Question Number 99744 by Rio Michael last updated on 23/Jun/20 $$\mathrm{A}\:\mathrm{wire}\:\mathrm{that}\:\mathrm{is}\:\mathrm{highly}\:\mathrm{insulated}\:\mathrm{has}\:\mathrm{a}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{2}.\mathrm{1}\:\mathrm{mm}\:\mathrm{and}\:\mathrm{a}\:\mathrm{current} \\ $$$$\mathrm{of}\:\mathrm{6}\:\mathrm{Agoes}\:\mathrm{through}\:\mathrm{it}.\:\mathrm{The}\:\mathrm{material}\:\mathrm{used}\:\mathrm{in}\:\mathrm{insulation}\:\mathrm{has}\:\mathrm{thickness} \\ $$$$\mathrm{of}\:\mathrm{2}.\mathrm{1}\:\mathrm{mm}\:\mathrm{with}\:\mathrm{a}\:\mathrm{thermal}\:\mathrm{conductivity}\:\mathrm{of}\:\mathrm{0}.\mathrm{2}\:\mathrm{W}/\mathrm{Km}.\:\mathrm{the}\:\mathrm{material}\:\mathrm{used} \\ $$$$\mathrm{in}\:\mathrm{constructing}\:\mathrm{the}\:\mathrm{wire}\:\mathrm{has}\:\mathrm{a}\:\mathrm{resistivity}\:\mathrm{of}\:\mathrm{4}.\mathrm{2}\:×\:\mathrm{10}^{−\mathrm{7}} \Omega\mathrm{m}.\:\mathrm{assume}\:\mathrm{the}\: \\ $$$$\mathrm{the}\:\mathrm{materials}\:\mathrm{reach}\:\mathrm{steady}\:\mathrm{state}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{difference}\:\mathrm{in}\:\mathrm{temperature} \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{outer}\:\mathrm{suface}\:\mathrm{and}\:\mathrm{inner}\:\mathrm{surface}. \\ $$ Answered…
Question Number 99737 by bemath last updated on 23/Jun/20 $$\frac{\mathrm{3}−\mathrm{9x}^{\mathrm{2}} }{\mathrm{5}−\mathrm{25x}^{\mathrm{2}} }\:=\:\frac{\mathrm{5}−\mathrm{125x}^{\mathrm{3}} }{\mathrm{1}−\mathrm{x}^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 34182 by NECx last updated on 02/May/18 $${resolve}\:\frac{{x}^{\mathrm{3}} }{{x}^{\mathrm{6}} −\mathrm{1}}\:{into}\:{partial}\:{fraction} \\ $$ Answered by math1967 last updated on 02/May/18 $$\frac{\mathrm{1}}{\mathrm{2}}\left\{\frac{\mathrm{1}}{{x}^{\mathrm{3}} +\mathrm{1}}\:+\frac{\mathrm{1}}{{x}^{\mathrm{3}} −\mathrm{1}}\right\} \\…
Question Number 165243 by Zaynal last updated on 28/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\lfloor\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{{x}}???\rfloor \\ $$$$\:\:\:\lfloor\mathrm{5}\boldsymbol{{x}}\:+\:\frac{\mathrm{5}\boldsymbol{{x}}}{\left(\mathrm{5}\:+\:\mathrm{5}\right)^{\mathrm{5}} }\:×\:\left(−\mathrm{5}\boldsymbol{{x}}\right)\:\boldsymbol{\div}\:\mathrm{555}\boldsymbol{{x}}\:−\mathrm{55}\boldsymbol{{x}}\:×\frac{\mathrm{5}\boldsymbol{\div}\mathrm{5}}{\mathrm{5}}\:\:+\:\boldsymbol{{x}}\:=\:\mathrm{555555555555555}\rfloor \\ $$$$\:^{\mathrm{proof}:\mathrm{z}.\mathrm{a}} \\ $$ Answered by alephzero last updated on 28/Jan/22 $$\mathrm{5}{x}+\frac{\mathrm{5}{x}}{\left(\mathrm{5}+\mathrm{5}\right)^{\mathrm{5}}…
Question Number 99698 by Quvonchbek last updated on 22/Jun/20 Commented by Quvonchbek last updated on 22/Jun/20 $$\mathrm{please}\:\:\: \\ $$ Commented by Quvonchbek last updated on…
Question Number 165226 by Neils last updated on 27/Jan/22 $${make}\:{x}\:{the}\:{subject}\:{of}\:{the}\:{formula}; \\ $$$${a}^{{x}} +{bx}+{c}=\mathrm{0} \\ $$ Answered by mr W last updated on 28/Jan/22 $${a}^{{x}} =−\left({bx}+{c}\right)…
Question Number 165215 by HongKing last updated on 27/Jan/22 $$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\:\mathrm{tan}^{−\mathrm{1}} \:\left(\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{2}} }\right) \\ $$ Answered by mindispower last updated on 27/Jan/22 $${S}=\Sigma\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{{n}^{\mathrm{2}}…
Question Number 165209 by HongKing last updated on 27/Jan/22 $$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{n}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{k}}} {\sum}}\:\frac{\mathrm{n}^{\mathrm{2}} \:\mathrm{sin}^{\mathrm{2}} \:\frac{\mathrm{n}\pi}{\mathrm{2}}}{\mathrm{n}^{\mathrm{4}} \:\pi^{\mathrm{4}} \:+\:\mathrm{n}^{\mathrm{2}} \:\pi^{\mathrm{2}} \:\mathrm{a}\:+\:\mathrm{b}}\:=\:? \\ $$ Terms of Service Privacy Policy…
Question Number 34139 by NECx last updated on 01/May/18 $${What}\:{is}\:{the}\:{remainder}\:{when} \\ $$$$\mathrm{17}^{\mathrm{200}} \:{is}\:{divided}\:{by}\:\mathrm{18} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 01/May/18 $${letn}=\mathrm{200} \\ $$$${so}\:{problem}\:{is}\:\left(\mathrm{18}−\mathrm{1}\right)^{{n}}…
Question Number 99655 by bemath last updated on 22/Jun/20 Commented by bramlex last updated on 22/Jun/20 $${approximation}\:{x}=\mathrm{7}.\mathrm{464} \\ $$$$\Leftrightarrow\:{x}−\mathrm{2}\sqrt{{x}}\:=\:\mathrm{7}.\mathrm{464}−\mathrm{2}\sqrt{\mathrm{7}.\mathrm{464}}\:\approx\:\mathrm{1}.\mathrm{9999355}…\: \\ $$ Answered by Farruxjano last…