Question Number 34020 by prof Abdo imad last updated on 29/Apr/18 $${let}\:{p}\left({x}\right)={cos}\left(\mathrm{2}{n}\:{arccos}\left({x}\right)\right)\:\:{with}\:{x}\in\left[−\mathrm{1},\mathrm{1}\right] \\ $$$${find}\:{the}\:{roots}\:{of}\:{p}\left({x}\right)\:{and}\:{factorize}\:\:{p}\left({x}\right) \\ $$ Commented by math khazana by abdo last updated on…
Question Number 34019 by prof Abdo imad last updated on 29/Apr/18 $${n}\:{integr}\:{decompose}\:{imsidr}\:{R}\left[{x}\right]\:{the}\:{fraction} \\ $$$${F}\left({x}\right)\:=\:\:\:\frac{\mathrm{1}}{\left({x}^{\mathrm{2}} \:−\mathrm{1}\right)^{{n}} } \\ $$ Commented by abdo mathsup 649 cc last…
Question Number 165060 by mathlove last updated on 25/Jan/22 $${x}−\frac{\mathrm{1}}{{x}}=\mathrm{4}\:\:{then}\:{x}^{\mathrm{2}} −\frac{\mathrm{1}}{{x}^{\mathrm{2}} }=? \\ $$ Answered by TheSupreme last updated on 25/Jan/22 $${x}^{\mathrm{2}} +\frac{\mathrm{1}}{{x}^{\mathrm{2}} }=\mathrm{18} \\…
Question Number 33988 by abdo imad last updated on 28/Apr/18 $${give}\:{the}\:{algebric}\:{form}\:{of}\:\left(\mathrm{1}+{i}\right)^{{i}} . \\ $$ Answered by MJS last updated on 28/Apr/18 $$\left(\mathrm{1}+\mathrm{i}\right)^{\mathrm{i}} =\left(\sqrt{\mathrm{2}}\mathrm{e}^{\mathrm{i}\frac{\pi}{\mathrm{4}}} \right)^{\mathrm{i}} =\left(\mathrm{e}^{\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{2}}}…
Question Number 33982 by abdo imad last updated on 28/Apr/18 $${decompose}\:{inside}\:{R}\left[{x}\right]\:{the}\:{fraction} \\ $$$${F}\left({x}\right)\:=\:\frac{\mathrm{1}}{{x}^{{n}} \left({x}+\mathrm{1}\right)^{\mathrm{2}} }\:{with}\:{n}\:{integr}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165054 by mathlove last updated on 25/Jan/22 Answered by alephzero last updated on 25/Jan/22 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\left(\sqrt{\mathrm{sin}\:\frac{\pi}{{x}}}\::\:\mathrm{cos}\:\frac{\pi}{{x}+\mathrm{2}}\right)^{\frac{\mathrm{1}}{{x}}} \:= \\ $$$$=\:\sqrt{\sqrt{\mathrm{sin}\:\frac{\pi}{\mathrm{2}}}\::\:\mathrm{cos}\:\frac{\pi}{\mathrm{4}}}\:= \\ $$$$=\:\sqrt{\mathrm{1}\::\:\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}}\:=\:\sqrt{\frac{\mathrm{2}}{\:\sqrt{\mathrm{2}}}}\:=\:\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\sqrt{\mathrm{2}}}}\:=\:\frac{\sqrt{\mathrm{2}}}{\:\sqrt[{\mathrm{4}}]{\mathrm{2}}}\:=\: \\ $$$$=\:\frac{\sqrt{\mathrm{2}}\sqrt[{\mathrm{4}}]{\mathrm{2}^{\mathrm{3}}…
Question Number 165044 by alephzero last updated on 25/Jan/22 $$\mathrm{If}\:{n}\:=\:{j}\:+\:{k},\:\mathrm{prove}\:\mathrm{or}\:\mathrm{disprove} \\ $$$$\frac{{d}^{{n}} }{{dx}^{{n}} }{f}\left({x}\right)\:=\:\frac{{d}^{{j}} }{{dx}^{{j}} }\left(\frac{{d}^{{k}} }{{dx}^{{k}} }{f}\left({x}\right)\right)\:=\:\frac{{d}^{{k}} }{{dx}^{{k}} }\left(\frac{{d}^{{j}} }{{dx}^{{j}} }{f}\left({x}\right)\right) \\ $$ Commented…
Question Number 165021 by mathlove last updated on 25/Jan/22 $${fog}=\mathrm{6}{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{3} \\ $$$${gof}=\mathrm{12}{x}^{\mathrm{2}} −\mathrm{14}{x}+\mathrm{6} \\ $$$${f}\left(\mathrm{2}\right)=? \\ $$ Answered by mr W last updated on…
Question Number 99486 by shaxzod last updated on 21/Jun/20 $$\int\sqrt{{sinx}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165006 by NUR23 last updated on 24/Jan/22 Commented by NUR23 last updated on 24/Jan/22 $${Help} \\ $$$$ \\ $$ Terms of Service Privacy…