mathrm{y}^{\mathrm{2}} =\left(\mathrm{2}^{\mathrm{x}}…

6-6-6-6-6-2-6-6-6-3-6-6-6-1000-6-

Question Number 165309 by cortano1 last updated on 29/Jan/22 $$\:\frac{\mathrm{6}}{\mathrm{6}+\sqrt{\mathrm{6}}}\:+\:\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{2}} +\sqrt{\mathrm{6}}}\:+\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{3}} +\sqrt{\mathrm{6}}}\:+…+\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{1000}} +\sqrt{\mathrm{6}}}\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-165291

Question Number 165291 by HongKing last updated on 28/Jan/22 Answered by mahdipoor last updated on 29/Jan/22 $$\frac{{sin}\rho+{cos}\varphi}{{sin}\varphi+{cos}\rho}=\frac{{sin}\rho+{cos}\left(\mathrm{90}−\left(\theta+\rho\right)\right)}{{sin}\left(\mathrm{90}−\left(\theta+\rho\right)\right)+{cos}\rho}= \\ $$$$\frac{{sin}\rho+{sin}\left(\theta+\rho\right)}{{cos}\left(\theta+\rho\right)+{cos}\rho}=\frac{\mathrm{2}{sin}\left(\rho+\frac{\theta}{\mathrm{2}}\right){cos}\left(\frac{\theta}{\mathrm{2}}\right)}{\mathrm{2}{cos}\left(\rho+\frac{\theta}{\mathrm{2}}\right){cos}\left(\frac{\theta}{\mathrm{2}}\right)}= \\ $$$${tan}\left(\rho+\frac{\theta}{\mathrm{2}}\right)={k} \\ $$ Commented by…